blocks|key|1336608|text|使用strftime|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1336609|>>>+from+datetime+import+datetime
>>>+datetime.today().strftime('%25Y-%25m-%25d')
'2021-01-26'|code-block|syntax|javascript|1336610|还要在末尾包含一个零填充的Hour:Minute:Second：|1336611|>>>+datetime.today().strftime('%25Y-%25m-%25d+%25H:%25M:%25S')
'2021-01-26+16:50:03'|1336612|要获得协调世界时的日期和时间：|1336613|>>>+datetime.utcnow().strftime('%25Y-%25m-%25d+%25H:%25M:%25S')
'2021-01-27+00:50:03'|1336614|entityMap|0|LINK|mutability|MUTABLE|url|http://strftime.org/^0|2|8|2|8|0|0|0|D|I|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@$9|13|A|14|1|15]]|E|$]]|$1|F|3|G|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|17|8|@$9|18|A|19|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|1A|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1B|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|1C|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|1D|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z]]]]

Use <a href="http://strftime.org/" rel="noreferrer"><code>strftime</code></a>:
<pre><code>&gt;&gt;&gt; from datetime import datetime
&gt;&gt;&gt; datetime.today().strftime('%Y-%m-%d')
'2021-01-26'
</code></pre>
To also include a zero-padded <code>Hour:Minute:Second</code> at the end:
<pre><code>&gt;&gt;&gt; datetime.today().strftime('%Y-%m-%d %H:%M:%S')
'2021-01-26 16:50:03'
</code></pre>
To get the UTC date and time:
<pre><code>&gt;&gt;&gt; datetime.utcnow().strftime('%Y-%m-%d %H:%M:%S')
'2021-01-27 00:50:03'
</code></pre>

blocks|key|849535|text|您可以使用datetime.date.today()并将结果的datetime.date对象转换为字符串：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|849536|from+datetime+import+date
today+=+str(date.today())
print(today)+++#+'2017-12-26'|code-block|syntax|javascript|849537|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/library/datetime.html#datetime.date.today|1|https://docs.python.org/library/datetime.html#date-objects^0|5|L|V|D|5|L|0|V|D|1|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]|$9|12|A|13|1|14]]|E|$]]|$1|F|3|G|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]|S|$5|N|O|P|E|$Q|T]]]]

You can use <a href="https://docs.python.org/library/datetime.html#datetime.date.today" rel="noreferrer"><code>datetime.date.today()</code></a> and convert the resulting <a href="https://docs.python.org/library/datetime.html#date-objects" rel="noreferrer"><code>datetime.date</code></a> object to a string:

<pre><code>from datetime import date
today = str(date.today())
print(today) # '2017-12-26'
</code></pre>

blocks|key|1336645|text|为此，我总是使用isoformat()方法。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1336646|from+datetime+import+date++++
today+=+date.today().isoformat()
print(today)++#+'2018-12-05'|code-block|syntax|javascript|1336647|注意，如果您也需要标准的对象格式的时间，这也适用于ISO+8601。|1336648|from+datetime+import+datetime
now+=+datetime.today().isoformat()
print(now)++#+'2018-12-05T11:15:55.126382'|1336649|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3/library/datetime.html#datetime.date.isoformat|1|https://docs.python.org/3/library/datetime.html#datetime-objects|2|https://en.wikipedia.org/wiki/ISO_8601^0|8|B|8|B|0|0|0|C|2|1|P|8|2|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@$9|13|A|14|1|15]]|E|$]]|$1|F|3|G|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|17|8|@]|D|@$9|18|A|19|1|1A]|$9|1B|A|1C|1|1D]]|E|$]]|$1|M|3|N|5|H|7|1E|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|1F|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]|W|$5|R|S|T|E|$U|X]]|Y|$5|R|S|T|E|$U|Z]]]]

