blocks|key|2039326|text|使用此模式|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2039327|(?=\S*['-])([a-zA-Z'-]%2B)|code-block|syntax|javascript|2039328|演示|offset|length|2039329|(?=+++++++++++++++++#+Look-Ahead
++\S++++++++++++++++#+<not+a+whitespace+character>
++*+++++++++++++++++#+(zero+or+more)(greedy)
++['-]++++++++++++++#+Character+in+['-]+Character+Class
)+++++++++++++++++++#+End+of+Look-Ahead
(+++++++++++++++++++#+Capturing+Group+(1)
++[a-zA-Z'-]++++++++#+Character+in+[a-zA-Z'-]+Character+Class
++%2B+++++++++++++++++#+(one+or+more)(greedy)
)+++++++++++++++++++#+End+of+Capturing+Group+(1)|2039330|entityMap|0|LINK|mutability|MUTABLE|url|https://regex101.com/r/yW4aZ3/267^0|0|0|0|2|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@$I|X|J|Y|1|Z]]|A|$]]|$1|K|3|L|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

use this pattern

<pre><code>(?=\S*['-])([a-zA-Z'-]+)
</code></pre>

<a href="https://regex101.com/r/yW4aZ3/267" rel="noreferrer">Demo</a>

<pre><code>(?= # Look-Ahead
 \S # &lt;not a whitespace character&gt;
 * # (zero or more)(greedy)
 ['-] # Character in ['-] Character Class
) # End of Look-Ahead
( # Capturing Group (1)
 [a-zA-Z'-] # Character in [a-zA-Z'-] Character Class
 + # (one or more)(greedy)
) # End of Capturing Group (1)
</code></pre>

blocks|key|2039353|text|[\w'-]%2B可以匹配几乎所有带有(或没有)连字符和撇号的单词，但在这些字符相邻的情况下也是如此。(?:\w%7C['-]\w)%2B应该匹配字符不能相邻的情况。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2039354|如果您需要确保单词包含连字符和/或撇号，并且这些字符不相邻，可以试试\w*(?:['-](?!['-])\w*)%2B。但这也与“独处”相匹配。|2039355|entityMap^0|0|7|1D|E|0|Y|N|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|R|8|@]|D|@]|E|$]]]|I|$]]

<code>[\w'-]+</code> would match pretty much any occurrence of words with (or without) hyphens and apostrophes, but also in cases where those characters are adjacent.
<code>(?:\w|['-]\w)+</code> should match cases where the characters can't be adjacent.

If you need to be sure that the word contains hyphens and/or apostrophes and that those characters aren't adjacent maybe try <code>\w*(?:['-](?!['-])\w*)+</code>. But that would also match ' and - alone.

blocks|key|627726|text|debuggex.com是可视化这些事情的一个很好的资源。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|627727|\b\w*[-']\w*\b应该能做到|style|CODE|627728|entityMap|0|LINK|mutability|MUTABLE|url|https://www.debuggex.com/r/E7N3Sscav7q9eFw1^0|0|T|0|0|0|E|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]]|C|$]]|$1|D|3|E|5|6|7|T|8|@$A|U|B|V|F|G]]|9|@]|C|$]]|$1|H|3|-4|5|6|7|W|8|@]|9|@]|C|$]]]|I|$J|$5|K|L|M|C|$N|O]]]]

<a href="https://www.debuggex.com/r/E7N3Sscav7q9eFw1" rel="noreferrer">debuggex.com is a great resource for visualizing these sorts of things</a>

<code>\b\w*[-']\w*\b</code> should do the trick

blocks|key|2039381|text|你遇到的问题是你实际上有三种可能的子模式:一个或多个字符，撇号后面跟着一个或多个字符，连字符后面跟着一个或多个字符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2039382|这意味着你不希望接受以撇号或连字符开头或结尾的单词，或者在撇号旁边有连字符(反之亦然)。|2039383|我认为在RegExp中表示这一点的最佳方法是：|2039384|/\b[a-z]%2B(?:['-]?[a-z]%2B)*\b/|code-block|syntax|javascript|2039385|被描述为：|2039386|\b+++++++++++++++++++#+word-break
[a-z]%2B+++++++++++++++#+one+or+more
(?:++++++++++++++++++#+start+non-matching+group
++['-]?++++++++++++++#+zero+or+one
++[a-z]%2B+++++++++++++#+one+or+more
)*+++++++++++++++++++#+end+of+non-matching+group,+zero+or+more
\b+++++++++++++++++++#+word-break|2039387|它将匹配以alpha开头和结尾的任何单词，并且可以包含零组或多组apos或连字符，后面跟着一个或多个alpha。|2039388|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|U|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|V|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|9|@]|A|$]]|$1|M|3|N|5|H|7|X|8|@]|9|@]|A|$I|J]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

