我正在编写一个PHP脚本,它接受XML输入,解析它,然后显示(最终是旋转的)矩形和椭圆区域。
因为区域可以旋转,所以我必须使用google.maps.Polygon而不是Rectangle。
为了处理旋转,我希望使用谷歌-地图-多边形-旋转库(这部分稍后来)。
我的问题是:从给定的XML输入中,我只知道矩形中心点的坐标和区域的尺寸(宽度和高度)。
目前,我只是将中心点显示为一个标记:

我的问题是:当只知道中心点的纬度和经度以及宽度、高度时,如何用google.maps.Polygon绘制矩形?
即如何计算四个端点的纬度和经度?
我可以在这里使用google.maps.geometry.spherical.computeOffset()方法吗?
发布于 2015-02-02 19:04:01
一种选择是使用v3移植版本的迈克·威廉姆斯的v2图形库
// ==- Tilted rectangles ===
var point = new google.maps.LatLng(44, -78);
var tiltedRectangle1 = google.maps.Polygon.Shape(point, 50000, 10000, 50000, 10000, -60, 4, "#000000", 3, 1, "#ffffff", 1, {}, true);
var tiltedRectangle2 = google.maps.Polyline.Shape(point, 50000, 10000, 50000, 10000, 30, 4, "#000000", 3, 1, {}, true);
tiltedRectangle1.setMap(map);
tiltedRectangle2.setMap(map);函数google.maps.Polygon.Shape(点,50000,10000,50000,10000,-60 )定义了边为100000米x 20000米的矩形,旋转了-60度,第二次调用定义了同样大小的矩形,旋转了30度。
工作小提琴
工作片段:
var map = null;
function initialize() {
var myOptions = {
zoom: 8,
center: new google.maps.LatLng(44, -78),
mapTypeControl: true,
mapTypeControlOptions: {
style: google.maps.MapTypeControlStyle.DROPDOWN_MENU
},
navigationControl: true,
mapTypeId: google.maps.MapTypeId.ROADMAP
}
map = new google.maps.Map(document.getElementById("map"),
myOptions);
// ==- Tilted rectangles ===
var point = new google.maps.LatLng(44, -78);
var tiltedRectangle1 = google.maps.Polygon.Shape(point, 50000, 10000, 50000, 10000, -60, 4, "#000000", 3, 1, "#ffffff", 1, {}, true);
var tiltedRectangle2 = google.maps.Polyline.Shape(point, 50000, 10000, 50000, 10000, 30, 4, "#000000", 3, 1, {}, true);
tiltedRectangle1.setMap(map);
tiltedRectangle2.setMap(map);
}
google.maps.event.addDomListener(window, 'load', initialize);
// EShapes.js
//
// Based on an idea, and some lines of code, by "thetoy"
//
// This Javascript is provided by Mike Williams
// Community Church Javascript Team
// http://www.bisphamchurch.org.uk/
// http://econym.org.uk/gmap/
//
// This work is licenced under a Creative Commons Licence
// http://creativecommons.org/licenses/by/2.0/uk/
//
// Version 0.0 04/Apr/2008 Not quite finished yet
// Version 1.0 10/Apr/2008 Initial release
// Version 3.0 12/Oct/2011 Ported to v3 by Lawrence Ross
google.maps.Polyline.Shape = function (point, r1, r2, r3, r4, rotation, vertexCount, colour, weight, opacity, opts, tilt) {
if (!colour) {
colour = "#0000FF";
}
if (!weight) {
weight = 4;
}
if (!opacity) {
opacity = 0.45;
}
var rot = -rotation * Math.PI / 180;
var points = [];
var latConv = google.maps.geometry.spherical.computeDistanceBetween(point, new google.maps.LatLng(point.lat() + 0.1, point.lng())) * 10;
var lngConv = google.maps.geometry.spherical.computeDistanceBetween(point, new google.maps.LatLng(point.lat(), point.lng() + 0.1)) * 10;
var step = (360 / vertexCount) || 10;
var flop = -1;
if (tilt) {
var I1 = 180 / vertexCount;
} else {
var I1 = 0;
}
for (var i = I1; i <= 360.001 + I1; i += step) {
var r1a = flop ? r1 : r3;
var r2a = flop ? r2 : r4;
flop = -1 - flop;
var y = r1a * Math.cos(i * Math.PI / 180);
