blocks|key|271149|text|以下是最简单的解决方案|type|unstyled|depth|inlineStyleRanges|entityRanges|data|271150|text.replace(word,+"*"+*+len(word))|code-block|syntax|javascript|271151|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is the simplest solution 

<pre><code>text.replace(word, "*" * len(word))
</code></pre>

blocks|key|158828|text|当你加入星号时，你有一个额外的空间：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|158829|def+censor(text,+word):
++++text+=+text.split("+")
++++asterisks=[]
++++text_with_asterisks=[]

++++for+item+in+text:
++++++++if+item+not+in+word:
++++++++++++text_with_asterisks.append(item)
++++++++else:
++++++++++++asterisks=[]
++++++++++++for+letter+in+word:
++++++++++++++++asterisks.append("*")

++++++++++++text_with_asterisks.append(''.join(asterisks))+#here's+the+culprit
++++return+("+".join(text_with_asterisks))|code-block|syntax|javascript|158830|censor("hey+hey+hey",+"hey")输出您想要的东西('***+***+***')|offset|length|style|CODE|158831|我只是指出了你的错误，但肯定有一个更优雅和更有效的方式来做你想做的事。|158832|entityMap^0|0|0|0|S|11|D|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]|$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|P|$]]

You have an extra space when you join your asterisks:

<pre><code>def censor(text, word):
 text = text.split(" ")
 asterisks=[]
 text_with_asterisks=[]

 for item in text:
 if item not in word:
 text_with_asterisks.append(item)
 else:
 asterisks=[]
 for letter in word:
 asterisks.append("*")

 text_with_asterisks.append(''.join(asterisks)) #here's the culprit
 return (" ".join(text_with_asterisks))
</code></pre>

<code>censor("hey hey hey", "hey")</code> outputs what you want (<code>'*** *** ***'</code>)

I just pointed out your mistake, but surely there's a more elegant and efficient way to do what you want.

blocks|key|271153|text|正如text_with_asterisks.append('+'.join(asterisks))所做的那样，每个字符都由"+"连接，然后"+".join(text_with_asterisks)也使每个单词由"+"连接，因此输出为：*+*+*+*+*+*+*+*+*，在每个恒星之间有一个空格。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|271154|entityMap^0|2|1B|1P|3|1X|T|2X|3|39|H|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]|$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|G|$]]

As <code>text_with_asterisks.append(' '.join(asterisks))</code> does, each character is joined by <code>" "</code>, and then <code>" ".join(text_with_asterisks)</code> also makes each words joined by <code>" "</code>, thus the output is: <code>* * * * * * * * *</code>, where there is a space between each star.

blocks|key|630713|text|做这件事的方法-|type|unstyled|depth|inlineStyleRanges|entityRanges|data|630714|import+re
def+censor(text,word):
++++return+re.sub(r'\b(?i){0}\b'.format(re.escape(word)),'*'+*+len(word),+text)|code-block|syntax|javascript|630715|示例/演示-|630716|>>>+censor('hey+hey+they+hey','hey')
'***+***+they+***'

>>>+censor('hey+hey+they+Hey','hey')
'***+***+they+***'|630717|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Regex method of doing this -

<pre><code>import re
def censor(text,word):
 return re.sub(r'\b(?i){0}\b'.format(re.escape(word)),'*' * len(word), text)
</code></pre>

<hr>

Example/Demo -

<pre><code>&gt;&gt;&gt; censor('hey hey they hey','hey')
'*** *** they ***'

&gt;&gt;&gt; censor('hey hey they Hey','hey')
'*** *** they ***'
</code></pre>

blocks|key|264322|text|在单词中的每个*之间都有空格，在单词之间有额外的空格，所以我认为，您只希望在单词之间有空格：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|264323|def+censor(text,+word):
++++return+'+'.join('*'*len(word)+if+word==item+else+item+for+item+in+text.split())|code-block|syntax|javascript|264324|entityMap^0|7|1|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You have spaces between every <code>*</code> in the word, and additional spaces between the words, so I think, you only want spaces between words:

<pre><code>def censor(text, word):
 return ' '.join('*'*len(word) if word==item else item for item in text.split())
</code></pre>

blocks|key|264326|text|简单的解决办法，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|264327|>>>+text+=+"hey+hey+hey"
>>>+"***".join(text.split("hey"))
'***+***+***'|code-block|syntax|javascript|264328|或|264329|+>>>+text+=+"hey+hey+they+Hey','hey"++
+>>>+"+".join([+'***'+if+word.lower()+==+'hey'+else+word
+...+for+word+in+text.replace("'","").replace(",","+").split()])
+'***+***+they+***+***'|264330|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Simple solution,

<pre><code>&gt;&gt;&gt; text = "hey hey hey"
&gt;&gt;&gt; "***".join(text.split("hey"))
'*** *** ***'
</code></pre>

Or

<pre><code> &gt;&gt;&gt; text = "hey hey they Hey','hey" 
 &gt;&gt;&gt; " ".join([ '***' if word.lower() == 'hey' else word
 ... for word in text.replace("'","").replace(","," ").split()])
 '*** *** they *** ***'
</code></pre>

blocks|key|264332|text|def+censor(text,+censor_w):
++++splitted_text+=+text.split("+")
++++asterics+=+"*"+*+len(censor_w)
++++result+=+[]

++++for+word+in+splitted_text:
++++++++if+word+==+censor:
++++++++++++result.append(asterics)
++++++++else:
++++++++++++result.append(word)

++++return+"+".join(result)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|264333|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>def censor(text, censor_w):
 splitted_text = text.split(" ")
 asterics = "*" * len(censor_w)
 result = []

 for word in splitted_text:
 if word == censor:
 result.append(asterics)
 else:
 result.append(word)

 return " ".join(result)
</code></pre>

I need to write a function that takes two strings (text and word) and returns the text with the chosen word replaced with asterisks (the number of asterisks should correspond to the number of letters in the censored word.).

For example:

if text="hey hey hey" and word="hey" the returned text should be:

<pre><code>'*** *** ***'
</code></pre>

Here is my code:

<pre><code>def censor(text,word):
 text = text.split(" ")
 asterisks=[]
 text_with_asterisks=[]

 for item in text:
 if item not in word:
 text_with_asterisks.append(item)
 else:
 asterisks=[]
 for letter in word:
 asterisks.append("*")

 text_with_asterisks.append(' '.join(asterisks))
 return (" ".join(text_with_asterisks))
</code></pre>

The code works but it returns:

<pre><code> ********* 
</code></pre>

and not

<pre><code>*** *** ***. 
</code></pre>

Once I use the line:

<pre><code>return ("_".join(text_with_asterisks))
</code></pre>

instead I get:

<pre><code>'***_***_***'
</code></pre>

I don't understand why the " " is ignored and how can I add a space between the words.

Thanks!

Python,join() function, adding space between words

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我需要编写一个函数，它接受两个字符串(文本和单词)，并返回所选单词替换为星号的文本(星号的数量应该对应于被审查的单词中的字母数)。例如：如果text=“嘿嘿”和word=“嘿嘿”，返回的文本应该是：'*** *** ***'这是我的代码：def censor(text,word):    text = text.spl...

问Python，联接()函数，在单词之间添加空格
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问Python，联接()函数，在单词之间添加空格EN