所以我有两个数组:
1. $users_populated = users_populated: Array
(
[0] => Array
(
[id] => 10000106
[username] =>
[name] =>
[firstname] =>
[initial] =>
[surname] =>
)
[1] => Array
(
[id] => 10000106
[username] =>
[name] =>
[firstname] =>
[initial] =>
[surname] =>
[email] =>
[role] =>
[roleids] =>
[platform] =>
)
[2] => Array
(
[id] => 10000065
[username] =>
[name] =>
[firstname] =>
[initial] =>
[surname] =>
[email] =>
)
[3] => Array
(
[id] => 296
[username] =>
[name] =>
[firstname] =>
[initial] =>
[surname] =>
[email] =>
)
[4] => Array
(
[id] => 297
[username] =>
[name] =>
[firstname] =>
[initial] =>
[surname] =>
[email] =>
)
)
2. $user_list: Array
(
[0] => 10000106
[1] => 297
)因此,我需要第一个数组的值,它匹配第二个数组,即条目:
$output = output: Array
(
[0] => Array
(
[id] => 10000106
[username] =>
[name] =>
[firstname] =>
[initial] =>
[surname] =>
)
[1] => Array
(
[id] => 297
[username] =>
[name] =>
[firstname] =>
[initial] =>
[surname] =>
[email] =>
)
)简而言之,来自第一个数组的ID和第二个数组中的值应该匹配。
我试过使用数组相交键,但没有成功。
感谢您的阅读。
发布于 2014-04-04 07:12:07
通过循环$users_populated和array_seach函数,您可以获得预期的结果。
<?php
$output = array();
// Case 1: This will overlap by using the last appearance of the same ID value if repeated ID appears in $users_populated
foreach($users_populated as $value) {
if($key = array_search($value['id'], $user_list))
$output[$key] = $value;
}
// Case 2: This will use the first result found in $users_populated
foreach($users_populated as $value) {
if(empty($output[$value['id']]) && $key = array_search($value['id'], $user_list))
$output[$key] = $value;
}
var_dump($output);希望这是你想要的。
发布于 2014-04-04 07:03:06
使用array_uintersect()
$result = array_uintersect($one, $two, function($x, $y)
{
$x = is_array($x)?$x['id']:$x;
$y = is_array($y)?$y['id']:$y;
return $x-$y;
});-your第二个数组是简单的,因此它将在回调中直接工作。
发布于 2014-04-04 07:06:25
当您想要检查两个数组是否包含相同的值时,无论值的顺序如何,您都不能使用"==“或"===”。试试这个函数。
<?php
function array_equal($a, $b) {
return (is_array($a) && is_array($b) && array_diff($a, $b) === array_diff($b, $a));
}
?>https://stackoverflow.com/questions/22855631
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