var x = r2a * Math.sin(i * Math.PI / 180);
var lng = (x * Math.cos(rot) - y * Math.sin(rot)) / lngConv;
var lat = (y * Math.cos(rot) + x * Math.sin(rot)) / latConv;
points.push(new google.maps.LatLng(point.lat() + lat, point.lng() + lng));
}
return (new google.maps.Polyline({
path: points,
strokeColor: colour,
strokeWeight: weight,
strokeOpacity: opacity
}))
}
google.maps.Polygon.Shape = function (point, r1, r2, r3, r4, rotation, vertexCount, strokeColour, strokeWeight, Strokepacity, fillColour, fillOpacity, opts, tilt) {
var rot = -rotation * Math.PI / 180;
var points = [];
var latConv = google.maps.geometry.spherical.computeDistanceBetween(point, new google.maps.LatLng(point.lat() + 0.1, point.lng())) * 10;
var lngConv = google.maps.geometry.spherical.computeDistanceBetween(point, new google.maps.LatLng(point.lat(), point.lng() + 0.1)) * 10;
var step = (360 / vertexCount) || 10;
var flop = -1;
if (tilt) {
var I1 = 180 / vertexCount;
} else {
var I1 = 0;
}
for (var i = I1; i <= 360.001 + I1; i += step) {
var r1a = flop ? r1 : r3;
var r2a = flop ? r2 : r4;
flop = -1 - flop;
var y = r1a * Math.cos(i * Math.PI / 180);
var x = r2a * Math.sin(i * Math.PI / 180);
var lng = (x * Math.cos(rot) - y * Math.sin(rot)) / lngConv;
var lat = (y * Math.cos(rot) + x * Math.sin(rot)) / latConv;
points.push(new google.maps.LatLng(point.lat() + lat, point.lng() + lng));
}
return (new google.maps.Polygon({
paths: points,
strokeColor: strokeColour,
strokeWeight: strokeWeight,
strokeOpacity: Strokepacity,
fillColor: fillColour,
fillOpacity: fillOpacity
}))
}html, body, #map {
height: 100%;
width: 100%;
margin: 0px;
padding: 0px
}<script src="https://maps.googleapis.com/maps/api/js?libraries=geometry&key=AIzaSyCkUOdZ5y7hMm0yrcCQoCvLwzdM6M8s5qk""></script>
<div id="map"></div>
发布于 2015-02-03 17:33:58
我自己的答案(见下面的截图)--首先添加geometry库:
<script type="text/javascript"
src="https://maps.googleapis.com/maps/api/js?v=3&libraries=geometry">
</script>然后使用它创建矩形的角:
var NORTH = 0;
var WEST = -90;
var SOUTH = 180;
var EAST = 90;
function drawRect(map, lat, lng, width, height, color) {
var center = new google.maps.LatLng(lat, lng);
var north = google.maps.geometry.spherical.computeOffset(center, height / 2, NORTH);
var south = google.maps.geometry.spherical.computeOffset(center, height / 2, SOUTH);
var northEast = google.maps.geometry.spherical.computeOffset(north, width / 2, EAST);
var northWest = google.maps.geometry.spherical.computeOffset(north, width / 2, WEST);
var southEast = google.maps.geometry.spherical.computeOffset(south, width / 2, EAST);
var southWest = google.maps.geometry.spherical.computeOffset(south, width / 2, WEST);
var corners = [ northEast, northWest, southWest, southEast ];
var rect = new google.maps.Polygon({
paths: corners,
strokeColor: color,
strokeOpacity: 0.9,
strokeWeight: 1,
fillColor: color,
fillOpacity: 0.3,
map: map
});
}

要用angle旋转矩形,我可能可以将它添加到computeOffset()调用的第二个参数中。还没试过呢。
https://stackoverflow.com/questions/28283530
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