I always use the <a href="https://docs.python.org/3/library/datetime.html#datetime.date.isoformat" rel="noreferrer"><code>isoformat()</code></a> method for this.
<pre><code>from datetime import date 
today = date.today().isoformat()
print(today) # '2018-12-05'
</code></pre>
Note that this also works on <a href="https://docs.python.org/3/library/datetime.html#datetime-objects" rel="noreferrer"><code>datetime</code> objects</a> if you need the time in the standard <a href="https://en.wikipedia.org/wiki/ISO_8601" rel="noreferrer">ISO 8601</a> format as well.
<pre><code>from datetime import datetime
now = datetime.today().isoformat()
print(now) # '2018-12-05T11:15:55.126382'
</code></pre>

blocks|key|169626|text|很晚才回答，但您可以简单地使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|169627|import+time
today+=+time.strftime("%25Y-%25m-%25d")
#+2022-11-26|code-block|syntax|javascript|169628|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Very late answer, but you can simply use:
<pre><code>import time
today = time.strftime(&quot;%Y-%m-%d&quot;)
# 2022-11-26
</code></pre>

blocks|key|849528|text|如果你喜欢记住有趣的代码，约会时间就是很可爱的。你不喜欢简单吗？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|849529|>>>+import+arrow
>>>+arrow.now().format('YYYY-MM-DD')
'2017-02-17'|code-block|syntax|javascript|849530|这个模块很聪明，可以理解你的意思。|849531|只要做pip+install+arrow。|offset|length|style|CODE|849532|增编:在回答那些对这个答案进行练习的人时，我只想说箭头代表了在Python中处理日期的替代方法之一。这就是我的主要意思。|849533|entityMap^0|0|0|0|3|H|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|V|8|@$K|W|L|X|M|N]]|9|@]|A|$]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

Datetime is just lovely if you like remembering funny codes. Wouldn't you prefer simplicity?

<pre><code>&gt;&gt;&gt; import arrow
&gt;&gt;&gt; arrow.now().format('YYYY-MM-DD')
'2017-02-17'
</code></pre>

This module is clever enough to understand what you mean. 

Just do <code>pip install arrow</code>.

Addendum: In answer to those who become exercised over this answer let me just say that arrow represents one of the alternative approaches to dealing with dates in Python. That's mostly what I meant to suggest.

blocks|key|1336679|text|你和潘达斯一起工作吗？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1336680|您可以从pd.to_datetime库中使用熊猫。以下是各种选项，取决于您想要返回的内容。|offset|length|style|CODE|1336681|import+pandas+as+pd

pd.to_datetime('today')++#+pd.to_datetime('now')
#+Timestamp('2019-03-27+00:00:10.958567')|code-block|syntax|javascript|1336682|作为python+日期时间对象，|1336683|pd.to_datetime('today').to_pydatetime()
#+datetime.datetime(2019,+4,+18,+3,+50,+42,+587629)|1336684|作为格式化日期字符串，|1336685|pd.to_datetime('today').isoformat()
#+'2019-04-18T04:03:32.493337'

#+Or,+`strftime`+for+custom+formats.
pd.to_datetime('today').strftime('%25Y-%25m-%25d')
#+'2019-03-27'|1336686|要获得时间戳中的日期，请调用Timestamp.date。|1336687|pd.to_datetime('today').date()
#+datetime.date(2019,+3,+27)|1336688|除了to_datetime之外，您还可以使用|1336689|pd.Timestamp('today')++#+pd.Timestamp('now')
#+Timestamp('2019-04-18+03:43:33.233093')

pd.Timestamp('today').to_pydatetime()
#+datetime.datetime(2019,+4,+18,+3,+53,+46,+220068)|1336690|如果希望使时间戳时区知道，请将时区传递给tz参数。|1336691|pd.Timestamp('now',+tz='America/Los_Angeles')
#+Timestamp('2019-04-18+03:59:02.647819-0700',+tz='America/Los_Angeles')|1336692|另一个日期解析器库:摆|1336693|这个很好，我保证。|1336694|如果您正在使用摆摆，那么有一些有趣的选择。您可以使用now()获得当前时间戳，也可以使用today()获取今天的日期。|1336695|import+pendulum+

pendulum.now()
#+DateTime(2019,+3,+27,+0,+2,+41,+452264,+tzinfo=Timezone('America/Los_Angeles'))

