blocks|key|2366354|text|您的格式和值不匹配。试一试：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2366355|string+format+=+"MMM-yy";
DateTime+result;
CultureInfo+provider+=+CultureInfo.InvariantCulture;
result+=+DateTime.ParseExact("Mar-13",+format,+provider);|code-block|syntax|javascript|2366356|编辑|offset|length|style|BOLD|2366357|对于es-ES格式提供程序，我猜Mar在Marzo+(3月)和Martes+(星期二)之间是不明确的。如果您在适当的格式下使用ParseExact，您应该会很好：|CODE|2366358|string+format+=+"MMM-yy";
DateTime+result;
CultureInfo+provider+=+CultureInfo.GetCultureInfo("es-ES");

//+fails
result+=+DateTime.Parse("Mar-13",+provider);

//+works
result+=+DateTime.ParseExact("Mar-13",+format,+provider);
result+=+DateTime.ParseExact("Abr-13",+format,+provider);|2366359|编辑2|2366360|这似乎是一个已知臭虫。他们的解决办法是使用类似的区域性，但是如果您的日期格式是已知的，我建议使用ParseExact显式定义格式，而不是让框架尝试推断格式。|2366361|entityMap|0|LINK|mutability|MUTABLE|url|http://connect.microsoft.com/VisualStudio/feedback/details/822536/datetime-parse-result-in-exception-when-the-format-is-rfc1123-pattern-and-locale-is-a-latin-one#^0|0|0|0|2|0|2|5|G|3|1R|A|0|0|0|3|0|1C|A|6|4|0|0^^$0|@$1|2|3|4|5|6|7|13|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|15|8|@$I|16|J|17|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|18|8|@$I|19|J|1A|K|O]|$I|1B|J|1C|K|O]|$I|1D|J|1E|K|O]]|9|@]|A|$]]|$1|P|3|Q|5|D|7|1F|8|@]|9|@]|A|$E|F]]|$1|R|3|S|5|6|7|1G|8|@$I|1H|J|1I|K|L]]|9|@]|A|$]]|$1|T|3|U|5|6|7|1J|8|@$I|1K|J|1L|K|O]]|9|@$I|1M|J|1N|1|1O]]|A|$]]|$1|V|3|-4|5|6|7|1P|8|@]|9|@]|A|$]]]|W|$X|$5|Y|Z|10|A|$11|12]]]]

Your format and value don't match. Try this instead:

<pre><code>string format = "MMM-yy";
DateTime result;
CultureInfo provider = CultureInfo.InvariantCulture;
result = DateTime.ParseExact("Mar-13", format, provider);
</code></pre>

EDIT

For the <code>es-ES</code> format provider, my guess is that <code>Mar</code> is ambiguous between Marzo (March) and Martes (Tuesday). You should be fine if you use <code>ParseExact</code> with the proper format:

<pre><code>string format = "MMM-yy";
DateTime result;
CultureInfo provider = CultureInfo.GetCultureInfo("es-ES");

// fails
result = DateTime.Parse("Mar-13", provider);

// works
result = DateTime.ParseExact("Mar-13", format, provider);
result = DateTime.ParseExact("Abr-13", format, provider);
</code></pre>

EDIT 2

This appears to be a <a href="http://connect.microsoft.com/VisualStudio/feedback/details/822536/datetime-parse-result-in-exception-when-the-format-is-rfc1123-pattern-and-locale-is-a-latin-one#" rel="nofollow">known bug</a>. Their workaround is to use a similar culture, however if your date format is known, I'd recommend using <code>ParseExact</code> to explicitly define the format rather than letting the framework try and infer the format.

