Python Sudoku Checker 9X9
Python Sudoku Checker 9X9
提问于 2014-03-12 18:17:38
while True:
try:
file = input("Enter a filename: ")
fi = open(file, "r")
infile = fi.read()
grid = [list (i) for i in infile.split()] #Puts the sudoku puzzle into a list in order to check that the total number is valid
check = len(grid)
print("The total number in this puzzle is:",check) #Counts the amount of numbers in the sudoku puzzle
break
except FileNotFoundError:
print ("The inputted file does not exist")
def check(infile):
count = 0
for j in range (0,9):
for n in range(0,9):
if infile[j].count(infile[j][n]) <= 1:
count = count + 0
else:
count = count + 1
cols = [[row[i] for row in infile] for i in[0,1,2,3,4,5,6,7,8]]
leg = 0
for i in range(0,9):
for j in range(0,9):
if cols[i].count(cols[i][j]) <= 1:
leg = leg + 0
else:
leg = leg + 1
angel = []
for t in range(3):
ang = infile[t]
for u in range(3):
angel.append(ang[u])
foot = 0
for be in range(9):
if angel.count(angel[be]) <= 1:
foot = foot + 0
else:
foot = foot + 1
if count + leg + foot == 0:
print("Valid")
else:
print ("Invalid")
def inputs():
x = raw_input()
ls = []
while x != '':
x1 =x.split(' ')
ls.append(x1)
if len(infile) >=9:
print (check(infile))
infile = []
x = raw_input()
inputs() 实际错误：
Traceback (most recent call last):
File "E:/Computer Programming/Assignment/check 2.py", line 22, in <module>
cols = [[row[i] for row in infile] for i in[0,1,2,3,4,5,6,7,8]]
File "E:/Computer Programming/Assignment/check 2.py", line 22, in <listcomp>
cols = [[row[i] for row in infile] for i in[0,1,2,3,4,5,6,7,8]]
File "E:/Computer Programming/Assignment/check 2.py", line 22, in <listcomp>
cols = [[row[i] for row in infile] for i in[0,1,2,3,4,5,6,7,8]]
IndexError: string index out of range为什么它给出了一个输出，说明我的字符串索引超出了范围，还有另一种方法来创建sudoku 9x9检查器来检查是否有任何重复出现的数字。我需要确保每列中都有9个数字，它们位于数字1和9之间。
回答 1
Stack Overflow用户
发布于 2014-03-12 18:31:44
首先，有几点评论：
从不做：
cols = [[row[i] for row in infile] for i in[0,1,2,3,4,5,6,7,8]]但要做到：
cols = [[row[i] for row in infile] for i in range(0,9)]- 永远不要调用变量的名称与您在代码
check和check()中定义的函数相同 - 不要在模块级别编写代码，而是将所有内容嵌入函数中，并在
if __name__ == "__main__"条件之后调用文件末尾的入口点函数(因此，如果您想在另一个模块中导入模块，则不执行模块级代码)。 - 不要打开文件而不关闭它们，而是使用上下文管理器：
with open('myfile', 'r') as f: ... - 您的代码具有对
while的无用使用..。或者至少是一个错误的用途(你真的是想在异常上永远循环吗？)使用命令行参数，这将使shell帮助用户选择一个实际存在的文件。
现在我已经说得很清楚了，关于你的实际问题：
infile是一个文件对象(如果我能正确地读取您的错误缩进的python代码)，因此infile的每一行(这里称为row )都只是一个字符串。
因此，如果您有一个空行或小于9列的行，则很可能会使row[i]脱离边界。
这里是重构您的代码的一个步骤，尽管我已经留下了一些错误的设计：
def check(infile):
count = 0
for j in range (0,9):
for n in range(0,9):
if infile[j].count(infile[j][n]) <= 1:
count = count + 0
else:
count = count + 1
def inputs():
x = raw_input()
ls = []
while x != '':
x1 =x.split(' ')
ls.append(x1)
if len(infile) >=9:
print (check(infile))
infile = []
x = raw_input()
def check_grid():
cols = [[row[i] for row in infile] for i in range(0,9)]
leg = 0
for i in range(0,9):
for j in range(0,9):
if cols[i].count(cols[i][j]) <= 1:
leg = leg + 0
else:
leg = leg + 1
angel = []
for t in range(3):
ang = infile[t]
for u in range(3):
angel.append(ang[u])
foot = 0
for be in range(9):
if angel.count(angel[be]) <= 1:
foot = foot + 0
else:
foot = foot + 1
if count + leg + foot == 0:
print("Valid")
else:
print ("Invalid")
inputs()
def sudoku_checker():
try:
file = input("Enter a filename: ")
fi = open(file, "r")
infile = fi.read()
grid = [list (i) for i in infile.split()] #Puts the sudoku puzzle into a list in order to check that the total number is valid
# Counts the amount of numbers in the sudoku puzzle
print("The total number in this puzzle is:",len(grid))
check_grid()
except FileNotFoundError:
print ("The inputted file does not exist")
if __name__ == "__main__":
sudoku_checker()页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/22360418
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