pendulum.today()
#+DateTime(2019,+3,+27,+0,+0,+0,+tzinfo=Timezone('America/Los_Angeles'))|1336696|此外，您还可以直接获取tomorrow()或yesterday()的日期，而无需执行任何额外的时间增量算法。|1336697|pendulum.yesterday()
#+DateTime(2019,+3,+26,+0,+0,+0,+tzinfo=Timezone('America/Los_Angeles'))

pendulum.tomorrow()
#+DateTime(2019,+3,+28,+0,+0,+0,+tzinfo=Timezone('America/Los_Angeles'))|1336698|有各种格式设置选项可用。|1336699|pendulum.now().to_date_string()
#+'2019-03-27'

pendulum.now().to_formatted_date_string()
#+'Mar+27,+2019'

pendulum.now().to_day_datetime_string()
#+'Wed,+Mar+27,+2019+12:04+AM'|1336700|这一答案的理由|1336701|许多熊猫用户无意中发现了这个问题，因为他们认为这是一个巨蟒问题，而不是熊猫问题。这个答案的目的是帮助那些已经在使用这些库的人，并且有兴趣知道在库本身的范围内有实现这些结果的方法。|1336702|如果您已经没有使用熊猫或钟摆，我绝对不建议仅仅为了运行这段代码而安装它们！这些图书馆很重，在引擎盖下有很多管道。当您可以使用标准库时，这是不值得的。|1336703|entityMap|0|LINK|mutability|MUTABLE|url|https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.to_datetime.html|1|https://pandas.pydata.org/|2|https://docs.python.org/3/library/datetime.html#module-datetime|3|https://pendulum.eustace.io/docs/^0|0|4|E|4|E|0|M|2|1|0|0|9|4|2|0|0|0|0|E|E|0|0|2|B|0|0|K|2|0|0|0|0|Q|5|18|7|7|2|3|0|0|B|A|M|B|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|26|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|27|8|@$D|28|E|29|F|G]]|9|@$D|2A|E|2B|1|2C]|$D|2D|E|2E|1|2F]]|A|$]]|$1|H|3|I|5|J|7|2G|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|2H|8|@]|9|@$D|2I|E|2J|1|2K]]|A|$]]|$1|O|3|P|5|J|7|2L|8|@]|9|@]|A|$K|L]]|$1|Q|3|R|5|6|7|2M|8|@]|9|@]|A|$]]|$1|S|3|T|5|J|7|2N|8|@]|9|@]|A|$K|L]]|$1|U|3|V|5|6|7|2O|8|@$D|2P|E|2Q|F|G]]|9|@]|A|$]]|$1|W|3|X|5|J|7|2R|8|@]|9|@]|A|$K|L]]|$1|Y|3|Z|5|6|7|2S|8|@$D|2T|E|2U|F|G]]|9|@]|A|$]]|$1|10|3|11|5|J|7|2V|8|@]|9|@]|A|$K|L]]|$1|12|3|13|5|6|7|2W|8|@$D|2X|E|2Y|F|G]]|9|@]|A|$]]|$1|14|3|15|5|J|7|2Z|8|@]|9|@]|A|$K|L]]|$1|16|3|17|5|6|7|30|8|@]|9|@]|A|$]]|$1|18|3|19|5|6|7|31|8|@]|9|@]|A|$]]|$1|1A|3|1B|5|6|7|32|8|@$D|33|E|34|F|G]|$D|35|E|36|F|G]]|9|@$D|37|E|38|1|39]]|A|$]]|$1|1C|3|1D|5|J|7|3A|8|@]|9|@]|A|$K|L]]|$1|1E|3|1F|5|6|7|3B|8|@$D|3C|E|3D|F|G]|$D|3E|E|3F|F|G]]|9|@]|A|$]]|$1|1G|3|1H|5|J|7|3G|8|@]|9|@]|A|$K|L]]|$1|1I|3|1J|5|6|7|3H|8|@]|9|@]|A|$]]|$1|1K|3|1L|5|J|7|3I|8|@]|9|@]|A|$K|L]]|$1|1M|3|1N|5|6|7|3J|8|@]|9|@]|A|$]]|$1|1O|3|1P|5|6|7|3K|8|@]|9|@]|A|$]]|$1|1Q|3|1R|5|6|7|3L|8|@]|9|@]|A|$]]|$1|1S|3|-4|5|6|7|3M|8|@]|9|@]|A|$]]]|1T|$1U|$5|1V|1W|1X|A|$1Y|1Z]]|20|$5|1V|1W|1X|A|$1Y|21]]|22|$5|1V|1W|1X|A|$1Y|23]]|24|$5|1V|1W|1X|A|$1Y|25]]]]

