blocks|key|368948|text|当呼叫1的开始或结束在呼叫2的开始和结束之间时，两个呼叫重叠。(不管你称之为“呼叫1”和“呼叫2”两个呼叫中的哪一个。)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|368949|WHERE+
(
++call1.start+BETWEEN+call2.start+AND+call2.end
++OR
++call1.end+BETWEEN+call2.start+AND+call2.end
)|code-block|syntax|javascript|368950|编辑:如果你考虑两个电话，其中一个同时结束，另一个开始重叠或不重叠，那就做好决定吧。中间条款是这样的。因此，如果您不想这样做，请用(call1.start+>+call2.start+AND+call1.start+<+call2.end)替换它。|offset|length|style|CODE|368951|编辑:查找所有重叠的呼叫组合：|368952|select+*+
from+calls
join+calls+other+
++on+other.callid+<+calls.callid+and+
++(
++++(calls.timeans+>+other.timeans+and+calls.timeans+<+other.timefin)
++++or
++++(calls.timefin+>+other.timeans+and+calls.timeans+<+other.timefin)
++)
;|368953|entityMap^0|0|0|1T|1J|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

Two calls overlap when start or end of call 1 is between start and end of call 2. (No matter, which of the two calls you call "call 1" and which "call 2".)

<pre><code>WHERE 
(
 call1.start BETWEEN call2.start AND call2.end
 OR
 call1.end BETWEEN call2.start AND call2.end
)
</code></pre>

EDIT: And make your mind up, if you consider two calls where one ends at the same time as the other starts overlapping or not. The BETWEEN clause does. So if you don't want this, replace this by <code>(call1.start &gt; call2.start AND call1.start &lt; call2.end)</code>.

EDIT: To find all overlapping call combinations:

<pre><code>select * 
from calls
join calls other 
 on other.callid &lt; calls.callid and 
 (
 (calls.timeans &gt; other.timeans and calls.timeans &lt; other.timefin)
 or
 (calls.timefin &gt; other.timeans and calls.timeans &lt; other.timefin)
 )
;
</code></pre>

blocks|key|1608603|text|在两个调用重叠的同一表上加入：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1608604|SELECT+*+FROM+TABLE
JOIN+TABLE+t2+on+t2.CallID+!=+TABLE.CallID+and+
++++(CallID.TimeFin+BETWEEN+t2.TimeAns+AND+t2.TimeFin
++++OR+CallID.TimeAns+BETWEEN+t2.TimeAns+AND+t2.TimeFin)|code-block|syntax|javascript|1608605|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Join on the same table where the two calls overlap:

<pre><code>SELECT * FROM TABLE
JOIN TABLE t2 on t2.CallID != TABLE.CallID and 
 (CallID.TimeFin BETWEEN t2.TimeAns AND t2.TimeFin
 OR CallID.TimeAns BETWEEN t2.TimeAns AND t2.TimeFin)
</code></pre>

blocks|key|369024|text|参考在这里工作ORACLE+Fiddle|type|unordered-list-item|depth|inlineStyleRanges|entityRanges|offset|length|data|369025|参考在这里工作SQL+SERVER+Fiddle|369026|查询应该可以帮助您：|unstyled|369027|SELECT+A.callID+,
A.startTime+OVERLAPPING_START_TIME,+
A.endTime+OVERLAPPING_END_TIME
++++FROM+phoneCall+A+
+++++++++LEFT+OUTER+JOIN+
+++++++++phoneCall+B+
+++ON+A.callID+!=+B.callID
WHERE
++++++((B.startTime)+BETWEEN+(A.STARTTIME)+AND+(A.endTime+))
OR+
++++++((B.endTime+)+BETWEEN+(A.STARTTIME)+AND+(A.endTime+))|code-block|syntax|javascript|369028|entityMap|0|LINK|mutability|MUTABLE|url|http://sqlfiddle.com/#!4/4989d8/1|1|http://sqlfiddle.com/#!6/25df7/1^0|2|I|0|0|2|M|1|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@$A|Y|B|Z|1|10]]|C|$]]|$1|D|3|E|5|6|7|11|8|@]|9|@$A|12|B|13|1|14]]|C|$]]|$1|F|3|G|5|H|7|15|8|@]|9|@]|C|$]]|$1|I|3|J|5|K|7|16|8|@]|9|@]|C|$L|M]]|$1|N|3|-4|5|H|7|17|8|@]|9|@]|C|$]]]|O|$P|$5|Q|R|S|C|$T|U]]|V|$5|Q|R|S|C|$T|W]]]]

<ul>
<li>Refer <a href="http://sqlfiddle.com/#!4/4989d8/1" rel="nofollow"> Working ORACLE Fiddle Here</a>:</li>
<li>Refer <a href="http://sqlfiddle.com/#!6/25df7/1" rel="nofollow"> Working SQL SERVER Fiddle Here</a>:</li>
</ul>

The Query should help you:

<pre><code>SELECT A.callID ,
A.startTime OVERLAPPING_START_TIME, 
A.endTime OVERLAPPING_END_TIME
 FROM phoneCall A 
 LEFT OUTER JOIN 
 phoneCall B 
 ON A.callID != B.callID
WHERE
 ((B.startTime) BETWEEN (A.STARTTIME) AND (A.endTime ))
OR 
 ((B.endTime ) BETWEEN (A.STARTTIME) AND (A.endTime ))
</code></pre>

blocks|key|369090|text|以下是不包括在内的查询：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|369091|SELECT+*+FROM+myCalls+t1
INNER+JOIN+myCalls+t2+on+t2.CallID+!=+t1.CallID+
++++AND+t1.TimeAns+<+t2.TimeFin
++++AND+t1.TimeFin+>++t2.TimeAns+|code-block|syntax|javascript|369092|此查询将为每个重叠返回2行。如果您希望每个重叠只包含一行，这将完成以下操作：|369093|SELECT+*+FROM+myCalls+t1
INNER+JOIN+myCalls+t2+on+t2.CallID+>+t1.CallID+
++++AND+t1.TimeAns+<+t2.TimeFin
++++AND+t1.TimeFin+>++t2.TimeAns+|369094|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Here is non-inclusive query:

<pre><code>SELECT * FROM myCalls t1
INNER JOIN myCalls t2 on t2.CallID != t1.CallID 
 AND t1.TimeAns &lt; t2.TimeFin
 AND t1.TimeFin &gt; t2.TimeAns 
</code></pre>

This query will return 2 rows for each overlap. if you want to have just one row per overlap this will do it:

<pre><code>SELECT * FROM myCalls t1
INNER JOIN myCalls t2 on t2.CallID &gt; t1.CallID 
 AND t1.TimeAns &lt; t2.TimeFin
 AND t1.TimeFin &gt; t2.TimeAns 
</code></pre>

Is there a way to work out if a call overlaps another call already in progress.

For example I have a call that comes in at <code>10:00</code> and ends at <code>10:05</code>.

Second call comes in at <code>10:02</code> and ends at <code>10:06</code> so is overlapping the first calls, how could I show this in a sql query? I have a few thousand calls to compare.

Table I have uses <code>CallID, TimeAns, TimeFin</code>

Any suggestions welcome.

Overlapping call durations

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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是否有办法计算一个呼叫是否与另一个正在进行的呼叫重叠。例如，我有一个电话在10:00打进来，最后打到10:05。第二个调用来自10:02，结束于10:06，所以第一个调用是重叠的，我如何在一个sql查询中显示这一点？我有几千个电话要比较。表我使用了CallID, TimeAns, TimeFin欢迎任何建议。

问重叠呼叫持续时间
EN

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问重叠呼叫持续时间EN