如何在浏览器中执行“后退”然后“转发”时强制用户插入用户名和密码？
如何在浏览器中执行“后退”然后“转发”时强制用户插入用户名和密码？
提问于 2014-04-05 10:01:06
考虑以下事件(银行登录)：
这里发生的是：
- user logs in
- reaches a new page
- hits back
- hits forward
- reaches the same page - 当用户试图向前击并到达他来自的旧页面时，我如何让用户点击他的用户名和密码？
- 是否可以完全禁用后退/前进选项？
下面是一些代码：
登录JSP：
<!-- Bank Application in JAVA -->
<!-- Updates : the DB now is using Hibernate for the SQL queries -->
<!-- 2014 version updates -->
<%@ page language="java"
contentType="text/html; charset=windows-1256"
pageEncoding="windows-1256"
%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head><title>Bank application</title>
<link rel="stylesheet"
href="./css/styles.css"
type="text/css"/>
</head>
<body>
<table class="title">
<tr><th>Web Bank application</th></tr>
</table>
<br/>
<!-- JS Code to make sure that the user MUST enter something in the login page -->
<script>
function verifyEmptyString()
{
var username = document.forms["loginForm"]["username"].value;
var password = document.forms["loginForm"]["password"].value;
if (username == null || username == '' || password == null || password == '')
{
alert("Both Username and Password are required !");
return false;
}
return true;
}
</script>
<fieldset>
<legend>Login Page - please enter your Username and Password</legend>
<form onsubmit="return verifyEmptyString(this)" id="loginForm" action="loginPage" method="post" >
<!-- note we use here a paragraph & font size -->
<!-- Notice we use a Required field !!! -->
<p style="font-size:15px"> <span style="color:red;font-weight:bold;">*</span> Username: <input type="text" name="username"><br> </p>
<p style="font-size:15px"><span style="color:red;font-weight:bold;">*</span> Password : <input type="password" name="password"><br> </p>
<input type="submit" value="Login">
</form>
</fieldset>
<br/>
<br/>
<br/>
<br/>
<br/><br/><br/><br/><br/><br/>
</body></html>登录的servlet：
package controller;
import java.io.IOException;
import java.sql.SQLException;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
import model.Person;
import db.Database;
/**
* When the user runs for the first time the bank application , he must first enter username & password
* and make a proper login into the system .
* @author Administrator
*
*/
@WebServlet("/loginPage") // this is the name of the servlet
public class LoginPage extends HttpServlet {
private static final String EMPLOYEE = "Employee";
private static final String CLIENT = "Client";
private static final String MANAGER = "Manager";
private static final String ADMIN = "Administrator";
private static final long serialVersionUID = 1L;
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{
HttpSession session = request.getSession();
synchronized(session)
{
String atrib = (String) session.getAttribute("loginFlag");
// create a new connection to mysql database , with this we put the new client in the database
Database myDabatase = null;
Person personDb = null;
try
{
myDabatase = new Database(); // creating a database
}
catch (ClassNotFoundException e) {e.printStackTrace();}
// create a new database
if (atrib == null) // then this is the first run of the program
{
myDabatase.deleteDatabase(); // delete previous database
}
myDabatase.createDatabaseAndTables(); // create the tables of the database
////////////// Adding people with permissions into the bank database
/**
* if atrib == null , this means that this is the first time
* that we run the current session .
*
* if atrib != null , then this is NOT the first time that this session
* is is reaching the current servlet
*/
if (atrib == null)
{
// add employees and clients of the bank
returnValue = myDabatase.
addNewPerson("Johnny", "Cordel" , "South-Africa" , "22421" , "cole" , "cole" , CLIENT);
returnValue = myDabatase.
addNewPerson("Jason", "Bourne" , "Australia" , "32323" , "jason" , "jason" , EMPLOYEE);
// add a manager
returnValue = myDabatase.
addNewPerson("Jacky", "Chan" , "Japan" , "29489324" , "jake" , "jake" , MANAGER);
if (returnValue == false)
throw new ServletException(); // if we got here - the person wasn't added
// add an initial account to the bank
// _accountNumber , _currentState , _holderIdnumber
myDabatase.openNewAccount("0123",120, "87534");
myDabatase.openNewAccount("0123",120, "12345");
myDabatase.openNewAccount("001234",-210, "22421");
myDabatase.openNewAccount("00212",-4343, "32323");
}
// get the username that the user entered into the text box
String username = request.getParameter("username");
// get the password entered into the text box
String password = request.getParameter("password");
try
{
// check if the client that entered the login details of Username & Password
// exists in the database
// find the user with the given "password" & "username"
personDb = myDabatase.verifyRegisteredPerson(username, password);
}
catch (SQLException e1)
{
e1.printStackTrace();
}
// making sure to use the person the next time we reach the same page
session.setAttribute("name", personDb);
// then the person exists in the db , forwarding to the right place - first check if the person is a client
// according to the credentials of the person , 4 options goes here :
// manager , client , admin , or - employee
if (personDb != null)
{
session.setAttribute("loginFlag", "turndOn");
///////////// client
if (personDb.getStatus().equals(CLIENT) == true)
{
String addressPath = "/WEB-INF/results/client/clientPage.jsp";
RequestDispatcher dispatcher = request.getRequestDispatcher(addressPath);
dispatcher.forward(request, response);
}
///////////// manager
// person is a manager - redirecting to the Manager's page
else if (personDb.getStatus().equals(MANAGER) == true)
{
session.setAttribute("managerLogin", "turnOn");
String addressPath = "/WEB-INF/results/manager/managerPage.jsp";
RequestDispatcher dispatcher = request.getRequestDispatcher(addressPath);
dispatcher.forward(request, response);
}
//////////////////// administrator
// person is the administrator of the bank - forwarding to the admin's page
else if (personDb.getStatus().equals(ADMIN) == true)
{
String addressPath = "/WEB-INF/results/admin/adminPage.jsp";
RequestDispatcher dispatcher = request.getRequestDispatcher(addressPath);
dispatcher.forward(request, response);
}
////////////////// employee
// person is an employee - forwarding to the employee's page
else if (personDb.getStatus().equals(EMPLOYEE) == true)
{
String addressPath = "/WEB-INF/results/employee/employeePage.jsp";
RequestDispatcher dispatcher = request.getRequestDispatcher(addressPath);
dispatcher.forward(request, response);
}
}
////////////// the user how entered the password & username doesn't exist
else if (personDb == null) // then the client doesn't exist , and isn't registered
{
String addressPath = "/WEB-INF/results/login-failed.jsp";
RequestDispatcher dispatcher = request.getRequestDispatcher(addressPath);
dispatcher.forward(request, response);
}
} // end session
// closing database
} // end method get
}Stack Overflow用户
回答已采纳
发布于 2014-04-08 10:20:22
您可以执行something such as this，其中每个导航或表单提交张贴到下一页。
例如：
<form method="https://www.example.com/requestHandler">
<input type="action" value="navigateToLoginForm" />
<input type="token" value="qwerty1234" />
</form>因为每个导航操作都是一个帖子，浏览器将要求用户在历史导航时重新提交他们的数据(例如。后退按钮)。如果您收到一个已经使用的token值，您将知道用户没有跟踪您的预设流，您可以要求他们再次登录。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/22879367
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