blocks|key|1369893|text|日期字符串"Mar-13"与格式"yyyyMM"不匹配。您的格式应该是MMM-yy。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1369894|您应该看到：自定义日期和时间格式字符串|1369895|以你的格式|1369896|"MMM“-这个月的缩写名称。
“耶”-从00岁到99岁。|blockquote|1369897|编辑：|1369898|问你为什么Convert.ToDateTime("Mar-13");失败了。您需要查看以下代码行：|1369899|var+currentCulture+=+new+CultureInfo("es-ES");
var+monthNames+=+currentCulture.DateTimeFormat.AbbreviatedMonthNames;
var+dayOfWeeks+=+currentCulture.DateTimeFormat.AbbreviatedDayNames;|code-block|syntax|javascript|1369900|如果在调试器中查看返回的值，您将看到区域性es-ES在月名和日名之间以及在mar上有一个匹配。|BOLD|1369901|Marzo/3月为月份|unordered-list-item|1369902|马提斯/星期二为日|1369903|这两个词都使用相同的缩写，即Mar。由于Convert.ToDateTime会尝试对字符串使用可能的格式，所以它无法将Mar识别为月名或日名。所以你才会有例外。|1369904|使用DateTime.ParseExact并指定单个或多种可能格式总是一个好主意。|1369905|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/8kb3ddd4%2528v=vs.110%2529.aspx|1|http://msdn.microsoft.com/en-us/library/332de853%2528v=vs.110%2529.aspx^0|5|8|G|8|Z|6|0|6|D|0|0|0|0|0|5|T|0|0|L|5|11|3|18|3|0|0|B|0|0|9|0|0|28|E|3|K|I|1N|3|0|0|15|2|J|R|6|1|0^^$0|@$1|2|3|4|5|6|7|1H|8|@$9|1I|A|1J|B|C]|$9|1K|A|1L|B|C]|$9|1M|A|1N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1O|8|@]|D|@$9|1P|A|1Q|1|1R]]|E|$]]|$1|H|3|I|5|6|7|1S|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|1T|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|1U|8|@]|D|@]|E|$]]|$1|O|3|P|5|6|7|1V|8|@$9|1W|A|1X|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|S|7|1Y|8|@]|D|@]|E|$T|U]]|$1|V|3|W|5|6|7|1Z|8|@$9|20|A|21|B|C]|$9|22|A|23|B|C]|$9|24|A|25|B|X]]|D|@]|E|$]]|$1|Y|3|Z|5|10|7|26|8|@$9|27|A|28|B|X]]|D|@]|E|$]]|$1|11|3|12|5|10|7|29|8|@$9|2A|A|2B|B|X]]|D|@]|E|$]]|$1|13|3|14|5|6|7|2C|8|@$9|2D|A|2E|B|X]|$9|2F|A|2G|B|C]|$9|2H|A|2I|B|C]|$9|2J|A|2K|B|C]]|D|@]|E|$]]|$1|15|3|16|5|6|7|2L|8|@$9|2M|A|2N|B|X]|$9|2O|A|2P|B|C]]|D|@$9|2Q|A|2R|1|2S]]|E|$]]|$1|17|3|-4|5|6|7|2T|8|@]|D|@]|E|$]]]|18|$19|$5|1A|1B|1C|E|$1D|1E]]|1F|$5|1A|1B|1C|E|$1D|1G]]]]

Your date string <code>"Mar-13"</code> doesn't match your format <code>"yyyyMM"</code>. Your format should be <code>MMM-yy</code>. 

You should see: <a href="http://msdn.microsoft.com/en-us/library/8kb3ddd4%28v=vs.110%29.aspx" rel="nofollow">Custom Date and Time Format Strings</a>

In your format 

<blockquote>
 "MMM" - The abbreviated name of the month.
 
 "yy" - The year, from 00 to 99.
</blockquote>

EDIT: 

For your question why <code>Convert.ToDateTime("Mar-13");</code> is failing. You need to look at the following lines of code:

<pre><code>var currentCulture = new CultureInfo("es-ES");
var monthNames = currentCulture.DateTimeFormat.AbbreviatedMonthNames;
var dayOfWeeks = currentCulture.DateTimeFormat.AbbreviatedDayNames;
</code></pre>

If you watch the returned values in debugger, You will see that for the culture <code>es-ES</code> there is a match between Month Name and Day name and that is on <code>mar</code>.

<ul>
<li>Marzo/March as Month</li>
<li>Martes/Tuesday as day</li>
</ul>

Both of these uses the same abbreviation i.e. <code>Mar</code>. Since <code>Convert.ToDateTime</code> would try to use possible formats for the string it fails to recognize <code>Mar</code> as Month or Day Name. That is why you get exception. 

