blocks|key|2830115|text|您可以在SUM子句中使用CASE语句的WHERE结果，如下所示：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2830116|SELECT+u.id,
++++max(t.request_at)+AS+"Date",
SUM(CASE
++++WHEN+t.view+=+1+THEN+1
++++ELSE+0+END)+AS+ONE,
SUM(CASE
++++WHEN+t.view+=+2+THEN+1
++++ELSE+0+END)+AS+TWO,
SUM(CASE
++++WHEN+t.view+=+3+THEN+1
++++ELSE+0+END)+AS+THREE
FROM+users+u
JOIN+t+ON+u.id+=+t.uid
WHERE+u.signup_city_id+=+18
AND+u.creationtime+BETWEEN+'2013-12-01'+AND+'2014-01-01'
GROUP+BY+1
HAVING+SUM(CASE
++++WHEN+t.view+=+1+THEN+1
++++ELSE+0+END)+<+3|code-block|syntax|javascript|2830117|entityMap^0|4|3|C|4|J|5|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|L|$]]

You can use the result of the <code>SUM</code> of the <code>CASE</code> statement in your <code>WHERE</code> clause like this:

<pre><code>SELECT u.id,
 max(t.request_at) AS "Date",
SUM(CASE
 WHEN t.view = 1 THEN 1
 ELSE 0 END) AS ONE,
SUM(CASE
 WHEN t.view = 2 THEN 1
 ELSE 0 END) AS TWO,
SUM(CASE
 WHEN t.view = 3 THEN 1
 ELSE 0 END) AS THREE
FROM users u
JOIN t ON u.id = t.uid
WHERE u.signup_city_id = 18
AND u.creationtime BETWEEN '2013-12-01' AND '2014-01-01'
GROUP BY 1
HAVING SUM(CASE
 WHEN t.view = 1 THEN 1
 ELSE 0 END) &lt; 3
</code></pre>

blocks|key|193487|text|您需要将其包装到派生表中：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|193488|select+*
from+(
++++SELECT+u.id,
+++++++++++max(t.request_at)+AS+"Date",
+++++++++++sum(CASE
+++++++++++++++WHEN+t.view+=+1+THEN+1
+++++++++++++++ELSE+0+END)+AS+ONE,
+++++++++++sum(CASE
+++++++++++++++WHEN+t.view+=+2+THEN+1
+++++++++++++++ELSE+0+END)+AS+TWO,
+++++++++++sum(CASE
+++++++++++++++WHEN+t.view+=+3+THEN+1
+++++++++++++++ELSE+0+END)+AS+THREE
++++FROM+users+u
++++++JOIN+t+ON+u.id+=+t.uid
++++WHERE+u.signup_city_id+=+18
++++++AND+u.creationtime+BETWEEN+'2013-12-01'+AND+'2014-01-01'
++++group+by+1
)+t
WHERE+ONE+<+3|code-block|syntax|javascript|193489|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You need to wrap it into a derived table:

<pre><code>select *
from (
 SELECT u.id,
 max(t.request_at) AS "Date",
 sum(CASE
 WHEN t.view = 1 THEN 1
 ELSE 0 END) AS ONE,
 sum(CASE
 WHEN t.view = 2 THEN 1
 ELSE 0 END) AS TWO,
 sum(CASE
 WHEN t.view = 3 THEN 1
 ELSE 0 END) AS THREE
 FROM users u
 JOIN t ON u.id = t.uid
 WHERE u.signup_city_id = 18
 AND u.creationtime BETWEEN '2013-12-01' AND '2014-01-01'
 group by 1
) t
WHERE ONE &lt; 3
</code></pre>

