blocks|key|1135335|text|尝试在.sort()调用！看看这里的文件。中使用自定义的比较函数|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1135336|在这个例子中(可能不是最好的方法)，我会：|1135337|有未排序的“计数”数组|ordered-list-item|1135338|有未排序的字阵列|1135339|对单词数组进行排序(使用下面描述的自定义函数)|1135340|对计数数组进行排序(没有自定义函数)|1135341|自定义比较函数可能是一个简单的查找，并返回未排序计数数组中的相应值。(即，如果单词"a“为第0索引，且其相关计数量位于计数数组的第0索引中，则返回计数)|1135342|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort^0|D|8|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|6|7|12|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|13|8|@]|9|@]|C|$]]|$1|I|3|J|5|H|7|14|8|@]|9|@]|C|$]]|$1|K|3|L|5|H|7|15|8|@]|9|@]|C|$]]|$1|M|3|N|5|H|7|16|8|@]|9|@]|C|$]]|$1|O|3|P|5|6|7|17|8|@]|9|@]|C|$]]|$1|Q|3|-4|5|6|7|18|8|@]|9|@]|C|$]]]|R|$S|$5|T|U|V|C|$W|X]]]]

Try using a custom compare function with your .sort() call! <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort" rel="nofollow">Check out the documentation here.</a>

I would, in this example (probably not the best way):

<ol>
<li>Have the unsorted "count" array</li>
<li>Have the unsorted word array</li>
<li>Sort the word array (with a custom function described below)</li>
<li>Sort the count array (no custom function)</li>
</ol>

The custom compare function would probably be a simple lookup and return the corresponding value in the unsorted count array. (i.e. if the word "a" is 0th index and its relevant count amount is in the 0th index of the count array, return count[0])

blocks|key|1358781|text|这将创建一个对象数组，然后按计数排序。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1358782|var+hashtags+=+{},
++++counts+=+[];

for+(var+i+in+data)
{
++++if(data[i].lang+==+"en")
++++{+++
++++++++for+(var+j+in+data[i].entities.hashtags)
++++++++{
++++++++++++var+text+=+data[i].entities.hashtags[j].text;

++++++++++++if(text)+{
++++++++++++++++if(hashtags[text])+{
+++++++++++++++++++++hashtags[text].data[0]%2B%2B;
++++++++++++++++}+else+{
+++++++++++++++++++++hashtags[text]+=+{
+++++++++++++++++++++++++name:+text,
+++++++++++++++++++++++++data:+[1]
+++++++++++++++++++++};
+++++++++++++++++++++counts.push(hashtags[text]);
++++++++++++++++}
++++++++++++}
++++++++}
++++}
}

counts.sort(function(a,+b)+{+return+b.data[0]+-+a.data[0];+});|code-block|syntax|javascript|1358783|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This will create an array of objects that are then sorted by count.

<pre><code>var hashtags = {},
 counts = [];

for (var i in data)
{
 if(data[i].lang == "en")
 { 
 for (var j in data[i].entities.hashtags)
 {
 var text = data[i].entities.hashtags[j].text;

 if(text) {
 if(hashtags[text]) {
 hashtags[text].data[0]++;
 } else {
 hashtags[text] = {
 name: text,
 data: [1]
 };
 counts.push(hashtags[text]);
 }
 }
 }
 }
}

counts.sort(function(a, b) { return b.data[0] - a.data[0]; });
</code></pre>

blocks|key|2595382|text|简单-不要使用两个数组，而是一个集合，每个元素都是一个对象|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2595383|我从这篇文章中学到了一些基本知识：按属性值对JavaScript对象进行排序|offset|length|2595384|并完成了演示：|2595385|var+collection+=+{car:300,+bike:60,+motorbike:200,+airplane:1000,+helicopter:400,+rocket:8*60*60}
var+sortable+=+[];
for+(var+item+in+collection)
++++++sortable.push([item,+collection[item]])
sortable.sort(function(a,+b)+{return+a[1]+-+b[1]})

collection+=+{};
for+(var+i+in+sortable)
{
++++collection[sortable[i][0]]+=+sortable[i][1];
}

console.log(collection);|code-block|syntax|javascript|2595386|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/1069666/sorting-javascript-object-by-property-value^0|0|H|L|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@$D|W|E|X|1|Y]]|A|$]]|$1|F|3|G|5|6|7|Z|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|10|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

