blocks|key|2329301|text|尝试：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2329302|SELECT+sender.name+as+Sender,+receiver.name+as+Receiver,+shipment.id,+ports.name+AS+Port+
FROM+sender,receiver,shipment,ports+
WHERE+shipment.sender_ID=sender.ID+AND+shipment.receiver_ID=receiver.ID+AND+ports.ID+=+shipment.From_Port_ID+|code-block|syntax|javascript|2329303|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try:

<pre><code>SELECT sender.name as Sender, receiver.name as Receiver, shipment.id, ports.name AS Port 
FROM sender,receiver,shipment,ports 
WHERE shipment.sender_ID=sender.ID AND shipment.receiver_ID=receiver.ID AND ports.ID = shipment.From_Port_ID 
</code></pre>

blocks|key|2329340|text|你可以用ports连接两次|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2329341|select+sender.name+as+Sender,+receiver.name+as+Receiver,+
++++++shipment.id,+port1.name+as+OriginPort,+port2.name+as+DestinationPort
from+sender,receiver,shipment,+ports+port1,+ports+port2+
WHERE+shipment.sender_ID=sender.ID+
++++++AND+shipment.receiver_ID=receiver.ID
++++++AND+shipment.From_Port_ID+=+port1.id
++++++AND+shipment.To_Port_ID+=+port2.id|code-block|syntax|javascript|2329342|我还建议您更改查询以使用join的显式语法(有关此的更多信息，请参见Explicit+vs+implicit+SQL+joins+)，如下所示：|2329343|select+sender.name+as+Sender,+receiver.name+as+Receiver,+
++++++shipment.id,+port1.name+as+OriginPort,+port2.name+as+DestinationPort
from+sender+JOIN+shipment+ON+sender.ID+=+shipment.sender_ID
++++++++JOIN+receiver+ON+shipment.receiver_ID=receiver.ID
++++++++JOIN+ports+port1+ON+shipment.From_Port_ID+=+port1.id
++++++++JOIN+ports+port2+ON+shipment.To_Port_ID+=+port2.id|2329344|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/44917/^0|4|5|0|0|Y|U|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@]|D|@$9|11|A|12|1|13]]|E|$]]|$1|M|3|N|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|15|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

You can do it joining twice with <code>ports</code>:

<pre><code>select sender.name as Sender, receiver.name as Receiver, 
 shipment.id, port1.name as OriginPort, port2.name as DestinationPort
from sender,receiver,shipment, ports port1, ports port2 
WHERE shipment.sender_ID=sender.ID 
 AND shipment.receiver_ID=receiver.ID
 AND shipment.From_Port_ID = port1.id
 AND shipment.To_Port_ID = port2.id
</code></pre>

I also suggest you to change your query to use the explicit syntax for join (see <a href="https://stackoverflow.com/questions/44917/">Explicit vs implicit SQL joins</a> for more information on this), as follows:

<pre><code>select sender.name as Sender, receiver.name as Receiver, 
 shipment.id, port1.name as OriginPort, port2.name as DestinationPort
from sender JOIN shipment ON sender.ID = shipment.sender_ID
 JOIN receiver ON shipment.receiver_ID=receiver.ID
 JOIN ports port1 ON shipment.From_Port_ID = port1.id
 JOIN ports port2 ON shipment.To_Port_ID = port2.id
</code></pre>

blocks|key|4796775|text|您可以使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4796776|SELECT+sender.name+as+Sender,+receiver.name+as+Receiver,+ports_a.name+as+FromPort,
ports_b.name+as+ToPort