<h1>Are you working with Pandas?</h1>
You can use <a href="https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.to_datetime.html" rel="noreferrer"><code>pd.to_datetime</code></a> from the <a href="https://pandas.pydata.org" rel="noreferrer">pandas</a> library. Here are various options, depending on what you want returned.
<pre><code>import pandas as pd

pd.to_datetime('today') # pd.to_datetime('now')
# Timestamp('2019-03-27 00:00:10.958567')
</code></pre>
As a python <a href="https://docs.python.org/3/library/datetime.html#module-datetime" rel="noreferrer">datetime</a> object,
<pre><code>pd.to_datetime('today').to_pydatetime()
# datetime.datetime(2019, 4, 18, 3, 50, 42, 587629)
</code></pre>
As a formatted date string,
<pre><code>pd.to_datetime('today').isoformat()
# '2019-04-18T04:03:32.493337'

# Or, `strftime` for custom formats.
pd.to_datetime('today').strftime('%Y-%m-%d')
# '2019-03-27'
</code></pre>
To get just the date from the timestamp, call <code>Timestamp.date</code>.
<pre><code>pd.to_datetime('today').date()
# datetime.date(2019, 3, 27)
</code></pre>
Aside from <code>to_datetime</code>, you can directly instantiate a <a href="https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.Timestamp.html" rel="noreferrer"><code>Timestamp</code></a> object using,
<pre><code>pd.Timestamp('today') # pd.Timestamp('now')
# Timestamp('2019-04-18 03:43:33.233093')

pd.Timestamp('today').to_pydatetime()
# datetime.datetime(2019, 4, 18, 3, 53, 46, 220068)
</code></pre>
If you want to make your Timestamp timezone aware, pass a timezone to the <code>tz</code> argument.
<pre><code>pd.Timestamp('now', tz='America/Los_Angeles')
# Timestamp('2019-04-18 03:59:02.647819-0700', tz='America/Los_Angeles')
</code></pre>
<hr />
<h1>Yet another date parser library: Pendulum</h1>
This one's good, I promise.
If you're working with <a href="https://pendulum.eustace.io/docs/" rel="noreferrer">pendulum</a>, there are some interesting choices. You can get the current timestamp using <code>now()</code> or today's date using <code>today()</code>.
<pre><code>import pendulum 

pendulum.now()
# DateTime(2019, 3, 27, 0, 2, 41, 452264, tzinfo=Timezone('America/Los_Angeles'))

pendulum.today()
# DateTime(2019, 3, 27, 0, 0, 0, tzinfo=Timezone('America/Los_Angeles'))
</code></pre>
Additionally, you can also get <code>tomorrow()</code> or <code>yesterday()</code>'s date directly without having to do any additional timedelta arithmetic.
<pre><code>pendulum.yesterday()
# DateTime(2019, 3, 26, 0, 0, 0, tzinfo=Timezone('America/Los_Angeles'))

pendulum.tomorrow()
# DateTime(2019, 3, 28, 0, 0, 0, tzinfo=Timezone('America/Los_Angeles'))
</code></pre>
There are various formatting options available.
<pre><code>pendulum.now().to_date_string()
# '2019-03-27'

pendulum.now().to_formatted_date_string()
# 'Mar 27, 2019'

pendulum.now().to_day_datetime_string()
# 'Wed, Mar 27, 2019 12:04 AM'
</code></pre>
<hr />
<h3>Rationale for this answer</h3>
A lot of pandas users stumble upon this question because they believe it is a python question more than a pandas one. This answer aims to be useful to folks who are already using these libraries and would be interested to know that there are ways to achieve these results within the scope of the library itself.
If you are not working with pandas or pendulum already, I definitely do not recommend installing them just for the sake of running this code! These libraries are heavy and come with a lot of plumbing under the hood. It is not worth the trouble when you can use the standard library instead.