Simple - don't use 2 arrays but one collection which every element is an object

I took the basics from this post: <a href="https://stackoverflow.com/questions/1069666/sorting-javascript-object-by-property-value">Sorting JavaScript Object by property value</a>

and completed the demo:

<pre><code>var collection = {car:300, bike:60, motorbike:200, airplane:1000, helicopter:400, rocket:8*60*60}
var sortable = [];
for (var item in collection)
 sortable.push([item, collection[item]])
sortable.sort(function(a, b) {return a[1] - b[1]})

collection = {};
for (var i in sortable)
{
 collection[sortable[i][0]] = sortable[i][1];
}

console.log(collection);
</code></pre>

blocks|key|1358813|text|如果不能使用对象，请尝试使用嵌套的for循环：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1358814|var+array1+=+['z',+'d',+'e',+'f',+'t'],+arr1Count+=+array1.length;
var+array2+=+[1,+12,+5,+7,+3];
var+sortedArray2+=+array2.sort(function(x,+y)+{return+y+-+x});

var+i,+j,+sortedArray1+=+[];

for+(i+=+0;+i+<+arr1Count;+i%2B%2B)+{
++++for+(j+=+0;+j+<+arr1Count;+j%2B%2B)+{
++++++++if+(array2[j]+===+sortedArray2[i])+sortedArray1.push(array1[j]);+//iterate+through+the+unsorted+numeric+array+(array2)+and+when+it+matches+the+sortedArray2,+push+this+index+of+array1+into+the+sortedArray1
++++}
}|code-block|syntax|javascript|1358815|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you cannot work with an object try using nested for loops:

<pre><code>var array1 = ['z', 'd', 'e', 'f', 't'], arr1Count = array1.length;
var array2 = [1, 12, 5, 7, 3];
var sortedArray2 = array2.sort(function(x, y) {return y - x});

var i, j, sortedArray1 = [];

for (i = 0; i &lt; arr1Count; i++) {
 for (j = 0; j &lt; arr1Count; j++) {
 if (array2[j] === sortedArray2[i]) sortedArray1.push(array1[j]); //iterate through the unsorted numeric array (array2) and when it matches the sortedArray2, push this index of array1 into the sortedArray1
 }
}
</code></pre>

I have two arrays. The first is for strings and the second is an array for their number of occurrences. 

I am trying to get the top 10 most occurrences of words in the first array. I sorted it but somehow I only sort it alphabetically and the second array respectively corresponds to their number of occurrences. 

How can I sort the second array from biggest to lowest and, at the same time, sort the first array that match the order of the second?

I'm having trouble inserting my json to my highcharts and I found out why, the numbers should be in square brackets [] I tried already inserting [] in 1 but still does not work please see my post I edit it

this is the data that i should insert in the highchart

<pre><code>[{"name":"#murrayftw","data":[46]},
 {"name":"#job","data":[37]},
 {"name":"#jobs","data":[25]},
 {"name":"#favnashvine","data":[16]},
 {"name":"#rollersmusicawards","data":[14]},
 {"name":"#soa","data":[13]},
 {"name":"#tweetmyjobs","data":[12]},
 {"name":"#sman1boyolangu","data":[12]},
 {"name":"#supernatural200thepisode","data":[12]},
 {"name":"#veteransday","data":[12]}]
</code></pre>

How do I sort one array by the corresponding values in another array?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有两个数组。第一个是字符串的数组，第二个是字符串出现次数的数组。我正试图在第一个数组中得到前10位最常见的单词。我对它进行了排序，但不知怎么的，我只按字母顺序排序，第二个数组分别对应于它们出现的次数。如何将第二个数组从最大排序到最低排序，同时对与第二个数组顺序匹配的第一个数组进行排序。我很难将我的json插入到我的高...

问如何根据另一个数组中的对应值对一个数组进行排序？
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问如何根据另一个数组中的对应值对一个数组进行排序？EN