我梦想“动态实例化案例类”--并根据每个字段类型为字段提供一些虚拟数据(稍后我将为此创建一些规则)。
到目前为止,我有一些与String;Long或Int .如果有可能处理嵌入式案例类的话,我会有点拘泥于此。
所以我可以实例化case class RequiredAPIResponse (stringValue: String, longValue: Long, intVlaue: Int)
但不是外星,外星在.
case class Inner (deep: String)
case class Outer (in : Inner)代码是
def fill[T <: Object]()(implicit mf: ClassTag[T]) : T = {
val declaredConstructors = mf.runtimeClass.getDeclaredConstructors
if (declaredConstructors.length != 1)
Logger.error(/*T.toString + */" has " + declaredConstructors.length + " constructors --- only 1 currently supported.")
val constructor = declaredConstructors.headOption.get
val m = constructor.getParameterTypes.map(p => {
Logger.info("getName " + p.getName +" --- getCanonicalName " + p.getCanonicalName)
Logger.info(p.getCanonicalName)
p.getCanonicalName match {
case "java.lang.String" => /*"Name"->*/ val s : java.lang.String = "DEFAULT STRING"
s
case "long" => /*"Name"-> */ val l : java.lang.Long = new java.lang.Long(99)
l
case "int" => /*"Name"->*/ val i : java.lang.Integer = new java.lang.Integer(99)
i
case _ => /*"Name"->*/
So around here I am stuck!
//THIS IS MADE UP :) But I want to get the "Type" and recursively call fill
//fill[p # Type] <- not real scala code
//I can get it to work in a hard coded manner
//fill[Inner]
}
})我觉得Scala: How to invoke method with type parameter and manifest without knowing the type at compile time?上的最后一个答案是一个答案的起点。所以,不是使用T <:Object;fill应该使用ClassTag还是TypeTag?
这段代码是从- How can I transform a Map to a case class in Scala?开始的,它提到了(正如Lift-Framework所提到的),我确实有liftweb源代码;但是到目前为止,还没有成功地解开它的所有秘密。
编辑--基于Imm的要点,我有下面的代码可以工作(对他的回答做一些小的更新)
def fillInner(cls: Class[_]) : Object = {
val declaredConstructors = cls.getDeclaredConstructors
if (declaredConstructors.length != 1)
Logger.error(/*T.toString + */ " has " + declaredConstructors.length + " constructors --- only 1 currently supported.")
val constructor = declaredConstructors.headOption.get
val m = constructor.getParameterTypes.map(p => {
Logger.info("getName " + p.getName + " --- getCanonicalName " + p.getCanonicalName)
Logger.info(p.getCanonicalName)
p.getCanonicalName match {
case "java.lang.String" => /*"Name"->*/ val s: java.lang.String = "DEFAULT STRING"
s
case "long" => /*"Name"-> */ val l: java.lang.Long = new java.lang.Long(99)
l
case "int" => /*"Name"->*/ val i: java.lang.Integer = new java.lang.Integer(99)
i
case _ => fillInner(p)
}
})
constructor.newInstance(m: _*).asInstanceOf[Object]
}
def fill[T](implicit mf: ClassTag[T]) : T = fillInner(mf.runtimeClass).asInstanceOf[T]谢谢,布伦特
发布于 2015-01-07 16:40:05
实际上,您并不是在使用ClassTag,而是Class[_],而且没有一个是typesafe (它只是Java反射),所以只需递归地传递Class[_]:
def fillInner(cls: Class[_]) : Any = {
val declaredConstructors = cls.getDeclaredConstructors
if (declaredConstructors.length != 1)
Logger.error(/*T.toString + */" has " + declaredConstructors.length + " constructors --- only 1 currently supported.")
val constructor = declaredConstructors.headOption.get
val m = constructor.getParameterTypes.map(p => {
Logger.info("getName " + p.getName +" --- getCanonicalName " + p.getCanonicalName)
Logger.info(p.getCanonicalName)
p.getCanonicalName match {
case "java.lang.String" => /*"Name"->*/ val s : java.lang.String = "DEFAULT STRING"
s
case "long" => /*"Name"-> */ val l : java.lang.Long = new java.lang.Long(99)
l
case "int" => /*"Name"->*/ val i : java.lang.Integer = new java.lang.Integer(99)
i
case _ => fillInner(p)
}
})
def fill[T: ClassTag]: T = fillInner(classOf[T].runtimeClass).asInstanceOf[T]但是,您可能可以以一种类型错误的方式完成您想要做的事情,也许可以使用无形状的:
trait Supplier[T] {
def supply: T
}
object Supplier[T] {
implicit val intSupplier = new Supplier[Int] {
def supply = 99
}
implicit val stringSupplier = ...
