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社区首页 >问答首页 >UnknownEntityTypeException:无法找到持久化程序(Hibernate 5.0)

UnknownEntityTypeException:无法找到持久化程序(Hibernate 5.0)
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Stack Overflow用户
提问于 2015-08-25 07:06:34
回答 3查看 18.9K关注 0票数 3

在下面的代码中,当我尝试执行Main.java时,我得到了异常:

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Exception in thread "main" org.hibernate.UnknownEntityTypeException: Unable to locate persister: com.np.vta.test.pojo.Users
    at org.hibernate.internal.SessionFactoryImpl.locateEntityPersister(SessionFactoryImpl.java:792)
    at org.hibernate.internal.SessionImpl.locateEntityPersister(SessionImpl.java:2637)
    at org.hibernate.internal.SessionImpl.access$2500(SessionImpl.java:164)
    at org.hibernate.internal.SessionImpl$IdentifierLoadAccessImpl.<init>(SessionImpl.java:2575)
    at org.hibernate.internal.SessionImpl$IdentifierLoadAccessImpl.<init>(SessionImpl.java:2562)
    at org.hibernate.internal.SessionImpl.byId(SessionImpl.java:1044)
    at org.hibernate.internal.SessionImpl.get(SessionImpl.java:955)
    at com.app.test.Main.main(Main.java:20)

但是,如果我取消注释cfg.addClass( Users.class ).addResource( "com/np/vta/test/pojo/Users.hbm.xml" );,那么代码就可以正常工作。

为什么它没有从<mapping>中读取hibernate.cfg.xml

项目设置

hibernate.cfg.xml

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<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN"
                                         "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
    <session-factory>
        <property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>
        <property name="hibernate.connection.password">root@123321</property>
        <property name="hibernate.connection.url">jdbc:mysql://192.168.1.90:3306/test</property>
        <property name="hibernate.connection.username">root</property>
        <property name="hibernate.dialect">org.hibernate.dialect.MySQLDialect</property>
        <mapping resource="com/np/vta/test/pojo/Users.hbm.xml" class="com.np.vta.test.pojo.Users" />
    </session-factory>
</hibernate-configuration>

Users.hbm.xml

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<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated 24 Aug, 2015 3:57:45 PM by Hibernate Tools 3.4.0.CR1 -->
<hibernate-mapping>
    <class name="com.np.vta.test.pojo.Users" table="tomcat_users">
        <id name="userName" type="java.lang.String">
            <column name="user_name" />
            <generator class="assigned" />
        </id>
        <property name="password" type="java.lang.String">
            <column name="password" />
        </property>
    </class>
</hibernate-mapping>

Users.java

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package com.np.vta.test.pojo;

import java.io.Serializable;

public class Users implements Serializable
{
    private static final long serialVersionUID = 7855937172997134350L;
    private String            userName;
    private String            password;

    public Users()
    {
    }
    // getter and setters
}

Main.java

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package com.app.test;

import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.boot.registry.StandardServiceRegistryBuilder;
import org.hibernate.cfg.Configuration;

import com.np.vta.test.pojo.Users;

public class Main
{
    public static void main( String[] args )
    {
        Configuration cfg = new Configuration();
        cfg.configure( "hibernate.cfg.xml" );
        //        cfg.addClass( Users.class ).addResource( "com/np/vta/test/pojo/Users.hbm.xml" );
        StandardServiceRegistryBuilder registryBuilder = new StandardServiceRegistryBuilder().applySettings( cfg.getProperties() );
        SessionFactory sessionFactory = cfg.buildSessionFactory( registryBuilder.build() );
        Session session = sessionFactory.openSession();
        Users users = session.get( Users.class, "anand" );
        System.out.println( users );
    }
}
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回答 3

Stack Overflow用户

发布于 2015-10-13 00:34:58

不要在StandardServiceRegistryBuilder中使用配置,配置被认为是不推荐的,而是像hibernate 5文档中提到的那样进行引导,我也遇到了同样的问题,这个问题得到了解决。

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StandardServiceRegistry standardRegistry = new     StandardServiceRegistryBuilder()
    .configure( "org/hibernate/example/MyCfg.xml" )
    .build();

Metadata metadata = new MetadataSources( standardRegistry )
    .addAnnotatedClass( MyEntity.class )
    .addAnnotatedClassName( "org.hibernate.example.Customer" )
    .addResource( "org/hibernate/example/Order.hbm.xml" )
    .addResource( "org/hibernate/example/Product.orm.xml" )
    .getMetadataBuilder()
    .applyImplicitNamingStrategy( ImplicitNamingStrategyJpaCompliantImpl.INSTANCE )
    .build();

SessionFactory sessionFactory = metadata.getSessionFactoryBuilder()
    .applyBeanManager( getBeanManagerFromSomewhere() )
    .build();

有关更多详细信息,请参阅文档

票数 4
EN

Stack Overflow用户

发布于 2021-04-02 10:37:20

尝试在末尾添加configure()方法。

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StandardServiceRegistryBuilder registryBuilder = new 
StandardServiceRegistryBuilder().applySettings(cfg.getProperties()).configure();
票数 2
EN

Stack Overflow用户

发布于 2020-08-27 07:13:56

同样的错误也可能由丢失或不正确的context:component-scan引起。

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/32197562

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