It is always a good idea to use <code>DateTime.ParseExact</code> and specify a single or <a href="http://msdn.microsoft.com/en-us/library/332de853%28v=vs.110%29.aspx" rel="nofollow">multiple possible formats</a>.

blocks|key|2087857|text|我认为您需要使用正确的CultureInfo并修复格式字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2087858|CultureInfo+provider+=+new+CultureInfo("ES-es");
DateTime+result+=+DateTime.ParseExact("Abr-13",+"MMM-yy",+provider);|code-block|syntax|javascript|2087859|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I think you need to use the correct CultureInfo and fix the format string

<pre><code>CultureInfo provider = new CultureInfo("ES-es");
DateTime result = DateTime.ParseExact("Abr-13", "MMM-yy", provider);
</code></pre>

blocks|key|2087885|text|引用我关于自动DateTime解析背后的逻辑的答案：当给定区域性不知道格式时，Convert.ToDateTime()如何解析给定的字符串|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2087886|您可以在Abr-13区域性中自动解析Abr，因为Abr只能匹配为MonthToken。但是在Mar-13+-+Mar的情况下，可以匹配为MonthToken，也可以匹配为DayOfWeekToken+(星期二)，因此DateTime.Parse/Convert.ToDateTime方法被混淆并抛出异常。|style|CODE|2087887|如果针对es-ES区域性执行引用答案中的代码，将在输出中看到以下内容：|2087888|+++mar+DayOfWeekToken+2
+++Mar+MonthToken+3|code-block|syntax|javascript|2087889|但是，没有多个匹配的完整月份名称，所以您可以安全地解析'marzo'，'abril‘值。|2087890|由于DateTime.Parse/Convert.ToDateTime方法被Mar值的这种对偶性所混淆，我们需要使用DateTime.ParseExact方法向其提供提示：|2087891|DateTime+output+=+DateTime.ParseExact("Mar-13",+"MMM-yy",+CultureInfo.GetCultureInfo("es-ES"));|2087892|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/22809884/how-convert-todatetime-parses-a-given-string-when-the-given-culture-does-not-k/22856050#22856050^0|Q|17|0|0|4|6|I|3|O|3|W|A|1A|6|1J|3|1W|A|2D|E|30|E|3F|I|0|4|5|0|0|0|2|E|H|I|12|3|1M|J|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@$A|13|B|14|1|15]]|C|$]]|$1|D|3|E|5|6|7|16|8|@$A|17|B|18|F|G]|$A|19|B|1A|F|G]|$A|1B|B|1C|F|G]|$A|1D|B|1E|F|G]|$A|1F|B|1G|F|G]|$A|1H|B|1I|F|G]|$A|1J|B|1K|F|G]|$A|1L|B|1M|F|G]|$A|1N|B|1O|F|G]|$A|1P|B|1Q|F|G]]|9|@]|C|$]]|$1|H|3|I|5|6|7|1R|8|@$A|1S|B|1T|F|G]]|9|@]|C|$]]|$1|J|3|K|5|L|7|1U|8|@]|9|@]|C|$M|N]]|$1|O|3|P|5|6|7|1V|8|@]|9|@]|C|$]]|$1|Q|3|R|5|6|7|1W|8|@$A|1X|B|1Y|F|G]|$A|1Z|B|20|F|G]|$A|21|B|22|F|G]|$A|23|B|24|F|G]]|9|@]|C|$]]|$1|S|3|T|5|L|7|25|8|@]|9|@]|C|$M|N]]|$1|U|3|-4|5|6|7|26|8|@]|9|@]|C|$]]]|V|$W|$5|X|Y|Z|C|$10|11]]]]

Reference to my answer about logic behind automatic DateTime parsing: <a href="https://stackoverflow.com/questions/22809884/how-convert-todatetime-parses-a-given-string-when-the-given-culture-does-not-k/22856050#22856050">How Convert.ToDateTime() parses a given string when the given culture does not know the format</a>

You can automatically parse <code>Abr-13</code> in <code>es-ES</code> culture, because <code>Abr</code> can be matched only as <code>MonthToken</code>. But in case of <code>Mar-13</code> - <code>Mar</code> can be matched as <code>MonthToken</code> and also it can be matched as <code>DayOfWeekToken</code> (Tuesday), so <code>DateTime.Parse</code>/<code>Convert.ToDateTime</code> methods are confused and throw exception.