implicit val emptyHListSupplier = new Supplier[HNil] {
def supply = HNil
}
implicit def consHListSupplier[H, T <: HList](
implicit headSupplier: Supplier[H],
tailSupplier: Supplier[T]) = new Supplier[H :: T] {
def supply = headSupplier.supply :: tailSupplier.supply
}
}然后,通过隐式解析的魔力,您可以为任何递归的Supplier[(String :: HNil) :: Int :: HNil] (最终只包含有Suppliers的值)获得一个HList;您只需要更多的形状(在版本1或2中是不同的,而且已经有一段时间没有这样做了,所以我不记得具体情况)来在这些类和case类之间来回转换。
发布于 2018-08-25 23:06:33
如果您只在测试中使用它,最好的方法是使用Scala/Java反射。
与使用宏相比,它的优点是编译速度更快。与使用标量相关库相比,API具有更好的优点。
设置它有点牵扯到。下面是一个完整的工作代码,您可以将其复制到代码库中:
import scala.reflect.api
import scala.reflect.api.{TypeCreator, Universe}
import scala.reflect.runtime.universe._
object Maker {
val mirror = runtimeMirror(getClass.getClassLoader)
var makerRunNumber = 1
def apply[T: TypeTag]: T = {
val method = typeOf[T].companion.decl(TermName("apply")).asMethod
val params = method.paramLists.head
val args = params.map { param =>
makerRunNumber += 1
param.info match {
case t if t <:< typeOf[Enumeration#Value] => chooseEnumValue(convert(t).asInstanceOf[TypeTag[_ <: Enumeration]])
case t if t =:= typeOf[Int] => makerRunNumber
case t if t =:= typeOf[Long] => makerRunNumber
case t if t =:= typeOf[Date] => new Date(Time.now.inMillis)
case t if t <:< typeOf[Option[_]] => None
case t if t =:= typeOf[String] && param.name.decodedName.toString.toLowerCase.contains("email") => s"random-$arbitrary@give.asia"
case t if t =:= typeOf[String] => s"arbitrary-$makerRunNumber"
case t if t =:= typeOf[Boolean] => false
case t if t <:< typeOf[Seq[_]] => List.empty
case t if t <:< typeOf[Map[_, _]] => Map.empty
// Add more special cases here.
case t if isCaseClass(t) => apply(convert(t))
case t => throw new Exception(s"Maker doesn't support generating $t")
}
}
val obj = mirror.reflectModule(typeOf[T].typeSymbol.companion.asModule).instance
mirror.reflect(obj).reflectMethod(method)(args:_*).asInstanceOf[T]
}
def chooseEnumValue[E <: Enumeration: TypeTag]: E#Value = {
val parentType = typeOf[E].asInstanceOf[TypeRef].pre
val valuesMethod = parentType.baseType(typeOf[Enumeration].typeSymbol).decl(TermName("values")).asMethod
val obj = mirror.reflectModule(parentType.termSymbol.asModule).instance
mirror.reflect(obj).reflectMethod(valuesMethod)().asInstanceOf[E#ValueSet].head
}
def convert(tpe: Type): TypeTag[_] = {
TypeTag.apply(
runtimeMirror(getClass.getClassLoader),
new TypeCreator {
override def apply[U <: Universe with Singleton](m: api.Mirror[U]) = {
tpe.asInstanceOf[U # Type]
}
}
)
}
def isCaseClass(t: Type) = {
t.companion.decls.exists(_.name.decodedName.toString == "apply") &&
t.decls.exists(_.name.decodedName.toString == "copy")
}
}当你想使用它的时候,你可以打电话给:
val user = Maker[User]
val user2 = Maker[User].copy(email = "someemail@email.com")上面的代码生成任意和唯一的值。它们并不完全是随机的。API非常好。考虑到它使用反射,最好在测试中使用。
在这里阅读我们的博客全文:https://give.engineering/2018/08/24/instantiate-case-class-with-arbitrary-value.html
https://stackoverflow.com/questions/27823448
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