blocks|key|347202|text|如果你在游戏中有一个以上的输入处理器，并且你希望在你的情况被其中一个处理器处理后，它不应该去其他处理器，而不是返回真；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|347203|否则，如果你想让它去其他处理器，也比你应该返回假。|347204|假设你有两个输入处理器，并且都有一个按键。如果你有一个条件，只有一个应该执行返回真从两个键下降，其他返回假。|347205|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

if u are having more than one input processor in the game and u want that after your condition is handled by one of the processor it should not go to other processor than return true;

else if u want it to go to other processors also than u should return false.

Consider a case where u have two input processor and both have a key down. if u have a condition that only one should execute return true from both key downs else return false.

blocks|key|3135081|text|您自己链接的文档如下所示|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3135082|返回:是否处理了输入
|blockquote|3135083|3135084|返回true意味着事件是由该处理程序处理的，并且它不会被触发到随后的任何其他处理程序。|3135085|如果您希望其他处理器也能接收事件并让它们也处理它，那么您的第一个处理程序需要return+false。|offset|length|style|CODE|3135086|entityMap^0|0|0|0|0|12|C|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Q|8|@]|9|@]|A|$]]|$1|E|3|-4|5|6|7|R|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|S|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|T|8|@$J|U|K|V|L|M]]|9|@]|A|$]]|$1|N|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|O|$]]

The documentation you linked yourself says the following

<blockquote>
 Returns: whether the input was processed
</blockquote>

Returning true means that the event was processed by that handler and it won't be fired to any other handler which comes after that.

If you want the other processors in line to also receive the event and let them handle it as well, then your first handler needs to <code>return false</code>.

blocks|key|345551|text|您返回的boolean值应该是：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|345552|如果此InputProcessor或InputAdapter处理输入，则为true。|ordered-list-item|345553|如果不处理输入，则为false。|345554|345555|345556|想想一个游戏，其中两个玩家在同一台电脑上玩(例如，分裂屏幕)。|345557|一个玩家用"WASD“控制，另一个用”箭头键“控制。因此，第一个播放器的InputProcessor只处理"WASD“键，而第二个只处理”箭头键“的InputProcessor。|345558|如果按下的键是"W，A，S或D"，则第一个InputProcessor处理它，您不需要将它交给第二个。所以你返回true。如果按下的键是“箭头键”之一，则第一个InputProcessor将无法处理它，因此您将返回false。|345559|复用器得到这个返回值，并说：|345560|返回为true，输入已被处理，将其丢弃。|345561|返回为false，输入未处理，将其交给下一个处理器。|345562|345563|345564|希望你能明白我说的是什么|345565|编辑：，keyDown(int+keyCode)，keyUp(int+keyCode)和其他方法都有int+keyCode，它告诉您按下了int+keyCode键。通常，您可以使用开关来知道按下了哪个键。这个开关看起来如下：|BOLD|345566|switch(keyCode)+{
case+Keys.W:
+++++//+Handle+the+event+for+"W"+key+pressed
case+Keys.A:
+++++//+Handle+the+event+for+"A"+key+pressed
//+Other+cases
default:
+++++return+false;
}
return+true;|code-block|syntax|javascript|345567|对于你在评论中的另一个问题:如果一个玩家被W，A，S，D控制，他不需要处理其他键的输入。因此，如果不处理输入，则返回false，否则返回true。第二个玩家被箭头键控制，所以他不需要处理其他的键，如W，A，S或D键。如果有一个以上的InputProcessor+(必须处理相同的键)，则必须返回false，以便InputMultiplexer将事件传递给每个InputProcessor。|345568|entityMap^0|4|7|0|3|E|I|C|0|0|0|0|0|10|E|22|E|0|L|E|1K|4|28|E|0|0|3|4|0|3|5|0|0|0|0|0|3|4|K|P|I|1E|B|1X|B|0|0|38|E|4B|G|4Z|E|0^^$0|@$1|2|3|4|5|6|7|1E|8|@$9|1F|A|1G|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1H|8|@$9|1I|A|1J|B|C]|$9|1K|A|1L|B|C]]|D|@]|E|$]]|$1|I|3|J|5|H|7|1M|8|@]|D|@]|E|$]]|$1|K|3|-4|5|6|7|1N|8|@]|D|@]|E|$]]|$1|L|3|-4|5|6|7|1O|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|1P|8|@]|D|@]|E|$]]|$1|O|3|P|5|6|7|1Q|8|@$9|1R|A|1S|B|C]|$9|1T|A|1U|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1V|8|@$9|1W|A|1X|B|C]|$9|1Y|A|1Z|B|C]|$9|20|A|21|B|C]]|D|@]|E|$]]|$1|S|3|T|5|6|7|22|8|@]|D|@]|E|$]]|$1|U|3|V|5|H|7|23|8|@$9|24|A|25|B|C]]|D|@]|E|$]]|$1|W|3|X|5|H|7|26|8|@$9|27|A|28|B|C]]|D|@]|E|$]]|$1|Y|3|-4|5|6|7|29|8|@]|D|@]|E|$]]|$1|Z|3|-4|5|6|7|2A|8|@]|D|@]|E|$]]|$1|10|3|11|5|6|7|2B|8|@]|D|@]|E|$]]|$1|12|3|13|5|6|7|2C|8|@$9|2D|A|2E|B|14]|$9|2F|A|2G|B|C]|$9|2H|A|2I|B|C]|$9|2J|A|2K|B|C]|$9|2L|A|2M|B|C]]|D|@]|E|$]]|$1|15|3|16|5|17|7|2N|8|@]|D|@]|E|$18|19]]|$1|1A|3|1B|5|6|7|2O|8|@$9|2P|A|2Q|B|C]|$9|2R|A|2S|B|C]|$9|2T|A|2U|B|C]]|D|@]|E|$]]|$1|1C|3|-4|5|6|7|2V|8|@]|D|@]|E|$]]]|1D|$]]

