blocks|key|1850767|text|如果您只是在寻找一个映射您的值的函数，您所需要的只是一些简单的数学：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1850768|function+f(x)+{
++return+Math.pow(10,+Math.floor(Math.log(x)+/+Math.log(10)));
}

alert(+f(1)+);
alert(+f(23)+);
alert(+f(2)+);
alert(+f(105)+);
alert(+f(2000)+);
alert(+f(30000)+);|code-block|syntax|javascript|1850769|我对d3没有经验，所以我不能帮你。|1850770|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

If you are just looking for a function that maps your values, all you need is some simple math:

<pre><code>function f(x) {
 return Math.pow(10, Math.floor(Math.log(x) / Math.log(10)));
}

alert( f(1) );
alert( f(23) );
alert( f(2) );
alert( f(105) );
alert( f(2000) );
alert( f(30000) );
</code></pre>

I have no experience with d3 so I cannot help you there.

blocks|key|1572255|text|d3阈值标度根据所选择的阈值将量化数据集拆分为离散类别。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1572256|与简单的线性尺度不同，阈值尺度的域不是最小值和最大值。相反，阈值标度的域是要拆分数据的阈值列表。|style|BOLD|1572257|与所有d3标度一样，范围是所需的输出值。但是，对于阈值尺度，范围内的输出值必须等于阈值(域)值加上一个的数量。范围中的第一值被赋值给小于第一阈值的值，范围中的第二值被赋值给等于或大于第一阈值但小于第二阈值的值，等等，直到范围中的最后一值被赋值给等于或大于域中最后一值的值。|1572258|因此，要根据10的幂将正整数数组拆分为类别，您可以使用10的幂作为域，并使用一组字符串描述类别为您的范围。|1572259|scale+=+d3.scale.threshold()
++++++++++.domain([1,+11,+101,+1001,+10001])
++++++++++.range(["<1",+"1-10",+"11-100",+"101-1000",+"1001-10,000",+">10,001"]);|code-block|syntax|javascript|1572260|当然，根据您正在使用的比例，像@Daniele+Torino这样的自定义函数可能更通用，因为它不需要您指定在/低于/高于/低于的最大和最小阈值，因为在这个阈值之上/低于这个阈值，所有的东西都会聚集在同一个类别中。但如果这是你想要的，那么以上的阈值应该可以做到这一点。|1572261|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/mbostock/d3/wiki/Quantitative-Scales#threshold-scales^0|0|6|0|0|U|F|0|U|L|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@$A|11|B|12|1|13]]|C|$]]|$1|D|3|E|5|6|7|14|8|@$A|15|B|16|F|G]]|9|@]|C|$]]|$1|H|3|I|5|6|7|17|8|@$A|18|B|19|F|G]]|9|@]|C|$]]|$1|J|3|K|5|6|7|1A|8|@]|9|@]|C|$]]|$1|L|3|M|5|N|7|1B|8|@]|9|@]|C|$O|P]]|$1|Q|3|R|5|6|7|1C|8|@]|9|@]|C|$]]|$1|S|3|-4|5|6|7|1D|8|@]|9|@]|C|$]]]|T|$U|$5|V|W|X|C|$Y|Z]]]]

A <a href="https://github.com/mbostock/d3/wiki/Quantitative-Scales#threshold-scales" rel="nofollow">d3 Threshold Scale</a> splits a quantitive dataset into discrete categories based on threshold points that you choose.

Unlike simple linear scales, the domain of the the threshold scale is not the min and max values. Instead, the threshold scale's domain is the list of threshold values at which you want to split your data.

As with all d3 scales, the range is the desired output values. For a threshold scale, however, the number of output values in the range has to be equal to the number of threshold (domain) values plus one. The first value in the range is assigned to values that are less than the first threshold, the second value in the range is assigned to values that are equal to or greater than the first threshold but less than the second, and so on, until the last value in the range is assigned to values that are equal to or greater than the last value in the domain.

So to split an array of positive integers into categories based on powers of 10, you could use the powers of 10 as your domain, and a set of strings describing the categories as your range:

<pre><code>scale = d3.scale.threshold()
 .domain([1, 11, 101, 1001, 10001])
 .range(["&lt;1", "1-10", "11-100", "101-1000", "1001-10,000", "&gt;10,001"]);
</code></pre>

Of course, depending on what you are using the scale for, a custom function like @Daniele Torino suggested may be more versatile, since it doesn't require you to specify max and min threshold above/below which everything gets bunched in the same category. But if that is what you want, the threshold scale above should do it.

I have a very sparse dataset and I want to plot it in a histogram with a logarithmic scale. I would like the X axis to look something similar to:

[1, 10, 100, 1000, 10000]

Meaning that the first bin would include the observations with a cost of 1-10, the second 11-10 and so on, and the last would be +10.000. 

<pre><code>function (pow, min, max) {
 var range = []; 
 for (i = min; i &lt; max; i++) {
 range.push(Math.pow(pow, i));
 }
 return range;
}
</code></pre>

I am able to generate the given array of powers of 10. Now, what I would like is to map a set of continuous values to that array, meaning that:

[1, 23, 2, 105, 2000, 30000]

would be output as: 

[1, 10, 1, 100, 1000, 10000]

I have tried using d3.scale.threshold, but it does not seem to be working as expecting.

Logarithmic range

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个非常稀疏的数据集，我想用一个对数比例的直方图来绘制它。我希望X轴看起来类似于：1，10,100,1000,10000这意味着第一个垃圾桶将包括花费1-10，第二个11-10等等的观测，最后一个是+10.000。function (pow, min, max) {    var range = [];      ...

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