我试图使用以下代码添加两个矩阵:
#include <stdio.h>
int matrix (void)
{
int a[2][2];
int b[2][2];
int c[2][2];
int i, j;
for (i = 0; i < 2; ++i) {
for (j = 0; j < 2; ++j) {
scanf("%d", &a[i][j]);
}
}
for (i = 0; i < 2; ++i) {
for (j = 0; j < 2; ++j) {
scanf("%d", &b[i][j]);
}
}
for (i = 0; i < 2; ++i) {
for (j = 0; j < 2; ++j) {
c[i][j] = a[i][j] + b[i][j];
}
}
return c;
}
int main ()
{
int i, j;
int c[2][2];
c = matrix();
for (i = 0; i < 2; ++i) {
for (j = 0; j < 2; ++j) {
printf("%d", c[i][j]);
}
printf("\n");
}
return 0;
}
上面的代码抛出了许多错误。请解释为什么我的编译器会显示这么多错误。
编辑-我在编译上面的代码时使用了GCC 4.4.3。
EDIT2 --在编译上面的代码时,我收到了以下错误和警告。
test.c: In function ‘matrix’:
test.c:23: warning: return makes integer from pointer without a cast
test.c:23: warning: function returns address of local variable
test.c: In function ‘main’:
test.c:29: error: incompatible types when assigning to type ‘int[2][2]’ from type ‘int’
发布于 2014-09-01 15:15:44
按你想要的做吧。
#include <stdio.h>
int (*matrix(void))[2]{//return pointer as int (*)[2]
static int c[2][2];//Can not be used to return the automatic local variables.
int a[2][2];
int b[2][2];
int i, j;
for (i = 0; i < 2; ++i) {
for (j = 0; j < 2; ++j) {
scanf("%d", &a[i][j]);
}
}
for (i = 0; i < 2; ++i) {
for (j = 0; j < 2; ++j) {
scanf("%d", &b[i][j]);
}
}
for (i = 0; i < 2; ++i) {
for (j = 0; j < 2; ++j) {
c[i][j] = a[i][j] + b[i][j];
}
}
return c;
}
int main (){
int i, j;
int (*c)[2];
c = matrix();
for (i = 0; i < 2; ++i) {
for (j = 0; j < 2; ++j) {
printf("%d ", c[i][j]);//remove &
}
printf("\n");
}
return 0;
}
发布于 2014-09-01 15:06:18
首先,matrix
返回一个int
的本地数组,但声明它返回一个int
值。
发布于 2014-09-01 15:17:13
试试这个固定的代码:
#include <stdio.h>
void matrix (int c[][2]) //Fix 1
{
int a[2][2];
int b[2][2];
int i, j;
for (i = 0; i < 2; ++i) {
for (j = 0; j < 2; ++j) {
scanf("%d", &a[i][j]);
}
}
for (i = 0; i < 2; ++i) {
for (j = 0; j < 2; ++j) {
scanf("%d", &b[i][j]);
}
}
for (i = 0; i < 2; ++i) {
for (j = 0; j < 2; ++j) {
c[i][j] = a[i][j] + b[i][j];
}
}
}
int main ()
{
int i, j;
int c[2][2];
matrix(c); //Fix 2
for (i = 0; i < 2; ++i) {
for (j = 0; j < 2; ++j) {
printf("%d\t", c[i][j]); //Fix 3
}
printf("\n");
}
return 0;
}
https://stackoverflow.com/questions/25608613
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