我用三个表设计了以下技能数据库:
( 1)和( 2)只给人和技能分配号码。3)将技能水平分配给员工。
例如,表3中的第13行6 )是指拥有个人3号技能的人具有1项技能知识,而知识水平为6。
我想要的是找回那些同时擅长的人
这样做最好的方法是什么?我首先考虑选择符合条件1的人,然后从他们中选出符合条件2的人,然后从结果中选出符合条件3的人)。但是对于这种方法,我必须创建临时表,并使用一些过程编程语言超越SQL。有没有更好的方法?
发布于 2014-05-05 16:31:49
我会使用一个子查询来计算一个人的技能匹配数,并确保它是三个:
SELECT name
FROM person
WHERE personnelnumber IN (SELECT personnelnumber
FROM skillmapping
WHERE (skillid = 2 AND skilllevel = 3) OR
(skillid = 4 AND skilllevel = 5) OR
(skillid = 8 AND skilllevel = 2)
GROUP BY personnelnumber
HAVING COUNT(*) = 3)发布于 2014-05-05 16:40:13
应该是一个相当直截了当的内连接;
SELECT e.*
FROM employees e
JOIN skillmapping s1 ON s1.personnelnumber = e.personnelnumber
AND s1.skillid = 2
AND s1.skillevel = 3
JOIN skillmapping s2 ON s2.personnelnumber = e.personnelnumber
AND s2.skillid = 4
AND s2.skillevel = 5
JOIN skillmapping s3 ON s3.personnelnumber = e.personnelnumber
AND s3.skillid = 8
AND s3.skillevel = 2发布于 2014-05-05 16:33:55
查询(我使用现有功能来检查该组合是否存在.):
SELECT * FROM Employees WHERE
EXISTS (SELECT * FROM skillmapping t2 WHERE t2.PersonnelNumber = Employees.PersonnelNumber AND SkillId = 2 AND t2.SkillLevel >= 3) --NOTE: lvl 3 or more!
AND EXISTS (SELECT * FROM skillmapping t2 WHERE t2.PersonnelNumber = Employees.PersonnelNumber AND SkillId 4 AND t2.SkillLevel >= 5) -- NOTE: lvl 5 or more
AND EXISTS (SELECT * FROM skillmapping t2 WHERE t2.PersonnelNumber = Employees.PersonnelNumber AND SkillId = 8 AND t2.SkillLevel >= 2) -- NOTE: lvl 2 or more https://stackoverflow.com/questions/23477280
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