blocks|key|804432|text|我认为你需要重新考虑你的数据结构。目前还不清楚信号是否；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|804433|涵盖不同的时间跨度；|ordered-list-item|804434|在阅读之间有不同的时间步骤；|804435|或者两者都是。|804436|在第一种情况下，您可以简单地裁剪序列，使它们具有相同的长度和覆盖的时间跨度。但是，数字列表只能包含值，而不能包含它们用于的时间。如果您不将此信息存储在程序的其他地方，那么您将无法执行裁剪。|804437|在第二种情况下，您需要选择一个适当的系列或时间，并使您的信号符合这一要求。这可能采取一系列勒普操作的形式来填充目标点。|offset|length|804438|//+x+-+the+first+value
//+y+-+the+second+value
//+t+-+the+distance+from+the+first+to+the+second+value,+normalized+to+0..1
public+static+float+Lerp(float+x,+float+y,+float+t)+{

++++return+x+%2B+t+*+(y+-+x);
}|code-block|syntax|javascript|804439|如您所见，执行Lerp需要t，这可以根据两个已知点的时间值来计算。|style|CODE|804440|更好的数据结构可能是将时间映射到值：|804441|var+signal+=+new+Dictionary<DateTime,+double>();|804442|这将使您能够更容易地跟踪阅读发生的时间。|804443|关于执行实际相关性的问题+on+StackOverflow已经存在了。|804444|顺便说一句，这是R让它变得容易得多的东西--看看zoo包中的灵感吧。|804445|entityMap|0|LINK|mutability|MUTABLE|url|https://en.wikipedia.org/wiki/Linear_interpolation|1|https://stackoverflow.com/questions/17447817/correlation-of-two-arrays-in-c-sharp%25E2%2580%258C%25E2%2580%258B|2|https://www.r-project.org/^0|0|0|0|0|0|19|2|0|0|0|7|4|D|1|0|0|0|0|0|C|1|0|O|3|8|1|2|0^^$0|@$1|2|3|4|5|6|7|1J|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|1K|8|@]|9|@]|A|$]]|$1|E|3|F|5|D|7|1L|8|@]|9|@]|A|$]]|$1|G|3|H|5|D|7|1M|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|1N|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|1O|8|@]|9|@$M|1P|N|1Q|1|1R]]|A|$]]|$1|O|3|P|5|Q|7|1S|8|@]|9|@]|A|$R|S]]|$1|T|3|U|5|6|7|1T|8|@$M|1U|N|1V|V|W]|$M|1W|N|1X|V|W]]|9|@]|A|$]]|$1|X|3|Y|5|6|7|1Y|8|@]|9|@]|A|$]]|$1|Z|3|10|5|Q|7|1Z|8|@]|9|@]|A|$R|S]]|$1|11|3|12|5|6|7|20|8|@]|9|@]|A|$]]|$1|13|3|14|5|6|7|21|8|@]|9|@$M|22|N|23|1|24]]|A|$]]|$1|15|3|16|5|6|7|25|8|@$M|26|N|27|V|W]]|9|@$M|28|N|29|1|2A]]|A|$]]|$1|17|3|-4|5|6|7|2B|8|@]|9|@]|A|$]]]|18|$19|$5|1A|1B|1C|A|$1D|1E]]|1F|$5|1A|1B|1C|A|$1D|1G]]|1H|$5|1A|1B|1C|A|$1D|1I]]]]

I think that you need to reconsider your data-structure. It's not clear if the signals; 

<ol>
<li>cover different time-spans;</li>
<li>have different time-steps between readings;</li>
<li>or both. </li>
</ol>

In the first case, you can simply crop the series so that they have the same length and cover the same time-span. However, a list of numbers can only contain the values, not the times they are for. If you do not store this information elsewhere in the program then you will not be able to do the clipping. 

In the second case, you need to choose an appropriate series or times and conform both of your signals to that. This will likely take the form of a series of <a href="https://en.wikipedia.org/wiki/Linear_interpolation" rel="nofollow noreferrer">lerp</a> operations to fill in the target points. 

<pre><code>// x - the first value
// y - the second value
// t - the distance from the first to the second value, normalized to 0..1
public static float Lerp(float x, float y, float t) {

 return x + t * (y - x);
}
</code></pre>

As you can see, performing the <code>Lerp</code> requires <code>t</code>, which can be computed from the time-values of the two known points. 

A better data-structure might be a mapping of times to values: 

<pre><code>var signal = new Dictionary&lt;DateTime, double&gt;();
</code></pre>

This will allow you to keep track of when a reading happens more easily. 

There is already a <a href="https://stackoverflow.com/questions/17447817/correlation-of-two-arrays-in-c-sharp%E2%80%8C%E2%80%8B">question about performing the actual correlation</a> on StackOverflow. 

As an aside, this is something which <a href="https://www.r-project.org/" rel="nofollow noreferrer">R</a> makes considerably easier - take a look at the <code>zoo</code> package for inspiration.

blocks|key|804452|text|您将无法找到不同长度的数组之间的关联。您需要使较短的数组更长，或者更长的数组更短。我建议您考虑自回归条件异方差和/或向量自回归，以便通过延长或缩短数组来进行操作。之后，您可以应用相关计算。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|804453|entityMap|0|LINK|mutability|MUTABLE|url|https://en.wikipedia.org/wiki/Autoregressive_conditional_heteroskedasticity#GARCH|1|https://en.wikipedia.org/wiki/Vector_autoregression^0|1B|8|0|1M|5|1|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@$A|O|B|P|1|Q]|$A|R|B|S|1|T]]|C|$]]|$1|D|3|-4|5|6|7|U|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]|L|$5|G|H|I|C|$J|M]]]]

