我试图通过WebApi方法将XML反序列化为对象。
我有以下课程:
[XmlRoot(IsNullable = false)]
public class MyObject
{
[XmlElement("Name")]
public string Name {get;set;}
}以及WebApi控制器中的下列方法。
[HttpPost]
public HttpResponseMessage UpdateMyObject(MyObject model)
{
//do something with the model
}在网络项目的启动过程中,我通过设置以下内容来使用XmlSerializer:
config.Formatters.XmlFormatter.UseXmlSerializer = true;当我发布以下XML时,model被正确地反序列化,并且我可以读取它的属性。
<?xml version="1.0" encoding="UTF-8"?>
<MyObject>
<Name>HelloWorld</Name>
</MyObject>但是,当我发布带有DOCTYPE声明的XML时,model值为null,而且似乎没有在方法条目上反序列化。也就是说,这个XML没有反序列化为一个模型:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE MyObject SYSTEM "http://example.com/MyObject.dtd">
<MyObject>
<Name>HelloWorld</Name>
</MyObject>希望有人能帮忙。
发布于 2015-04-15 13:51:35
即使是个老职位,我也发现自己也处于同样的境地。最后,我编写了一个XmlMediaTypeFormatter的自定义版本,覆盖了ReadFromStreamAsync方法。
在这里,我的个人解决方案:
public class CustomXmlMediaTypeFormatter : XmlMediaTypeFormatter
{
/// <summary>
/// Initializes a new instance of the <see cref="CustomXmlMediaTypeFormatter"/> class.
/// This XmlMediaTypeFormatter will ignore the doctype while reading the provided stream.
/// </summary>
public CustomXmlMediaTypeFormatter()
{
UseXmlSerializer = true;
}
public override Task<object> ReadFromStreamAsync(Type type, Stream readStream, HttpContent content, IFormatterLogger formatterLogger)
{
if (type == null)
throw new ArgumentNullException("type");
if (readStream == null)
throw new ArgumentNullException("readStream");
try
{
return Task.FromResult(ReadFromStream(type, readStream, content, formatterLogger));
}
catch (Exception ex)
{
var completionSource = new TaskCompletionSource<object>();
completionSource.SetException(ex);
return completionSource.Task;
}
}
private object ReadFromStream(Type type, Stream readStream, HttpContent content, IFormatterLogger formatterLogger)
{
var httpContentHeaders = content == null ? (HttpContentHeaders)null : content.Headers;
if (httpContentHeaders != null)
{
var contentLength = httpContentHeaders.ContentLength;
if ((contentLength.GetValueOrDefault() != 0L ? 0 : (contentLength.HasValue ? 1 : 0)) != 0)
return GetDefaultValueForType(type);
}
var settings = new XmlReaderSettings
{
DtdProcessing = DtdProcessing.Ignore
};
var deserializer = GetDeserializer(type, content);
try
{
// The standard XmlMediaTypeFormatter will get the encoding from the HttpContent, instead
// here the XmlReader will decide by itself according to the content
using (var xmlReader = XmlReader.Create(readStream, settings))
{
var xmlSerializer = deserializer as XmlSerializer;
if (xmlSerializer != null)
return xmlSerializer.Deserialize(xmlReader);
var objectSerializer = deserializer as XmlObjectSerializer;
if (objectSerializer == null)
throw new InvalidOperationException("xml object deserializer not available");
return objectSerializer.ReadObject(xmlReader);
}
}
catch (Exception ex)
{
if (formatterLogger == null)
{
throw;
}
formatterLogger.LogError(string.Empty, ex);
return GetDefaultValueForType(type);
}
}
}显然,我已经替换了配置的标准XmlFormatter:
config.Formatters.Remove(config.Formatters.XmlFormatter);
config.Formatters.Add(new CustomXmlMediaTypeFormatter());发布于 2014-10-07 04:59:30
我还没有尝试过DOCTYPEs,但是实现IXmlSerializable接口应该可以让您完全控制XmlSerializer对对象序列化的控制。
IXmlSerializable接口
https://stackoverflow.com/questions/26228371
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