blocks|key|4258325|text|根据您的问题描述，您不需要return两个对象。您只需创建和return一个ArrayList，并对setToCheck进行就地修改.由于setToCheck是一个对象引用，所以对方法中的对象所做的任何更改都将在外部可见。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4258326|entityMap^0|D|6|U|6|12|9|1E|A|1X|A|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]|$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|G|$]]

By your problem description, you don't need to <code>return</code> two objects. You can just create and <code>return</code> an <code>ArrayList</code> and make alterations to <code>setToCheck</code> in-place. Since <code>setToCheck</code> is an object reference, any changes made to the object inside the method will be visible outside.

blocks|key|4258353|text|如果在setToCheck方法中修改necessaryChanges对象，则该方法之外的更改也是可见的，因为在Java+(不包括原语类型，但不是您的情况)是作为引用传递的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4258354|因此，基本上，您不需要返回--+setToCheck对象:您仍然可以在方法调用之后使用它:它始终是同一个对象(在方法内部和外部)，因此它将包含新的更改。|BOLD|4258355|entityMap^0|3|A|I|G|0|7|6|G|A|0^^$0|@$1|2|3|4|5|6|7|K|8|@$9|L|A|M|B|C]|$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|P|8|@$9|Q|A|R|B|H]|$9|S|A|T|B|C]]|D|@]|E|$]]|$1|I|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|J|$]]

If you modify the <code>setToCheck</code> object inside the <code>necessaryChanges</code> method, the changes will be visible also outside of that method, since in Java everything (primitive types excluded, but it's not your case) is passed as reference.

So basically you don't need to return the <code>setToCheck</code> object: you can simply still use it after the method call: it is always the same object (inside and outside the method), therefor it will contains the new changes.

blocks|key|4258372|text|正如其他人所指出的，Java是通过引用传递的。因此，如果您在setToCheck中更改了一个对象，那么它将在内存中被更改，因此，除了更改对象引用之外，不需要做任何其他事情。比如说..。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4258373|++++public+List<String>+neccessaryChanges(Set<Object>+setToCheck)+{
++++++++List<String>+changeList+=+new+ArrayList<String>();
++++++++Iterator<Object>+iterator+=+setToCheck.iterator();
++++++++while(iterator.hasNext())+{
++++++++++++Object+objectToCheck+=+iterator.next();
++++++++++++if(objectMustChange)+{
++++++++++++++++//once+you+change+the+object+here,+it+will+change+
++++++++++++++++//in+setToCheck+since+objectToCheck+now+equals+something
++++++++++++++++//different+and+setToCheck+still+has+reference+to+
++++++++++++++++//objectToCheck
++++++++++++++++objectToCheck+=+new+String();
++++++++++++++++changeList.add((String)+objectToCheck);
++++++++++++}
++++++++}
++++++++return+changeList;
++++}|code-block|syntax|javascript|4258374|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

As others have pointed out, Java is pass by reference. So, if you change an object in setToCheck, it will be changed in memory and therefore no need to do anything other than change your object reference. For instance...

<pre><code> public List&lt;String&gt; neccessaryChanges(Set&lt;Object&gt; setToCheck) {
 List&lt;String&gt; changeList = new ArrayList&lt;String&gt;();
 Iterator&lt;Object&gt; iterator = setToCheck.iterator();
 while(iterator.hasNext()) {
 Object objectToCheck = iterator.next();
 if(objectMustChange) {
 //once you change the object here, it will change 
 //in setToCheck since objectToCheck now equals something
 //different and setToCheck still has reference to 
 //objectToCheck
 objectToCheck = new String();
 changeList.add((String) objectToCheck);
 }
 }
 return changeList;
 }
</code></pre>

If I have a method

<pre><code> public ArrayList&lt;String&gt; necessaryChanges(Set&lt;Object&gt; setToCheck ) {

 //checks to see whether each element of set is correct by comparing it to something
 // and if it needs to be changed its added to an arraylist to be returned to the user

 }
</code></pre>

I need to return a list with necessary changes which is fine.

But I also want to modify setToCheck with the changes. I know you cant return two objects in a method.
What I am asking is what is the most efficient way of doing this.

I know I can create another method in the main class and call it to change the set, but it seems really inefficient.

Is there a better way of doing this.

Thanks

Return Two Arraylists or Use Two Different Methods

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如果我有办法 public ArrayList<String> necessaryChanges(Set<Object> setToCheck ) { //checks to see whether each element of set is correct by comparing it to something ...

问返回两个数组列表或使用两个不同的方法
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