blocks|key|532641|text|我不确定，但我认为最简单的方法是在view内部进行验证，以处理您的登录：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|532642|if(request.user.is_authenticated):
++++return+redirect('/');+#homepage,+whatever
else:
++++....|code-block|syntax|javascript|532643|entityMap^0|H|4|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

I am not sure but I believe that the easiest way is to do a verification inside the<code>view</code> that handles your login:

<pre><code>if(request.user.is_authenticated):
 return redirect('/'); #homepage, whatever
else:
 ....
</code></pre>

blocks|key|532645|text|在登录方法中，检查请求上下文中的用户是否已登录。如果是这样，则将该用户重定向到另一个视图，如果没有，则让他查看登录视图。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|532646|+def+login_page(request):

+++username+=+password+=+''
+++loginForm+=+LoginForm

++if+request.POST:
++++username+=+request.POST.get('usernameInput')
++++password+=+request.POST.get('passwordInput')
++++next+=+request.POST.get('nextInput')

++++user+=+authenticate(username=username,+password=password)

++++if+user+is+not+None:
++++++++if+user.is_active:
++++++++++++login(request,+user)
++++++++++++state+=+"User+successfully+logged+in!"

++++++++++++return+HttpResponseRedirect("/dashboard/")
++++++++else:
++++++++++++state+=+"Your+account+is+not+active"
++++else:
++++++++state+=+"Your+username+and/or+password+were+incorrect."
++else:
++++print('form+was+not+posted')

++variables=RequestContext(request,{
++++'form':loginForm
++})
++return+render_to_response('login.html',variables)|code-block|syntax|javascript|532647|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In your login method check whether the user in the request context is logged in or not. If so redirect that user to another view, if not let him see the login view.

<pre><code> def login_page(request):

 username = password = ''
 loginForm = LoginForm

 if request.POST:
 username = request.POST.get('usernameInput')
 password = request.POST.get('passwordInput')
 next = request.POST.get('nextInput')

 user = authenticate(username=username, password=password)

 if user is not None:
 if user.is_active:
 login(request, user)
 state = "User successfully logged in!"

 return HttpResponseRedirect("/dashboard/")
 else:
 state = "Your account is not active"
 else:
 state = "Your username and/or password were incorrect."
 else:
 print('form was not posted')

 variables=RequestContext(request,{
 'form':loginForm
 })
 return render_to_response('login.html',variables)
</code></pre>

blocks|key|3504747|text|在template.html中使用templateTags隐藏内容，如下所示：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3504748|{%25+if+user.is_authenticated+%25}
++Only+a+logged+in+User+can+view
{%25+else+%25}
++Only+a+logged+out+User+can+view
{%25+endif+%25}|code-block|syntax|javascript|3504749|编辑|3504750|如果要在呈现网页之前重定向用户，则可以在视图中这样做。|3504751|def+myView(request):
++++if+request.user.is_authenticated:
++++++++return+render(request,+'logged_in_view.html')
++++else:
++++++++return+render(request,+'logged_out_view.html')|3504752|entityMap^0|1|D|H|C|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|Z|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|Q|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|R|$]]

You hide content within the <code>template.html</code> using <code>templateTags</code> like so:

<pre><code>{% if user.is_authenticated %}
 &lt;p&gt;Only a logged in User can view&lt;/p&gt;
{% else %}
 &lt;p&gt;Only a logged out User can view&lt;/p&gt;
{% endif %}
</code></pre>

[EDIT]

If you would like to then redirect the user before the web page is rendered, then you can do that in the view.

<pre><code>def myView(request):
 if request.user.is_authenticated:
 return render(request, 'logged_in_view.html')
 else:
 return render(request, 'logged_out_view.html')
</code></pre>

blocks|key|533417|text|可能的解决方案:我创建'my_login'：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|533418|def+my_login(request):
++++if+request.user.is_authenticated():
++++++++return+redirect(#...home)
++++else:
++++++++return+login(request,+'template/login.html')+#+here+i+used+login+built-in+function
+++++++++++++++++++++++++++++++++++++++++++++++++++++#+instead+of+using+directly+in+urls.py|code-block|syntax|javascript|533419|我在urls.py中使用了urls.py视图而不是'django.contrib.auth.views.login'|offset|length|style|CODE|533420|编辑|533421|New+in+Django+1.10:
The+redirect_authenticated_user+parameter+was+added.|533422|检查https://docs.djangoproject.com/en/1.10/topics/auth/default/#django.contrib.auth.views.login|533423|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.djangoproject.com/en/1.10/topics/auth/default/#django.contrib.auth.views.login^0|0|0|P|X|0|0|0|2|2J|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|12|8|@$I|13|J|14|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|15|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|16|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|17|8|@]|9|@$I|18|J|19|1|1A]]|A|$]]|$1|S|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z]]]]

Possible solution:
I create 'my_login':

