blocks|key|2505284|text|我认为不符合任何条件是不可能连接表的。否则，您必须将表B中的键与表A中的一个键放在一起。如果不想放置表B键(与表A键匹配)，这并不重要。您仍然可以使用SQL查询加入它。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2505285|这就像：|2505286|SELECT+tableA.*,+tableB.*+FROMtableA+JOIN+tableB+ON+tableA.id1+=+tableB.id1|code-block|syntax|javascript|2505287|您可以根据需要选择字段。|2505288|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

I think it's impossible to join tables without matching any conditions. Otherwise, you have to put the key from table B with one of table A key. It doesn't matter if you don't want to put the table B key(matched with table A key). You're still able to join it, using SQL query.

It will be like:

<pre><code>SELECT tableA.*, tableB.* FROMtableA JOIN tableB ON tableA.id1 = tableB.id1
</code></pre>

see, you can select the field based on you want.

blocks|key|2505306|text|使用row_number创建要用于完全连接的索引|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2505307|select+*+from+(
++++select+
++++++++row_number()+over+(order+by+id1+asc)+rn,
++++++++id1,+data1
++++from+ta
)+t1++++
full+join+(
++++select+
++++++++row_number()+over+(order+by+id2+asc)+rn,
++++++++id2,+data2
++++from+tb
)+t2+on+t1.rn+=+t2.rn
full+join+(
++++select+
++++++++row_number()+over+(order+by+id3+asc)+rn,
++++++++id3,+data3
++++from+tc
)+t3+on+t1.rn+=+t3.rn|code-block|syntax|javascript|2505308|entityMap^0|2|A|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Create an index using <code>row_number</code> to use for your full join 

<pre><code>select * from (
 select 
 row_number() over (order by id1 asc) rn,
 id1, data1
 from ta
) t1 
full join (
 select 
 row_number() over (order by id2 asc) rn,
 id2, data2
 from tb
) t2 on t1.rn = t2.rn
full join (
 select 
 row_number() over (order by id3 asc) rn,
 id3, data3
 from tc
) t3 on t1.rn = t3.rn
</code></pre>

blocks|key|2505332|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2505333|with+a+as
(select+*,+row_number()+over+(order+by+id1)+an+from+tableA),
b+as
(select+*,+row_number()+over+(order+by+id2)+bn+from+tableB),
c+as
(select+*,+row_number()+over+(order+by+id3)+cn+from+tableC)

select+a.id1,+a.data1,+b.id2,+b.data2,+c.id3,+c.data3+
from+a
full+outer+join+b+on+a.an+=+b.bn
full+outer+join+c+on+a.an+=+c.cn|code-block|syntax|javascript|2505334|SQL+Fiddle|offset|length|2505335|entityMap|0|LINK|mutability|MUTABLE|url|http://sqlfiddle.com/#!3/44004/10^0|0|0|0|A|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Try this:

<pre><code>with a as
(select *, row_number() over (order by id1) an from tableA),
b as
(select *, row_number() over (order by id2) bn from tableB),
c as
(select *, row_number() over (order by id3) cn from tableC)

select a.id1, a.data1, b.id2, b.data2, c.id3, c.data3 
from a
full outer join b on a.an = b.bn
full outer join c on a.an = c.cn
</code></pre>

<a href="http://sqlfiddle.com/#!3/44004/10" rel="nofollow">SQL Fiddle</a>

blocks|key|284108|text|试着做这样的事情：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|284109|SELECT+*
FROM+A
++++FULL+OUTER+JOIN+B+ON+1+=+1
++++FULL+OUTER+JOIN+C+ON+1+=+1|code-block|syntax|javascript|284110|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try something like this:
<pre><code>SELECT *
FROM A
 FULL OUTER JOIN B ON 1 = 1
 FULL OUTER JOIN C ON 1 = 1
</code></pre>

I am using MS SQL. 
I have the following tables:

<pre><code>table A:
 id1 data1
 8234 ko
 2 po
 333 koo
 40 woo

table B:
 id2 data2
 123 meow
 654 frrr

table C:
 id3 data3
 10 a
 20 b
 30 c
 40 d
 50 e 
 60 f
</code></pre>

I want to get this:

<pre><code> id1 data1 id2 data2 id3 data3
 8234 ko 123 meow 10 a
 2 po 654 frrr 20 b
 333 koo NULL NULL 30 c
 40 woo NULL NULL 40 d
 NULL NULL NULL NULL 50 e
 NULL NULL NULL NULL 60 f
</code></pre>

It's seems like full sum of tables without any conditions. I just want to get all columns and all data from all tables as is. How can I do this?
UPD: tables are not related. 
In case when tables are related: I would use LEFT or RIGHT JOIN, when it was known in advance what table is larger than. But it is unknown.

SQL full join without any conditions

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在使用MS。我有以下表格：table A:    id1   data1    8234    ko    2       po    333     koo    40      wootable B:    id2     data2    123     meow    654     frrrtable C...

问没有任何条件的SQL完全连接
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问没有任何条件的SQL完全连接EN