blocks|key|2177290|text|您可以使用查找符来确保您的单词在前面，并在两边都有一个字字符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2177291|strLine+=+strLine.replaceAll("(?<=\\w)"+%2B+word+%2B+"(?=\\w)",+replaceWord);|code-block|syntax|javascript|2177292|或者在两边使用\B：|offset|length|style|CODE|2177293|strLine+=+strLine.replaceAll("\\B"+%2B+word+%2B+"\\B",+replaceWord);|2177294|RegEx演示|2177295|entityMap|0|LINK|mutability|MUTABLE|url|https://regex101.com/r/uJ7gA3/1^0|0|0|7|2|0|0|0|7|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@$I|11|J|12|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|14|8|@]|9|@$I|15|J|16|1|17]]|A|$]]|$1|Q|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|R|$S|$5|T|U|V|A|$W|X]]]]

You can use lookarounds to make sure your word is preceded and followed by a word character on each side.

<pre><code>strLine = strLine.replaceAll("(?&lt;=\\w)" + word + "(?=\\w)", replaceWord);
</code></pre>

Or else use <code>\B</code> on either side:

<pre><code>strLine = strLine.replaceAll("\\B" + word + "\\B", replaceWord);
</code></pre>

<a href="https://regex101.com/r/uJ7gA3/1" rel="nofollow">RegEx Demo</a>

blocks|key|2177334|text|工作实例：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2177335|public+class+Main+{
++++public+static+void+main(String[]+args)+{
++++++++for+(String+prefix+:+new+String[]+{+"pre",+""+})+{
++++++++++++for+(String+suffix+:+new+String[]+{+"suf",+""+})+{
++++++++++++++++String+toReplace+=+"lala";
++++++++++++++++String+before+=+prefix+%2B+toReplace+%2B+suffix;
++++++++++++++++System.out.println(before+%2B+"+->+"
++++++++++++++++++++++++%2B+before.replaceAll("(?<=.)"+%2B+toReplace
++++++++++++++++++++++++%2B+"%7C"+%2B+toReplace+%2B+"(?=.)",+"[replaced]"));
++++++++++++}
++++++++}
++++}
}|code-block|syntax|javascript|2177336|输出：|2177337|prelalasuf+->+pre[replaced]suf
prelala+->+pre[replaced]
lalasuf+->+[replaced]suf
lala+->+lala|2177338|有关正则表达式语法的信息。|offset|length|2177339|正如人们所评论的，奇怪的是，您已经为单词字符编写了//w而不是\\w。我不知道它以前是怎么被取代的。|style|CODE|2177340|此外，您还说希望匹配任何字符，这意味着您希望使用.，而不是\\w。|2177341|entityMap|0|LINK|mutability|MUTABLE|url|http://www.regular-expressions.info/lookaround.html^0|0|0|0|0|0|D|0|0|P|3|V|3|0|O|1|T|3|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|14|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|16|8|@]|9|@$M|17|N|18|1|19]]|A|$]]|$1|O|3|P|5|6|7|1A|8|@$M|1B|N|1C|Q|R]|$M|1D|N|1E|Q|R]]|9|@]|A|$]]|$1|S|3|T|5|6|7|1F|8|@$M|1G|N|1H|Q|R]|$M|1I|N|1J|Q|R]]|9|@]|A|$]]|$1|U|3|-4|5|6|7|1K|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]]]

Working example:

<pre><code>public class Main {
 public static void main(String[] args) {
 for (String prefix : new String[] { "pre", "" }) {
 for (String suffix : new String[] { "suf", "" }) {
 String toReplace = "lala";
 String before = prefix + toReplace + suffix;
 System.out.println(before + " -&gt; "
 + before.replaceAll("(?&lt;=.)" + toReplace
 + "|" + toReplace + "(?=.)", "[replaced]"));
 }
 }
 }
}
</code></pre>

Output:

<pre><code>prelalasuf -&gt; pre[replaced]suf
prelala -&gt; pre[replaced]
lalasuf -&gt; [replaced]suf
lala -&gt; lala
</code></pre>

<a href="http://www.regular-expressions.info/lookaround.html" rel="nofollow">Information on the relevant regex syntax.</a>

As was commented, it's strange that you've written <code>//w</code> instead of <code>\\w</code> for a word character. I'm not sure how that got replaced before.

Also, you said you wanted to match any char which means you want to use <code>.</code>, not <code>\\w</code>.

I have the following text:

<blockquote>
 Testlalatest
</blockquote>

I am trying to replace <code>lala</code> with another string,

Output should be <code>Test[replace]test</code> only if there is any char after or behind <code>lala</code>.

but I am getting that: <code>Tes[replace]est</code>

Code:

<pre><code>strLine = strLine.replaceAll("\\w"+word+"\\w", replaceWord);
</code></pre>

Java Regex and replaceAll

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有以下案文：泰拉塔我试图用另一个字符串替换lala，只有在Test[replace]test之后或后面有任何字符时，输出才应该是lala。但我明白了：Tes[replace]est代码：strLine = strLine.replaceAll("\\w"+word+"\\w", replaceWord);

问Java和replaceAll
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问Java和replaceAllEN