blocks|key|521586|text|如果您只出现一次(和)，则此操作将有效。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|521587|SELECT+
++++SUBSTRING(columnName,+
++++++++++++++CHARINDEX('(',+columnName)%2B1,+
++++++++++++++CHARINDEX(')',+columnName)+-+CHARINDEX('(',+columnName)-1)
FROM+tableName|code-block|syntax|javascript|521588|如果您的值没有任何(...)内容，请添加以下where子句：|521589|WHERE++++CHARINDEX('(',+columnName)+>+0+AND+
+++++++++CHARINDEX(')',+columnName)+>+CHARINDEX('(',+columnName)|521590|entityMap^0|8|1|A|1|0|0|9|5|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|10|8|@]|D|@]|E|$]]]|P|$]]

This will work provided you only have a single occurence of <code>(</code> and <code>)</code>:

<pre><code>SELECT 
 SUBSTRING(columnName, 
 CHARINDEX('(', columnName)+1, 
 CHARINDEX(')', columnName) - CHARINDEX('(', columnName)-1)
FROM tableName
</code></pre>

If you have values that do not have any <code>(...)</code> content, add this where clause:

<pre><code>WHERE CHARINDEX('(', columnName) &gt; 0 AND 
 CHARINDEX(')', columnName) &gt; CHARINDEX('(', columnName)
</code></pre>

blocks|key|1565043|text|在Postgres中，可以使用POSIX正则表达式捕获来完成此操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1565044|=>+select+substring('This+(might)+work'+from+'[(](.*)[)]');
+substring+
-----------
+might|code-block|syntax|javascript|1565045|server似乎确实提供了正则表达式支持，但我并不熟悉它，我也没有一个运行测试用例的平台。这个特殊的例子很棘手，因为您必须正确引用分隔符()。|offset|length|style|CODE|1565046|entityMap|0|LINK|mutability|MUTABLE|url|https://msdn.microsoft.com/en-us/magazine/cc163473.aspx#S3^0|0|0|1W|2|D|7|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@$I|X|J|Y|K|L]]|9|@$I|Z|J|10|1|11]]|A|$]]|$1|M|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

In Postgres, you can do this using POSIX regular expression capture:

<pre><code>=&gt; select substring('This (might) work' from '[(](.*)[)]');
 substring 
-----------
 might
</code></pre>

It appears SQL server does offer <a href="https://msdn.microsoft.com/en-us/magazine/cc163473.aspx#S3" rel="nofollow">regexp support</a>, but I'm not familiar with it and I don't have a platform to run a test case. This particular example is tricky because you have to get the quoting of the delimiters <code>()</code> right.

blocks|key|521630|text|说明no、嵌套或不完整的()|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|521631|;with+t(f)+as+(
++++select+'aaa(bbb)ccc'+union
++++select+'aaa(bbbccc'+union
++++select+'aaabbb)ccc'+union
++++select+'aaa()ccc'+union
++++select+'(aaa(?))ccc'
)

select+f,
case+when+patindex('%25(%25)%25',+f)+>+0+
++++then+substring(f,+charindex('(',+f+)+%2B+1,+(len(f)+-+charindex(')',+reverse(f)))+-+charindex('(',+f+))+
++++else+''
end
from+t

>>

f+++++++++++++(No+column+name)
aaa()ccc++++
aaa(bbb)ccc+++bbb
(aaa(?))ccc+++aaa(?)
aaa(bbbccc++
aaabbb)ccc++|code-block|syntax|javascript|521632|entityMap^0|C|2|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

To account for no, nested or incomplete <code>()</code>

<pre><code>;with t(f) as (
 select 'aaa(bbb)ccc' union
 select 'aaa(bbbccc' union
 select 'aaabbb)ccc' union
 select 'aaa()ccc' union
 select '(aaa(?))ccc'
)

select f,
case when patindex('%(%)%', f) &gt; 0 
 then substring(f, charindex('(', f ) + 1, (len(f) - charindex(')', reverse(f))) - charindex('(', f )) 
 else ''
end
from t

&gt;&gt;

f (No column name)
aaa()ccc 
aaa(bbb)ccc bbb
(aaa(?))ccc aaa(?)
aaa(bbbccc 
aaabbb)ccc 
</code></pre>

I need to select a substring that is found between (). The starting and ending position will vary, as well as the length of the substring. I have had moderate success with the following but not 100%. 

It will work for some values but not for others, it return blanks and will also change the values capitalization format, in other words if value is 'TEST' it will display as 'Test'.

<pre><code>SELECT SUBSTRING(columnName, CHARINDEX('(', LEN(columnName)),
CHARINDEX(')', columnName) - CHARINDEX('(',columnName)) AS INPUT
FROM tableName
</code></pre>

Update There is only 1 set of parentheses ()

Selecting Substring SQL

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我需要选择一个在()之间找到的子字符串。起始位置和结束位置以及子字符串的长度都会有所不同。我在以下方面取得了一定的成功，但不是100%。它对某些值有效，但对另一些值无效，它返回空白，还将更改值大写格式，换句话说，如果值是'Test‘，它将显示为'TEST’。SELECT SUBSTRING(columnName, CH...

问选择子字符串SQL
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