blocks|key|2165441|text|也许您应该看看join.me是如何制作的：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2165442|在第一台机器上启动可观察的。|unordered-list-item|2165443|这将连接到中央服务器，并接收将显示给用户的唯一id+(票证)。|2165444|2165445|​|2165446|在第二台机器上启动观察者。|2165447|它还连接到中央服务器，并等待输入要连接到的所需id。|2165448|2165449|2165450|现在，可观察机器上的用户必须通过不同的通道(例如电话)将id传递给观察者。|2165451|在观测器上，输入票号，服务器可以发送两台机器的ip地址和端口，它们的孔穿孔在其中进行。如果一个直接连接是可能的，中央服务器已经完成其工作，否则双方将发送他们的数据到服务器，并从他们的另一个客户端。|2165452|因此，要确保正确的客户端连接，只需创建一个唯一的id，双方必须通过不同的通信渠道共享。|2165453|entityMap|0|LINK|mutability|MUTABLE|url|https://www.join.me/^0|7|7|0|0|1|1|0|0|1|1|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|15|8|@]|9|@$A|16|B|17|1|18]]|C|$]]|$1|D|3|E|5|F|7|19|8|@]|9|@]|C|$]]|$1|G|3|H|5|F|7|1A|8|@]|9|@]|C|$]]|$1|I|3|-4|5|6|7|1B|8|@]|9|@]|C|$]]|$1|J|3|K|5|6|7|1C|8|@]|9|@]|C|$]]|$1|L|3|M|5|F|7|1D|8|@]|9|@]|C|$]]|$1|N|3|O|5|F|7|1E|8|@]|9|@]|C|$]]|$1|P|3|-4|5|6|7|1F|8|@]|9|@]|C|$]]|$1|Q|3|K|5|6|7|1G|8|@]|9|@]|C|$]]|$1|R|3|S|5|F|7|1H|8|@]|9|@]|C|$]]|$1|T|3|U|5|F|7|1I|8|@]|9|@]|C|$]]|$1|V|3|W|5|6|7|1J|8|@]|9|@]|C|$]]|$1|X|3|-4|5|6|7|1K|8|@]|9|@]|C|$]]]|Y|$Z|$5|10|11|12|C|$13|14]]]]

Maybe you should take a look on how <a href="https://www.join.me" rel="nofollow">join.me</a> makes it:

<ul>
<li>On first machine start the Observable.
<ul>
<li>This connects to the central server and receives a unique id (ticket) that will be shown to the user.</li>
</ul></li>
<li>On the second machine start the Observer.
<ul>
<li>This connects also to the central server and awaits an entering of the desired id to connect to.</li>
</ul></li>
<li>Now the user on the observable machine has to communicate the id to the observer guy through a different channel (e.g. phone).</li>
<li>On the observer the ticket number is entered and the server can send both machines the ip address and port of each other where their did the hole punching. If a direct connect is possible, the central server has finished its work, otherwise both sides will send their data to the server and from their to the other client.</li>
</ul>

So to ensure that the correct clients are connected simply create a unique id which both sides have to share through a different communication channel.

blocks|key|919679|text|我认为以下内容应该足以查看正确的客户端是否已连接到您的服务器：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|919680|创建一个TCPListener并开始同步或异步地接受连接。我正在使用来自MSDN：http://msdn.microsoft.com/en-us/library/system.net.sockets.tcplistener.accepttcpclient(v=vs.110).aspx的同步示例|ordered-list-item|offset|length|919681|当客户端连接时，创建一个流来读取客户端发送的数据，如下所示：
NetworkStream流=+client.GetStream()；i=stream.Read(字节，0，bytes.Length)；|919682|将消息从字节反序列化为字符串，并检查它是否匹配您期望的唯一ID：|919683|`|919684|data+=+System.Text.Encoding.ASCII.GetString(bytes,+0,+i);
//There+are,+of+course,+better+ways+of+doing+this.
if(data.Equals("HandshakeId")
{
//start+receiving/sending+data+in+a+loop
}
else
{
+//+Shutdown+and+end+connection
++client.Close();
}|code-block|syntax|javascript|919685|919686|一个更有趣的问题是如何捕捉您将要共享的实际屏幕。我个人已经在VS+C%2B%2B中做到了这一点，而且性能还不错。有几种方法可以做到这一点，即使用GDI%2B，使用DirectX或OpenGL，列表继续。|919687|我很好奇你打算用什么:)|919688|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/system.net.sockets.tcplistener.accepttcpclient(v=vs.110).aspx^0|0|15|2T|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|15|8|@]|9|@$E|16|F|17|1|18]]|A|$]]|$1|G|3|H|5|D|7|19|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|1A|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|1B|8|@]|9|@]|A|$]]|$1|M|3|N|5|O|7|1C|8|@]|9|@]|A|$P|Q]]|$1|R|3|L|5|6|7|1D|8|@]|9|@]|A|$]]|$1|S|3|T|5|6|7|1E|8|@]|9|@]|A|$]]|$1|U|3|V|5|6|7|1F|8|@]|9|@]|A|$]]|$1|W|3|-4|5|6|7|1G|8|@]|9|@]|A|$]]]|X|$Y|$5|Z|10|11|A|$12|13]]]]

I think the following should be enough to see if the correct client has connected to your server:

<ol>
<li>Create a TCPListener and start accepting connections either synchronously or async. I'm using the synchronous example from MSDN: <a href="http://msdn.microsoft.com/en-us/library/system.net.sockets.tcplistener.accepttcpclient(v=vs.110).aspx" rel="nofollow">http://msdn.microsoft.com/en-us/library/system.net.sockets.tcplistener.accepttcpclient(v=vs.110).aspx</a></li>
<li>When a client connects, create a stream to read data sent by the client like this: 

NetworkStream stream = client.GetStream();
i = stream.Read(bytes, 0, bytes.Length);</li>
<li>Deserialize the message from bytes to string and check if it, for example, matches a unique ID that you are expecting:</li>
</ol>

`

<pre><code>data = System.Text.Encoding.ASCII.GetString(bytes, 0, i);
//There are, of course, better ways of doing this.
if(data.Equals("HandshakeId")
{
//start receiving/sending data in a loop
}
else
{
 // Shutdown and end connection
 client.Close();
}
</code></pre>

`

A more interesting question is how to capture the actual screen you'll be sharing. I personally have done this in VS C++, and the performance was okay. There are several ways to do it, i.e. using GDI+, using DirectX or OpenGL, the list goes on..

I'm curious as to what are you planing to use :)

I'm creating a screen sharing application. To allow for nat traversal I'm having to do this through a server, I'm just wondering how I can check that the client trying to connect to the server is the one I want to connect and not someone else, whilst not actually blocking other people from being able to connect to that port.

I'm thinking of using BeginAcceptTcpClient() instead of AcceptTcpClient() is there a way to check who is trying to connect before it accepts the connection this way so it can be picked up by the TcpListener later?

The only other thing I can of is to send the ID of the person I want to send the image to in the connection and let the server handle who to send it to but would that be too slow or resource intensive?

Listen for certain IP address and port with tcplistener

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在创建一个屏幕共享应用程序。为了允许nat穿越，我不得不通过服务器来实现这一点，我只是想知道如何才能检查试图连接到服务器的客户端是我想连接的客户端，而不是其他人，而不是阻止其他人连接到该端口。我正在考虑使用BeginAcceptTcpClient()而不是AcceptTcpClient()，在它以这种方式接受连接之...

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