blocks|key|2288744|text|您可以使用having子句：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2288745|SELECT+u.id,+max(t.request_at)+AS+"Date",
+++++++sum(CASE+WHEN+t.view+=+1+THEN+1+ELSE+0+END)+AS+ONE,
+++++++sum(CASE+WHEN+t.view+=+2+THEN+1+ELSE+0+END)+AS+TWO,
+++++++sum(CASE+WHEN+t.view+=+3+THEN+1+ELSE+0+END)+AS+THREE
FROM+users+u+JOIN
+++++t
+++++ON+u.id+=+t.uid
WHERE+u.signup_city_id+=+18+AND+u.creationtime+BETWEEN+'2013-12-01'+AND+'2014-01-01'
group+by+1
HAVING+sum(CASE+WHEN+t.view+=+1+THEN+1+ELSE+0+END)+<+3;|code-block|syntax|javascript|2288746|或者使用子查询：|2288747|SELECT+t.*
FROM+(SELECT+u.id,+max(t.request_at)+AS+"Date",
+++++++++++++sum(CASE+WHEN+t.view+=+1+THEN+1+ELSE+0+END)+AS+ONE,
+++++++++++++sum(CASE+WHEN+t.view+=+2+THEN+1+ELSE+0+END)+AS+TWO,
+++++++++++++sum(CASE+WHEN+t.view+=+3+THEN+1+ELSE+0+END)+AS+THREE
++++++FROM+users+u+JOIN
+++++++++++t
+++++++++++ON+u.id+=+t.uid
++++++WHERE+u.signup_city_id+=+18+AND+u.creationtime+BETWEEN+'2013-12-01'+AND+'2014-01-01'
++++++group+by+1
+++++)+t
WHERE+ONE+<+3;|2288748|entityMap^0|5|6|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

You would use a <code>having</code> clause:

<pre><code>SELECT u.id, max(t.request_at) AS "Date",
 sum(CASE WHEN t.view = 1 THEN 1 ELSE 0 END) AS ONE,
 sum(CASE WHEN t.view = 2 THEN 1 ELSE 0 END) AS TWO,
 sum(CASE WHEN t.view = 3 THEN 1 ELSE 0 END) AS THREE
FROM users u JOIN
 t
 ON u.id = t.uid
WHERE u.signup_city_id = 18 AND u.creationtime BETWEEN '2013-12-01' AND '2014-01-01'
group by 1
HAVING sum(CASE WHEN t.view = 1 THEN 1 ELSE 0 END) &lt; 3;
</code></pre>

Or use a subquery:

<pre><code>SELECT t.*
FROM (SELECT u.id, max(t.request_at) AS "Date",
 sum(CASE WHEN t.view = 1 THEN 1 ELSE 0 END) AS ONE,
 sum(CASE WHEN t.view = 2 THEN 1 ELSE 0 END) AS TWO,
 sum(CASE WHEN t.view = 3 THEN 1 ELSE 0 END) AS THREE
 FROM users u JOIN
 t
 ON u.id = t.uid
 WHERE u.signup_city_id = 18 AND u.creationtime BETWEEN '2013-12-01' AND '2014-01-01'
 group by 1
 ) t
WHERE ONE &lt; 3;
</code></pre>

I would like to filter the result set on the variables that are listed in the CASE statements.

<pre><code>SELECT u.id,
max(t.request_at) AS "Date",
sum(CASE
 WHEN t.view = 1 THEN 1
 ELSE 0 END) AS ONE,
sum(CASE
 WHEN t.view = 2 THEN 1
 ELSE 0 END) AS TWO,
sum(CASE
 WHEN t.view = 3 THEN 1
 ELSE 0 END) AS THREE

FROM users u

JOIN t ON u.id = t.uid

WHERE u.signup_city_id = 18
AND u.creationtime BETWEEN '2013-12-01' AND '2014-01-01'

group by 1
</code></pre>

I would really like to filter something along the lines of: WHERE ONE &lt; 3

i.e. Where the column one is smaller than 3.

Using WHERE to filter a CASE statement

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想在CASE语句中列出的变量上筛选结果集。SELECT u.id,max(t.request_at) AS "Date",sum(CASE    WHEN t.view = 1 THEN 1    ELSE 0 END) AS ONE,sum(CASE    WHEN t.view = 2 THEN 1    ELS...

问使用WHERE筛选CASE语句
EN

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