If you execute the code from referenced answer against <code>es-ES</code> culture, you would see the following in the output:

<pre><code> mar DayOfWeekToken 2
 Mar MonthToken 3
</code></pre>

There are no multiple matches for full months names though, so you can safely parse 'marzo', 'abril' values.

Since <code>DateTime.Parse</code>/<code>Convert.ToDateTime</code> methods are confused by this duality of <code>Mar</code> value, we need to provide a hint to it using <code>DateTime.ParseExact</code> method:

<pre><code>DateTime output = DateTime.ParseExact("Mar-13", "MMM-yy", CultureInfo.GetCultureInfo("es-ES"));
</code></pre>

blocks|key|2087904|text|您需要结合“MMM”格式使用西班牙文化信息：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2087905|++++++++string+format+=+"MMM-yy";
++++++++DateTime+result;
++++++++CultureInfo+provider+=+new+CultureInfo("es-ES");
++++++++result+=+DateTime.ParseExact("mar-13",+format,+provider);
++++++++result+=+DateTime.ParseExact("abr-13",+format,+provider);|code-block|syntax|javascript|2087906|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You need to use the Spanish culture info in association with the "MMM-yy" format : 

<pre><code> string format = "MMM-yy";
 DateTime result;
 CultureInfo provider = new CultureInfo("es-ES");
 result = DateTime.ParseExact("mar-13", format, provider);
 result = DateTime.ParseExact("abr-13", format, provider);
</code></pre>

blocks|key|2366509|text|在我的系统中，当前的文化是en-US，当尝试转换abril+(4月)时，以下代码将失败：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|2366510|string+format+=+"MMM-yy";
DateTime+result;
CultureInfo+provider+=+CultureInfo.InvariantCulture;
result+=+DateTime.ParseExact("abr-13",+format,+provider);|code-block|syntax|javascript|2366511|因此，在我的系统中，我必须创建一种西班牙文化才能使代码工作：|2366512|string+format+=+"MMM-yy";
DateTime+result;
CultureInfo+provider+=+CultureInfo.CreateSpecificCulture("es-ES");
result+=+DateTime.ParseExact("abr-13",+format,+provider);|2366513|因此，您需要了解您的代码正在运行的文化，并采取适当的操作。|2366514|entityMap^0|D|5|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|Y|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|R|$]]

On my system the current culture is en-US the following code will fail when trying to convert abril (April):

<pre><code>string format = "MMM-yy";
DateTime result;
CultureInfo provider = CultureInfo.InvariantCulture;
result = DateTime.ParseExact("abr-13", format, provider);
</code></pre>

Therefore on my system I have to create a Spanish culture for the code to work:

<pre><code>string format = "MMM-yy";
DateTime result;
CultureInfo provider = CultureInfo.CreateSpecificCulture("es-ES");
result = DateTime.ParseExact("abr-13", format, provider);
</code></pre>

So you need to be aware what culture your code is running on and take the proper action.

I need to convert to DateTime some strings with this format "MMM-yy". I'm working with the culture "{es-ES}".

It works fine with all month except with March (In spanish Marzo).
This throws me this exception:

<blockquote>
 'Convert.ToDateTime("Mar-13")' threw an exception of type
 'System.FormatException' System.DateTime {System.FormatException}
</blockquote>

I've tried:

<pre><code>string format = "yyyyMM";
DateTime result;
CultureInfo provider = CultureInfo.InvariantCulture;
result = DateTime.ParseExact("Mar-13", format, provider);
</code></pre>

and this:

<pre><code>DateTime date = Convert.ToDateTime("Mar-13");
</code></pre>

This works fine for example with:

"Jun-13"

"Feb-13"

"Nov-13"

...

EDIT
The real problem is with:

DateTime date = Convert.ToDateTime("Ene-13"); -> ok

DateTime date = Convert.ToDateTime("Feb-13"); -> ok

DateTime date = Convert.ToDateTime("Mar-13"); -> crash

DateTime date = Convert.ToDateTime("Abr-13"); -> ok

....

Particular DateTime exception

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我需要用这种格式将一些字符串转换为DateTime，“MMM”。我正在使用文化"{es-ES}"。除了三月(西班牙语马佐语)外，整个月都很好。这给我带来了一个例外：'Convert.ToDateTime("Mar-13")‘抛出了'System.FormatException’System.DateTime {Syst...

问特殊DateTime异常
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