一对多，多对多
一对多，多对多
提问于 2014-03-10 11:10:31
$trell = Trell::find($trell_id);
$builder = $trell->builders();
$codes = $builder->codes(); //Undefined method codes...所以我得到了关于代码的未定义方法，我的关系如下所示:为什么它不能工作？
Trell在模型中有一个定义：
public function builders() {
return $this->hasOne('Appsales\\Models\\Builders');
}建造商的代码定义如下：
public function codes() {
return $this->hasMany('Appsales\\Models\\Codes');
}守则包括：
public function builders() {
return $this->belongsTo('Appsales\\Models\\Builders');
}
$trell->with('builders.codes')->get()->toArray(); works, but I only want "one codes" with some filtering (where in the sql) that is.Stack Overflow用户
回答已采纳
发布于 2014-03-10 11:40:37
它不起作用，因为对关系函数的调用不是返回模型，而是返回关系。
<?php
$trell = Trell::find($trell_id);
$builder = $trell->builders();
/**
* $builder is now of type \Illuminate\Database\Eloquent\Relations\HasOne
* which does not have a method codes()
* But you don't want the relationship, you want the property as a Model.
* So you call it as property and not as a function
*/
$builderModel = $trell->builders;
$codes = $builderModel->codes;
/**
* Now $codes contains all codes as collection of models. If you want to
* filter them, you get it as Relationship / Query object and use the
* regular query builder functions:
*/
$codes = $builderModels->codes()->where('key', $value)->get();您甚至可以从Trell模型加载所有内容：
$trells = Trell::with([
'builders.codes' => function($query) {
$query->where('key1', $value1);
},
])->get();页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/22298530
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