You will not be able to find correlation between to arrays of different length. You need either to make shorter array longer, or longer array shorter. I propose you to consider <a href="https://en.wikipedia.org/wiki/Autoregressive_conditional_heteroskedasticity#GARCH" rel="nofollow">Autoregressive conditional heteroskedasticity</a> and/or <a href="https://en.wikipedia.org/wiki/Vector_autoregression" rel="nofollow">Vector autoregression</a> in order to make manipulations with prolonging or cutting short your array. After that you can apply correlation calculation.

blocks|key|1239708|text|使用下面的VB.NET代码生成相同大小的数组。它将基本扩展/压缩数组，同时保持值的线性序列。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1239709|{2，4，6}将被拉伸到9大小为{2.0，2.5，3.0，3.5，4.0，4.5，5.0，5.5，6.0}|1239710|Public+Sub+Process
++++++++Dim+requiredLength+As+Integer+=+10
++++++++Dim+originalArr()+As+Double+=+{2.2,+3.3,+4.4,+4}

++++++++Dim+lcm+As+Integer+=+GetLCM(originalArr.Length+-+1,+requiredLength+-+1)

++++++++Dim+finalArr(requiredLength+-+1)+As+Double
++++++++Dim+finalIndex+As+Integer+=+0
++++++++Dim+originalIndex+As+Integer+=+0
++++++++Dim+currentValue+As+Double

++++++++Dim+portionRatio+As+Integer+=+(lcm+/+(originalArr.Length+-+1))
++++++++Dim+portionValue+As+Double+=+0
++++++++For+i+=+0+To+lcm
++++++++++++If+portionRatio+=+1+Or+(i+%2B+1)+Mod+portionRatio+=+1+Then
++++++++++++++++currentValue+=+originalArr(originalIndex)

++++++++++++++++If+originalIndex+<+originalArr.Length+-+1+Then+portionValue+=+(originalArr(originalIndex+%2B+1)+-+originalArr(originalIndex))+/+(lcm+-+1)

++++++++++++++++originalIndex+%2B=+1
++++++++++++Else
++++++++++++++++currentValue+%2B=+portionValue
++++++++++++End+If

++++++++++++If+i+Mod+(lcm+/+(requiredLength+-+1))+=+0+Then
++++++++++++++++finalArr(finalIndex)+=+currentValue
++++++++++++++++finalIndex+%2B=+1
++++++++++++End+If
++++++++Next
End+Sub

Private+Function+GetGCD(num1+As+Integer,+num2+As+Integer)+As+Integer
++++While+(Not+num1+=+num2)
++++++++If+num1+>+num2+Then+num1+=+num1+-+num2
++++++++If+num2+>+num1+Then+num2+=+num2+-+num1
++++End+While

++++Return+num1
End+Function

Private++Function+GetLCM(num1+As+Integer,+num2+As+Integer)+As+Integer
++++Return+(num1+*+num2)+/+GetGCD(num1,+num2)
End+Function|code-block|syntax|javascript|1239711|如果您在处理之前和之后绘制excel图表上的数组。您将看到海图线将具有相同的形状。|1239712|然后使用任何相关系数公式将其与所需数组进行比较。|1239713|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Use following VB.NET code to make arrays of same size. It will basically stretch/compress an array and at the same time it will maintain the linear sequence of values.

e.g. {2, 4, 6} will be stretched to size 9 as
{2.0, 2.5, 3.0, 3.5, 4.0, 4.5, 5.0, 5.5, 6.0}

<pre><code>Public Sub Process
 Dim requiredLength As Integer = 10
 Dim originalArr() As Double = {2.2, 3.3, 4.4, 4}

 Dim lcm As Integer = GetLCM(originalArr.Length - 1, requiredLength - 1)

 Dim finalArr(requiredLength - 1) As Double
 Dim finalIndex As Integer = 0
 Dim originalIndex As Integer = 0
 Dim currentValue As Double

 Dim portionRatio As Integer = (lcm / (originalArr.Length - 1))
 Dim portionValue As Double = 0
 For i = 0 To lcm
 If portionRatio = 1 Or (i + 1) Mod portionRatio = 1 Then
 currentValue = originalArr(originalIndex)

 If originalIndex &lt; originalArr.Length - 1 Then portionValue = (originalArr(originalIndex + 1) - originalArr(originalIndex)) / (lcm - 1)

 originalIndex += 1
 Else
 currentValue += portionValue
 End If

 If i Mod (lcm / (requiredLength - 1)) = 0 Then
 finalArr(finalIndex) = currentValue
 finalIndex += 1
 End If
 Next
End Sub

Private Function GetGCD(num1 As Integer, num2 As Integer) As Integer
 While (Not num1 = num2)
 If num1 &gt; num2 Then num1 = num1 - num2
 If num2 &gt; num1 Then num2 = num2 - num1
 End While

 Return num1
End Function

Private Function GetLCM(num1 As Integer, num2 As Integer) As Integer
 Return (num1 * num2) / GetGCD(num1, num2)
End Function
</code></pre>

If you plot array on excel chart before and after the process. You will see chart line will have same shape.

Then use any correlation coefficient formula to compare it with required array.

I have a signal that I store it real time in a list in c#. I also have a reference signal which I want to compare with the real time signal. The two signals haven't the same size. How can I align those two signals? How can I correlate them in c# I mean is there a function to calculate the correlation?

Correlate two signals in C# with different length

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个信号，我将它实时存储在c#中的列表中。我也有一个参考信号，我想要比较的实时信号。这两个信号大小不一样。我怎样才能对齐这两个信号？如何在c#中关联它们，我的意思是，是否有一个函数来计算相关性？

问不同长度的C#中的两个信号相关
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