blocks|key|1505726|text|为你的问题找到答案/提示。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1505727|您必须以相反的顺序打印数组的内容。
对于(int+=+dblValues.length+-1;i+-+>=+0；i-){+System.out.println(dblValuesi)；}
对于乞丐来说，这是最基本的方法。他们是一些预先指定的图书馆来做这项工作。|ordered-list-item|1505728|您可以使用int+a+=+(int)+Math.round(doubleVar);|offset|length|style|CODE|1505729|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/6/docs/api/java/lang/Math.html#round(double)^0|0|0|5|10|5|10|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$]]|$1|E|3|F|5|D|7|U|8|@$G|V|H|W|I|J]]|9|@$G|X|H|Y|1|Z]]|A|$]]|$1|K|3|-4|5|6|7|10|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Find the answers/hints for your questions.

<ol>
<li>You have to print the content of the array in reverse order.

<pre><code>for (int i = dblValues.length -1;i &gt;= 0; i--) {
 System.out.println(dblValues[i]);
}
</code></pre>

This is the fundamental way for a begginer. They are some predifined libraries to do this job</li>
<li>You can use <a href="http://docs.oracle.com/javase/6/docs/api/java/lang/Math.html#round(double)" rel="nofollow"><code>int a = (int) Math.round(doubleVar);</code></a></li>
</ol>

blocks|key|209656|text|对于第二个问题:有一个Math.round()方法。然后，您需要在安全途径中将返回的long转换为int。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|209657|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/6/docs/api/java/lang/Math.html#round(double)()|1|https://stackoverflow.com/questions/1590831/safely-casting-long-to-int-in-java^0|B|C|0|X|4|1|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@$A|O|B|P|1|Q]|$A|R|B|S|1|T]]|C|$]]|$1|D|3|-4|5|6|7|U|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]|L|$5|G|H|I|C|$J|M]]]]

For your second question: there is a <a href="http://docs.oracle.com/javase/6/docs/api/java/lang/Math.html#round%28double%29()" rel="nofollow noreferrer">Math.round()</a> method. You'll then need to cast the returned long to int in a <a href="https://stackoverflow.com/questions/1590831/safely-casting-long-to-int-in-java">safe way</a>.

blocks|key|2023913|text|如果你不想按反序打印数字并自然排序，你可以将它们添加到一个列表中并排序。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2023914|如果你也不关心四舍五入，你可以投一个双倍|2023915|++++String+s+=+"4+3+2+1";
++++String[]+split+=+s.split("\\s%2B");
++++List<Integer>+numbers+=+new+LinkedList<>();

++++for+(String+toAdd+:+split)+{
++++++++numbers.add(Integer.parseInt(toAdd));
++++}+++++++

++++Collections.sort(numbers);++++++
++++System.out.println(numbers);

++++System.out.println((int)45.7654);|code-block|syntax|javascript|2023916|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

If you dont just want to print the numbers in reverse order and order them naturally you can add them to a list and sort them

If you also don't care about rounding you can just cast a double

<pre><code> String s = "4 3 2 1";
 String[] split = s.split("\\s+");
 List&lt;Integer&gt; numbers = new LinkedList&lt;&gt;();

 for (String toAdd : split) {
 numbers.add(Integer.parseInt(toAdd));
 } 

 Collections.sort(numbers); 
 System.out.println(numbers);

 System.out.println((int)45.7654);
</code></pre>

blocks|key|1505854|text|1.)循环从最后一个索引和打印在reverse+order中。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1505855|2.)使用Math.round()获取int部件|1505856|public+static+void+main(String[]+arg)+{
++++++++Scanner+input+=+new+Scanner(System.in);
++++++++System.out.println("Enter+4+float+values");
++++++++String+inputValues2+=+input.nextLine();
++++++++String[]+dblValues+=+inputValues2.split("\\s%2B");

++++++++System.out.println("Reverse+order");

++++++++for+(int+i+=+dblValues.length+-+1+;+i+>=+0+;+i--)+{
++++++++++++System.out.println(dblValues[i]);
++++++++}

++++++++System.out.println("int+part+");

++++++++for+(String+s+:+dblValues)+{
++++++++++++int+a+=+Math.round(new+Float(s));
++++++++++++System.out.println(a);
++++++++}
++++}|code-block|syntax|javascript|1505857|输出|BOLD|1505858|Enter+4+float+values
12.4+23.5+34.5+45.3
Reverse+order
45.3
34.5
23.5
12.4
int+part+
12
24
35
45|1505859|entityMap^0|G|D|0|5|C|0|0|0|2|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|Z|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|10|8|@$9|11|A|12|B|O]]|D|@]|E|$]]|$1|P|3|Q|5|J|7|13|8|@]|D|@]|E|$K|L]]|$1|R|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|S|$]]

1.) loop from last index and print in <code>reverse order</code>.

2.) Use <code>Math.round()</code> for getting int part

<pre><code>public static void main(String[] arg) {
 Scanner input = new Scanner(System.in);
 System.out.println("Enter 4 float values");
 String inputValues2 = input.nextLine();
 String[] dblValues = inputValues2.split("\\s+");

 System.out.println("Reverse order");

 for (int i = dblValues.length - 1 ; i &gt;= 0 ; i--) {
 System.out.println(dblValues[i]);
 }

 System.out.println("int part ");

 for (String s : dblValues) {
 int a = Math.round(new Float(s));
 System.out.println(a);
 }
 }
</code></pre>

output

<pre><code>Enter 4 float values
12.4 23.5 34.5 45.3
Reverse order
45.3
34.5
23.5
12.4
int part 
12
24
35
45
</code></pre>

First question: I am trying to print out four double values in reverse order so if the user enters "1 2 3 4" I want it to print out "4 3 2 1" Here is my coding.

<pre><code>// User enters 4 float values here
System.out.println("Enter 4 float values");
inputValues2 = input.readLine();
String[] dblValues = inputValues2.split("\\s+");
</code></pre>

Second Question: I want to print out the integer portion of a double value. I guess I am trying to convert the double value to an int. I have tried these two different ways and get errors for both of them. Any ideas?? Maybe I should just do some sort of rounding to a whole number??

<pre><code>int dblConvert = dblAverage.intValue(); // One way
int dblConvert = Integer.parseInt(dblAverage); // Second way
</code></pre>

2 Simple Java questions

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

第一个问题:我试图按反向顺序打印出四个双值，所以如果用户输入“12，3，4”，我希望它打印出"4，3，2，1“，这是我的编码。// User enters 4 float values hereSystem.out.println("Enter 4 float values");inputValues2 = input...

问2个简单Java问题
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问2个简单Java问题EN