问查找字符串是否位于二维VBA Excel数组中
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Stack Overflow用户

提问于 2015-06-04 12:05:02

回答 6查看 10.5K关注 0票数 3

我有一个很好的函数，我一直对一个一维Excel数组使用它来检查字符串是否在数组中：

Function IsInArray(stringToBeFound As String, arr As Variant) As Boolean

    IsInArray = (UBound(Filter(arr(), stringToBeFound)) > -1)

End Function

不幸的是，在使用它检查二维数组时，它不能工作，就像我在这里所做的那样：

Sub new_idea_filter()

home_sheet = ActiveSheet.Name

c = 1

Dim myfilters(1 To 4, 1 To 5000)


myfilters(1, 4) = "Test"

If IsInArray("Test", myfilters()) = True Then
    killer = True
End If



End Sub

Function IsInArray(stringToBeFound As String, arr As Variant) As Boolean

    IsInArray = (UBound(Filter(arr(), stringToBeFound)) > -1)

End Function

它在函数中不断出错，表示下标超出了范围，有人想我如何检查字符串是否在二维数组中？

arrays

vba

excel

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Stack Overflow用户

发布于 2017-10-08 08:46:41

@Siddharth上面的答案除了Application.Match函数:-)外，还与Filter完美地工作在一起。-我的解决方案只尝试使用OP Filter函数:由于过滤器函数需要一个1昏暗的数组，所以数组被分割成部分。

A)使用原始筛选函数而不是匹配加上错误处理的替代解决方案

Function IsInArray(stringToBeFound As String, arr As Variant) As Boolean
Dim i      As Long

If nDim(arr) = 1 Then
  IsInArray = (UBound(Filter(arr(), stringToBeFound)) > -1)
Else    ' allows using filter function in portions
  For i = 1 To UBound(arr, 2)
      If (UBound(Filter(Application.Transpose(Application.Index(arr, 0, i)), stringToBeFound)) > -1) Then IsInArray = True: Exit For
  Next i
End If
End Function

帮助函数获取数组维数

Function nDim(ByVal vArray As Variant) As Long
' Purp: get number of array dimensions
' Site: http://support.microsoft.com/kb/152288
  Dim dimnum     As Long
  Dim ErrorCheck As Variant
  On Error GoTo FinalDimension
  For dimnum = 1 To 60000
      ErrorCheck = LBound(vArray, dimnum)
  Next

FinalDimension:
  nDim = dimnum - 1
End Function

B)递归解决方案使用原始的过滤函数而不是匹配加上错误处理

Function IsInArray(stringToBeFound As String, arr As Variant, Optional i As Long = 0) As Boolean
Select Case i
       Case -1:                                                             ' stop 2dim calls
       Case 0: IsInArray = IsInArray(stringToBeFound, arr, nDim(arr))       ' start recursive call
       Case 1: IsInArray = (UBound(Filter(arr(), stringToBeFound)) > -1)    ' 1dim array
       Case Else           ' allows using filter function in portions
            If (UBound(Filter(Application.Transpose(Application.Index(arr, 0, i)), stringToBeFound)) > -1) Then
               IsInArray = True
            Else            ' recursive calls (2dim array)
               IsInArray = IsInArray(stringToBeFound, arr, IIf(i + 1 > UBound(arr), -1, i + 1))
            End If
End Select
End Function