blocks|key|349608|text|使用&分离器|type|unstyled|depth|inlineStyleRanges|entityRanges|data|349609|sudo+-u+oracle+-i+&&+cd+/lo2/ram/daska+&&+./script.sh|code-block|syntax|javascript|349610|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use &amp;&amp; separator

<pre><code>sudo -u oracle -i &amp;&amp; cd /lo2/ram/daska &amp;&amp; ./script.sh
</code></pre>

blocks|key|1128800|text|您还可以使用分号分隔命令。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1128801|sudo+-u+oracle+-i+;+cd+/lo2/ram/daska+;+./script.sh|code-block|syntax|javascript|1128802|使用&&和分号的区别在于，如果只想在前面的命令成功的情况下执行每个命令，那么可以使用&&操作符。但是，如果您想执行命令，不管前面的命令执行与否，您都可以使用分号(;)来分隔这些命令。|1128803|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can also use semicolon to seperate your command

<pre><code>sudo -u oracle -i ; cd /lo2/ram/daska ; ./script.sh
</code></pre>

The difference between using &amp;&amp; and semicolon is that if you want to execute each command only if the previous one succeeds, then you can use the &amp;&amp; operator. However if you want to execute commands, irrespective of previous one executes or not, you can use semicolon (;) to separate the commands.

blocks|key|1127960|text|我将在Piperoman和Rahul的回答中添加以下内容:对于&&，只有当第一个命令成功时才执行后一个命令，而对于;，总是执行以下命令。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1127961|所以|1127962|sudo+-u+oracle+-i+;+cd+/lo2/ram/daska+;+./script.sh|1127963|如果您不关心链中的所有东西是否都执行，并且|1127964|sudo+-u+oracle+-i+&&+cd+/lo2/ram/daska+&&+./script.sh|1127965|如果你愿意的话。|1127966|entityMap^0|V|2|1L|1|0|0|0|1F|0|0|0|1H|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]|$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|W|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|X|8|@$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|10|8|@]|D|@]|E|$]]|$1|L|3|M|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@]|E|$]]|$1|N|3|O|5|6|7|14|8|@]|D|@]|E|$]]|$1|P|3|-4|5|6|7|15|8|@]|D|@]|E|$]]]|Q|$]]

I'll just add to Piperoman's and Rahul's answers that with <code>&amp;&amp;</code> the later command is only executed if the first succeeds and with <code>;</code> following command is always executed.

So 

<code>sudo -u oracle -i ; cd /lo2/ram/daska ; ./script.sh</code>

if you don't care whether everything in the chain executes, and

<code>sudo -u oracle -i &amp;&amp; cd /lo2/ram/daska &amp;&amp; ./script.sh</code> 

if you do.

blocks|key|292037|text|执行sudo之后，就有了一个新的shell，其余的“命令”不是它的一部分，而是父shell的一部分。你可以：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|292038|+sudo+-u+oracle+-i+bash+-c+"cd+/lo2/ram/daska+&&+./script.sh"|code-block|syntax|javascript|292039|或者直接，|292040|+sudo+-u+oracle+-i+/lo2/ram/daska/script.sh|292041|entityMap^0|2|4|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

After executing <code>sudo</code> there's a new shell and the rest of "commands" are not part of it but part of the parent shell. You can do:

<pre><code> sudo -u oracle -i bash -c "cd /lo2/ram/daska &amp;&amp; ./script.sh"
</code></pre>

Or directly,

<pre><code> sudo -u oracle -i /lo2/ram/daska/script.sh
</code></pre>

blocks|key|349706|text|如果你这样做了|type|unstyled|depth|inlineStyleRanges|entityRanges|data|349707|sudo+-u+oracle+-i+;+cd+/lo2/ram/daska;+./script.sh|code-block|syntax|javascript|349708|告诉您应该启动在用户oracle下运行的登录shell。这是会发生的，其他命令在您离开这个shell后执行。|offset|length|style|CODE|349709|这可能不是你想要的。|349710|我认为有以下选择：|349711|sudo+-u+oracle+sh+-c+'cd+/lo2/ram/daska;+./script.sh'|349712|原则上在sudo的手册页中提到过。|349713|entityMap^0|0|0|A|6|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@$I|Z|J|10|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|11|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|12|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|14|8|@]|9|@]|A|$]]|$1|U|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|V|$]]

If you do

<pre><code>sudo -u oracle -i ; cd /lo2/ram/daska; ./script.sh
</code></pre>

you tell that a login shell running under user <code>oracle</code> should be started. That happens, and the other commands are executed after you leave this shell.

This is probably not what you want.

I see the following option:

<pre><code>sudo -u oracle sh -c 'cd /lo2/ram/daska; ./script.sh'
</code></pre>

which in principle is mentioned in sudo's man page.

How can I execute three commands on one command line in Linux? I tried the below:

<code>sudo -u oracle -i ; cd /lo2/ram/daska; ./script.sh</code>

When I execute this only the <code>sudo</code> command is executing.

Please advise me

Execute three commands in single command line in Linux

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如何在Linux中的一个命令行上执行三个命令？我尝试了以下几点：sudo -u oracle -i ; cd /lo2/ram/daska; ./script.sh当我执行这个命令时，只有sudo命令正在执行。请告诉我

问在Linux中在单个命令行中执行三个命令
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问在Linux中在单个命令行中执行三个命令EN