The problem you're running into is that you actually have three possible sub-patterns: one or more chars, an apostrophe followed by one or more chars, and a hyphen followed by one or more chars.
This presumes you don't wish to accept words that begin or end with apostrophes or hyphens or have hyphens next to apostrophes (or vice versa).
I believe the best way to represent this in a RegExp would be:
<pre><code>/\b[a-z]+(?:['-]?[a-z]+)*\b/
</code></pre>
which is described as:
<pre><code>\b # word-break
[a-z]+ # one or more
(?: # start non-matching group
 ['-]? # zero or one
 [a-z]+ # one or more
)* # end of non-matching group, zero or more
\b # word-break
</code></pre>
which will match any word that begins and ends with an alpha and can contain zero or more groups of either a apos or a hyphen followed by one or more alpha.

blocks|key|627713|text|怎么样：\'?\w%2B([-']\w%2B)*\'?|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|627714|演示|627715|我想这些话不应该相配：|627716|something-或-something：从-开始还是结束|unordered-list-item|627717|some--thing或some'-thing：-后面没有字符|627718|some''：两个连字符|627719|entityMap|0|LINK|mutability|MUTABLE|url|https://regex101.com/r/bW5wN0/1^0|4|J|0|0|2|0|0|0|0|A|B|A|N|1|0|0|B|C|B|O|1|0|0|6|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|11|8|@]|D|@$9|12|A|13|1|14]]|E|$]]|$1|H|3|I|5|6|7|15|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|16|8|@$9|17|A|18|B|C]|$9|19|A|1A|B|C]|$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|M|3|N|5|L|7|1D|8|@$9|1E|A|1F|B|C]|$9|1G|A|1H|B|C]|$9|1I|A|1J|B|C]]|D|@]|E|$]]|$1|O|3|P|5|L|7|1K|8|@$9|1L|A|1M|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|1N|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X]]]]

How about: <code>\'?\w+([-']\w+)*\'?</code>

<a href="https://regex101.com/r/bW5wN0/1" rel="nofollow">demo</a>

I suppose these words shouldn't be matched: 

<ul>
<li><code>something-</code> or <code>-something</code>: start or end with <code>-</code></li>
<li><code>some--thing</code> or <code>some'-thing</code>: <code>-</code> not followed by a character </li>
<li><code>some''</code>: two hyphens</li>
</ul>

blocks|key|888022|text|这对我起了作用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|888023|([a-zA-Z]%2B'?-?[a-zA-Z]%2B(-?[a-zA-Z])?)%7C[a-zA-Z]|code-block|syntax|javascript|888024|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This worked for me:
<pre><code>([a-zA-Z]+'?-?[a-zA-Z]+(-?[a-zA-Z])?)|[a-zA-Z]
</code></pre>

blocks|key|627781|text|使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|627782|([\w]%2B[']*[\w]*)%7C([']*[\w]%2B)|code-block|syntax|javascript|627783|它将正确地解析“You‘a+and+we’it‘98”(在单词中的任何地方都支持'，但忽略了单个'+)。如果需要，\w可以替换为[a-zA-Z]等。|offset|length|style|CODE|627784|entityMap^0|0|0|14|1|1C|1|1L|2|1S|8|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]|$I|V|J|W|K|L]|$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|N|$]]

Use
<pre><code>([\w]+[']*[\w]*)|([']*[\w]+)
</code></pre>
It will properly parse
&quot;You've and we i've it' '98&quot;
(supports <code>'</code> in any place in the word but single <code>'</code> is ignored).
If needed <code>\w</code> could be replaced with <code>[a-zA-Z]</code> etc.

I was looking for a regex to match words with hyphens and/or apostrophes. So far, I have:

<pre><code>(\w+([-'])(\w+)?[']?(\w+))
</code></pre>

and that works most of the time, though if there's a apostrophe and then a hyphen, like "qu'est-ce", it doesn't match. I could append more optionals, though perhaps there's another more efficient way?

Some examples of what I'm trying to match: Mary's, High-school, 'tis, Chambers', Qu'est-ce.

Regex to match words with hyphens and/or apostrophes

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在寻找一个正则表达式来将单词与连字符和/或撇号匹配。到目前为止，我已经：(\w+([-'])(\w+)?[']?(\w+))这在大多数情况下都有效，但是如果有撇号，然后是连字符，比如“qu ce”，它就不匹配了。我可以附加更多的选项，虽然也许还有更有效的方法？一些我想要匹配的例子:玛丽的，高中的，‘它，钱伯斯’，曲特西。

问将单词与连字符和/或撇号匹配的正则表达式
EN

回答 7

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问将单词与连字符和/或撇号匹配的正则表达式EN

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问将单词与连字符和/或撇号匹配的正则表达式
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