The <code>boolean</code> value you return should be:

<ol>
<li>true, if this <code>InputProcessor</code> or <code>InputAdapter</code> handled the input.</li>
<li>false, if it did not handle the input.</li>
</ol>

Think about a game, where 2 players play on the same pc (splitscreen for example). 
One player controlls with "WASD", the second with "Arrow keys". So the <code>InputProcessor</code> for the first player handles only the "WASD" keys and the <code>InputProcessor</code> for the second only the "Arrow keys". 
If the pressed key was "W,A,S or D", the first <code>InputProcessor</code> handles it and you don't need to give it to the second one. So you return <code>true</code>. If the pressed key is one of the "Arrow keys", the first <code>InputProcessor</code> won't handle it and so you return false.

The multiplexer gets this return value and says:

<ol>
<li>The return is <code>true</code>, input was handled, throw it away.</li>
<li>The return was <code>false</code>, input not handled, give it to the next processor.</li>
</ol>

Hope you understand what i am talking about :P

Edit: the <code>keyDown(int keyCode)</code>, <code>keyUp(int keyCode)</code> and other methods have the <code>int keyCode</code>, which tells you whihc key was pressed. Usually you use a switch to know which key was pressed. This switch looks like this:

<pre><code>switch(keyCode) {
case Keys.W:
 // Handle the event for "W" key pressed
case Keys.A:
 // Handle the event for "A" key pressed
// Other cases
default:
 return false;
}
return true;
</code></pre>

For your other question in the comment: If 1 player is controlled by W,A,S,D he does not need to handle the input for other keys. So he returns false, if he did not handle the input and true otherwise.
The second player is controlled by the arrow keys, so he does not need to handle other keys, like the W, A, S or D key.
If you have more then one <code>InputProcessor</code>, which have to handle the same keys, you have to return false, so that the <code>InputMultiplexer</code> passes the event to every <code>InputProcessor</code>.

I am having problems handling inputs from more than one separate InputAdapters that use keyDown/keyUp.

<code>Gdx.input.setInputProcessor( new InputMultiplexer( keyboardController1, keyboardController2, keyboardController3));</code>

Only the first one in line works, while the others don't; in this case keyboardController1.
I am guessing it has something to do with the <code>return true;</code> at the end of the <code>keyDown()</code> methods'.
I tried reading the documentation, tutorials, post...etc But, I still can't get a good grasp on what the return value means and does, nor to which boolean value I should set it to.
My question:
What is the meaning of the boolean return value of the keyDown/keyUp(and so forth)?

<ul>
<li><a href="http://libgdx.badlogicgames.com/nightlies/docs/api/com/badlogic/gdx/InputProcessor.html#keyDown%28int%29" rel="nofollow">http://libgdx.badlogicgames.com/nightlies/docs/api/com/badlogic/gdx/InputProcessor.html#keyDown%28int%29</a></li>
</ul>

LIBGDX: What is the meaning of the return value of an InputAdapter's keyDown, keyUp...etc

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我在处理来自多个使用keyDown/keyUp的独立InputAdapters的输入时遇到了问题。Gdx.input.setInputProcessor( new InputMultiplexer(  keyboardController1, keyboardController2, keyboardControlle...

问LIBGDX: InputAdapter的keyDown，keyUp...etc的返回值的含义是什么
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问LIBGDX: InputAdapter的keyDown，keyUp...etc的返回值的含义是什么EN