FROM+Shipment+as+shipment

JOIN+Sender
ON+sender.ID=+shipment.sender_ID

JOIN++Receiver++as+receiver
ON+receiver.ID=+shipment.receiver_ID

JOIN+Ports+as+ports_a
on+ports_a.ID=+shipment.From_Port_ID+

JOIN+Ports+as+ports_b
on+ports_b.ID=+shipment.To_Port_ID|code-block|syntax|javascript|4796777|第一行包括SELECT，就像您所做的那样，只需将您想要获取的所有信息放入其中。|offset|length|style|CODE|4796778|第二部分是，指定从哪里获取信息。FROM将是from表，它是连接所有其他表的主表。|4796779|然后，该表将使用关键字JOIN与其他表连接。它就像有一个公共引用的连接表。此引用是Shipment表(如sender_ID+)中的sender_ID。|4796780|例如，sender_ID将与发件人表中的Sender.id匹配，如Sender.id+#5将与Shipment.sender_ID+#5连接。|4796781|entityMap^0|0|0|5|6|0|G|4|0|B|4|15|8|1G|9|1T|9|0|3|9|K|9|X|9|1B|I|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|Z|8|@$I|10|J|11|K|L]]|9|@]|A|$]]|$1|O|3|P|5|6|7|12|8|@$I|13|J|14|K|L]|$I|15|J|16|K|L]|$I|17|J|18|K|L]|$I|19|J|1A|K|L]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1B|8|@$I|1C|J|1D|K|L]|$I|1E|J|1F|K|L]|$I|1G|J|1H|K|L]|$I|1I|J|1J|K|L]]|9|@]|A|$]]|$1|S|3|-4|5|6|7|1K|8|@]|9|@]|A|$]]]|T|$]]

You can use: 

<pre><code>SELECT sender.name as Sender, receiver.name as Receiver, ports_a.name as FromPort,
ports_b.name as ToPort

FROM Shipment as shipment

JOIN Sender
ON sender.ID= shipment.sender_ID

JOIN Receiver as receiver
ON receiver.ID= shipment.receiver_ID

JOIN Ports as ports_a
on ports_a.ID= shipment.From_Port_ID 

JOIN Ports as ports_b
on ports_b.ID= shipment.To_Port_ID
</code></pre>

First line includes <code>SELECT</code>, as what you did, just put all the info you want to fetch. 

The second part is, to specify from where you want to get the info. 
<code>FROM</code> will be the from table, which is the main table that connects all other tables. 

Then that table, will be joined with other tables using the keyword <code>JOIN</code>. It's like connection table by having a common reference. This reference is the <code>ID</code> in <code>Shipment</code> table such as <code>sender_ID</code>. 

For example <code>sender_ID</code> for will be matched with <code>Sender.id</code> from Sender table as in <code>Sender.id</code> #5 will be connected with <code>Shipment.sender_ID</code> #5.

blocks|key|2329391|text|我希望这是你想要的！|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2329392|select+
+S.name+as+Sender
,R.name+as+Receiver
,SH.id
,PFROM.name
,PTO.name

from+shipment+AS+SH

INNER+JOIN+PORTS+AS+PFROM+ON+PFROM.ID+=+SH.From_Port_ID
INNER+JOIN+PORTS+AS+PTO+ON+PTO.ID+=+SH.From_Port_ID
INNER+JOIN+SENDER+AS+S+ON+SH.sender_ID=S.ID+
INNER+JOIN+RECEIVER+AS+R+ON+SH.receiver_ID=R.ID+|code-block|syntax|javascript|2329393|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I HOPE IS THAT WHAT YOU WANT !!!!...

<pre><code>select 
 S.name as Sender
,R.name as Receiver
,SH.id
,PFROM.name
,PTO.name

from shipment AS SH

INNER JOIN PORTS AS PFROM ON PFROM.ID = SH.From_Port_ID
INNER JOIN PORTS AS PTO ON PTO.ID = SH.From_Port_ID
INNER JOIN SENDER AS S ON SH.sender_ID=S.ID 
INNER JOIN RECEIVER AS R ON SH.receiver_ID=R.ID 
</code></pre>

I have following tables:

<pre><code>Sender
---------
ID, name, type, mobile


Receiver
-----------
ID, name, type, mobile


Ports
-----------
ID, name, city, country


Shipment
-----------
ID, Sender_ID, Receiver_ID, From_Port_ID, To_Port_ID, Date, Status
</code></pre>

I was trying to display shipment table contents in my webpage with names instead of IDs. I can fetch sender and receiver name by the following query:

<pre><code>SELECT sender.name AS Sender, receiver.name AS Receiver, shipment.id 
FROM sender,receiver,shipment
WHERE shipment.sender_ID=sender.ID AND shipment.receiver_ID=receiver.ID
</code></pre>

How to fetch port names from ports table?

MySQL: Select Data from multiple Columns on Multiple conditions

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有以下表格：Sender---------ID, name, type, mobileReceiver-----------ID, name, type, mobilePorts-----------ID, name, city, countryShipment-----------ID, Sender_ID, Re...

问MySQL:在多个条件下从多列中选择数据
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