在php中使用json对象响应http get请求
在php中使用json对象响应http get请求
提问于 2015-02-07 07:00:12
我有一个PHP页面(test.php)，它必须响应从android应用程序发送的HTTP请求。响应必须通过json对象。我该怎么做？
以供参考:-是一个php代码，用于检查登录表单中的登录详细信息。http请求将是从包含登录表单的android应用程序发送的用户名和密码。此页面的响应将是成功或失败消息。
<?php
session_start();
require('connect.php');
if (isset($_GET['username']) and isset($_GET['password']))
{
$username = $_GET['username'];
$password = $_GET['password'];
$query = "SELECT * FROM `staff_reg` WHERE username='$username' and password='$password'";
$result = mysql_query($query) or die(mysql_error());
$count = mysql_num_rows($result);
if ($count == 1)
{
$_SESSION['username'] = $username;
}
else
{
echo "Invalid Username or Password";
}
}
if (!isset($_SESSION['username']))
{
echo "Session Expired";
echo "<br><a href='staff_login.php'>Click here</a> to login again";
echo "<br><a href='index.html'>Click here</a> to go back to the homepage";
$username = $_SESSION['username'];
}
else{
$username = $_SESSION['username'];
echo "<p>Welcome ".$username."<br>";
echo "This is the Staff Portal<br>";
echo "<a href='logout.php'>Logout</a></p>";
?>Stack Overflow用户
回答已采纳
发布于 2015-02-07 07:11:23
我想这可能对你有帮助..。
<?php
session_start();
require('connect.php');
//create an variable $response
//Use GET instead of POST since you are sending data in GET method
if (isset($_GET['username']) and isset($_GET['password']))
{
$username = $_GET['username'];
$password = $_GET['password'];
$query = "SELECT * FROM `staff_reg` WHERE username='$username' and password='$password'";
$result = mysql_query($query) or die(mysql_error());
$count = mysql_num_rows($result);
if ($count == 1)
{
$response="Success";
}
else
{
$response="Failure";
}
//now echo it as an json object
echo json_encode($response);
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/28379531
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