我正在使用asmack库作为我的聊天应用程序,在成功登录后使用下面描述的代码获取Muc房信息:
MultiUserChat mMultiUserChat =新MultiUserChat(连接,"VjNewMoiosandroid@conference.chat");mMultiUserChat.join(用户名);尝试{ if (mMultiUserChat.isJoined()==true) { RoomInfo MultiUserChat“VjNewMoiosandroid@conference.chat”;} catch (异常e) { // TODO:处理异常e.printStackTrace();}
当我得到房间信息时,当我调试和检查我在日志中得到房间信息时,我得到了这个错误,但是在roomInfo中什么都没有。
10-10 08:55:12.388: W/System.err(1821):org.jivesoftware.smack.util.PacketParserUtils$2 : java.lang.ClassCastException: java.lang.ClassCastException不能投给org.jivesoftware.smackx.packet.DiscoverInfo 10-10 08:55:12.428: W/System.err(1821):at org.jivesoftware.smackx.ServiceDiscoveryManager.discoverInfo(ServiceDiscoveryManager.java:600) 10-10 08:55:12.458: W/System.err(1821):at org.jivesoftware.smackx。ServiceDiscoveryManager.discoverInfo(ServiceDiscoveryManager.java:552) 10-1008:55:12.478: W/System.err(1821):at com.demo.xmppchat.CopyOfXMPPChatDemoActivity.getRoomInfo(CopyOfXMPPChatDemoActivity.java:469)
我在日志中收到的聊天室信息
10-10 15:38:10.133: D/SMACK(26035): 03:38:10 PM RCV (1107887640): <iq
from='VjNewMoiosandroid@conference.chat' to='14393671556301070000@chat/Smack'
id='VWaeO-6' type='result'><query xmlns='http://jabber.org/protocol/disco#info'><identity
category='conference' type='text' name='VjNewMoiosandroid'/><feature var='
http://jabber.org/protocol/muc'/><feature var='muc_public'/><feature
var='muc_persistent'/><feature var='muc_open'/><feature var='muc_semianonymous'/><feature
var='muc_moderated'/><feature var='muc_unsecured'/><x xmlns='jabber:x:data'
type='result'><field type='hidden' var='FORM_TYPE'><value>
http://jabber.org/protocol/muc#roominfo</value></field><field label='Room description'
var='muc#roominfo_description'><value></value></field><field label='Number of occupants'
var='muc#roominfo_occupants'><value>1</value></field></x></query></iq>
发布于 2014-10-10 10:30:54
我使用的是老的asmack jar,这是我的问题,我做了一些更改,我在类中直接使用了MultiUserChat类getRoomInfo()方法
MultiUserChat mMultiUserChat =新MultiUserChat(连接,"VjNewMoiosandroid@conference.chat");mMultiUserChat.join(用户名);尝试{ if (mMultiUserChat.isJoined()==true) { String roomInfo=getRoomInfo(连接,"VjNewMoiosandroid@conference.chat");} catch (异常e) { // TODO:处理异常e.printStackTrace();}
我做了一个方法如下
公共静态字符串getRoomInfo(连接连接,字符串空间)抛出XMPPException { String roomInfo=“;尝试{ ServiceDiscoveryManager serviceDiscoveryManager=new ServiceDiscoveryManager( connection );DiscoverInfo info = serviceDiscoveryManager.discoverInfo( room);roomInfo=info.toXML();} catch (XMPPException e) { // TODO:处理异常Log.e("xmpp",e.toString());}返回roomInfo;}
发布于 2014-10-10 09:30:22
这样做
替换这一行
RoomInfo roomInfo=mMultiUserChat.getRoomInfo(connection,"VjNewMoiosandroid@conference.chat");
有了这个
RoomInfo roomInfo=MultiUserChat.getRoomInfo(connection,"VjNewMoiosandroid@conference.chat");
https://stackoverflow.com/questions/26295888
复制相似问题