<pre><code>def my_login(request):
 if request.user.is_authenticated():
 return redirect(#...home)
 else:
 return login(request, 'template/login.html') # here i used login built-in function
 # instead of using directly in urls.py
</code></pre>

And i used <code>my_login</code> view in urls.py instead of <code>'django.contrib.auth.views.login'</code>

EDIT

<pre><code>New in Django 1.10:
The redirect_authenticated_user parameter was added.
</code></pre>

Check <a href="https://docs.djangoproject.com/en/1.10/topics/auth/default/#django.contrib.auth.views.login" rel="nofollow noreferrer">https://docs.djangoproject.com/en/1.10/topics/auth/default/#django.contrib.auth.views.login</a>

blocks|key|532682|text|由于基于类的视图(CBV)正在上升。这种方法将帮助您在访问非身份验证用户的视图时重定向到另一个url。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|532683|在我的示例中，注册页面覆盖get()方法。|CODE|532684|class+Signup(CreateView):
++++template_name+=+'sign-up.html'

++++def+get(self,+request,+*args,+**kwargs):
++++++++if+self.request.user.is_authenticated:
++++++++++++return+redirect('path/to/desired/url')
++++++++else:
++++++++++++#+Omit+the+form+if+you+are+not+using+it.
++++++++++++form+=+self.form_class()+
++++++++++++return+render(request,+self.template_name,+{'form':+form})|code-block|syntax|javascript|532685|为了简单起见，还可以在View类的dispatch()方法上这样做。|532686|def+dispatch(self,+*args,+**kwargs):
++++if+self.request.user.is_authenticated:
++++++++return+redirect('path/to/desired/url')
++++return+super().dispatch(*args,+**kwargs)|532687|干杯!|532688|entityMap^0|4|1B|0|0|L|D|5|0|0|0|Y|H|A|0|0|0|3|0^^$0|@$1|2|3|4|5|6|7|V|8|@$9|W|A|X|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|H]]|D|@]|E|$]]|$1|I|3|J|5|K|7|13|8|@]|D|@]|E|$L|M]]|$1|N|3|O|5|6|7|14|8|@$9|15|A|16|B|C]|$9|17|A|18|B|H]]|D|@]|E|$]]|$1|P|3|Q|5|K|7|19|8|@]|D|@]|E|$L|M]]|$1|R|3|S|5|6|7|1A|8|@$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|T|3|-4|5|6|7|1D|8|@]|D|@]|E|$]]]|U|$]]

Since class based views (CBVs) is on the rise. This approach will help you redirect to another url when accessing view for non authenticated users only.

In my example the sign-up page overriding the <code>get()</code> method.

<pre><code>class Signup(CreateView):
 template_name = 'sign-up.html'

 def get(self, request, *args, **kwargs):
 if self.request.user.is_authenticated:
 return redirect('path/to/desired/url')
 else:
 # Omit the form if you are not using it.
 form = self.form_class() 
 return render(request, self.template_name, {'form': form})
</code></pre>

You can also do this on <code>dispatch()</code> method of the View class for simplicity sake.

<pre><code>def dispatch(self, *args, **kwargs):
 if self.request.user.is_authenticated:
 return redirect('path/to/desired/url')
 return super().dispatch(*args, **kwargs)
</code></pre>

Cheers!

blocks|key|2961934|text|您只需编写登录url，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2961935|from+django.contrib.auth+import+views+as+auth_views

path('login/',+auth_views.LoginView.as_view(template_name="accounts/login.html",+redirect_authenticated_user=True),+name='login'),|code-block|syntax|javascript|2961936|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Simply you can write you login url as this:

<pre><code>from django.contrib.auth import views as auth_views

path('login/', auth_views.LoginView.as_view(template_name="accounts/login.html", redirect_authenticated_user=True), name='login'),
</code></pre>

I'm using <code>django.contrib.auth</code> to handle user authentication in my django project. In order to log in, I have

<pre><code>from django.contrib.auth.views import login, logout

# ...

url(r'^login/', login, name='login'),
url(r'^logout/', logout, {'next_page': '/'}, name='logout'),
</code></pre>

in my main project's <code>urls.py</code>.

So far, so good. However, I notice that after logging in, if I access <code>/login/</code>, I still see the login page, and am able to log in as another user. This seems like counter-intuitive behavior -- most websites will either show an error or redirect you to the homepage if you attempt to access the login page while logged in.

I'm using the builtin models / views, and so as far as I know I have no easy way of altering the views. Is there a simple way of gaining this functionality (i.e. preventing access to the login form if logged in), or is the best way simply to modify the template to only show the form if not logged in?

Logged in users still see login page (django auth)

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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在django项目中，我使用django.contrib.auth来处理用户身份验证。为了登录，我有from django.contrib.auth.views import login, logout# ...url(r'^login/', login, name='login'),url(r'^logout/', ...

问登录用户仍然可以看到登录页面(django auth)
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问登录用户仍然可以看到登录页面(django auth)EN