blocks|key|853419|text|from+datetime+import+datetime

date+=+datetime.today().date()

print(date)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|853420|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>from datetime import datetime

date = datetime.today().date()

print(date)
</code></pre>

blocks|key|169849|text|使用f-字符串，它们通常是任何文本变量组合的最佳选择：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|169850|from+datetime+import+date
print(f'{date.today():%25Y-%25m-%25d}')|code-block|syntax|javascript|169851|摘自Python+f-字符串格式不使用strftime内联。，它也有官方链接。|offset|length|169852|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/65145502/11154841^0|0|0|2|S|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Use f-strings, they are usually the best choice for any text-variable mix:
<pre class="lang-py prettyprint-override"><code>from datetime import date
print(f'{date.today():%Y-%m-%d}')
</code></pre>
Taken from <a href="https://stackoverflow.com/a/65145502/11154841">Python f-string formatting not working with strftime inline</a> which has the official links as well.

blocks|key|1336818|text|如果你需要太平洋标准时间(PST)，你可以这样做|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1336819|from+datetime+import+datetime
import+pytz

tz+=+pytz.timezone('US/Pacific')
datetime.now(tz).strftime('%25Y-%25m-%25d+%25H:%25M:%25S')
#+'2021-09-02+10:21:41'|code-block|syntax|javascript|1336820|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you need e.g. pacific standard time (PST) you can do
<pre><code>from datetime import datetime
import pytz

tz = pytz.timezone('US/Pacific')
datetime.now(tz).strftime('%Y-%m-%d %H:%M:%S')
# '2021-09-02 10:21:41'
</code></pre>

blocks|key|169652|text|我的代码有点复杂，但我经常使用它。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|169653|strftime("%25y_%25m_%25d",+localtime(time.time()))|code-block|syntax|javascript|169654|参考：‘https://strftime.org/’|offset|length|169655|您可以查看该引用来为您制作任何您想要的内容YYYY+DD只需将我的代码更改为：|169656|strftime("%25Y-%25m-%25d",+localtime(time.time()))|169657|entityMap|0|LINK|mutability|MUTABLE|url|https://strftime.org/^0|0|0|4|L|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@$I|Z|J|10|1|11]]|A|$]]|$1|K|3|L|5|6|7|12|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

my code is a little complicated but I use it a lot
<pre><code>strftime(&quot;%y_%m_%d&quot;, localtime(time.time()))
</code></pre>
reference:'https://strftime.org/
you can look at the reference to make anything you want
for you what YYYY-MM-DD just change my code to:
<pre><code>strftime(&quot;%Y-%m-%d&quot;, localtime(time.time()))
</code></pre>

blocks|key|169720|text|这样做是可行的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|169721|from+datetime+import+date
today+=date.today()|code-block|syntax|javascript|169722|这一时期的产出:2020年-08-29|169723|补充：|169724|this_year+=+date.today().year
this_month+=+date.today().month
this_day+=+date.today().day
print(today)
print(this_year)
print(this_month)
print(this_day)|169725|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

This works:
<pre><code>from datetime import date
today =date.today()
</code></pre>
Output in this time: 2020-08-29
Additional:
<pre><code>this_year = date.today().year
this_month = date.today().month
this_day = date.today().day
print(today)
print(this_year)
print(this_month)
print(this_day)
</code></pre>

blocks|key|853414|text|从日期中获取日号在python中。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|853415|例如:+19+-12-2020(dd-mm-yyy)order_date我们需要19作为输出。|853416|order['day']+=+order['Order_Date'].apply(lambda+x:+x.day)|code-block|syntax|javascript|853417|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

To get day number from date is in python
for example:19-12-2020(dd-mm-yyy)order_date
we need 19 as output
<pre class="lang-py prettyprint-override"><code>order['day'] = order['Order_Date'].apply(lambda x: x.day)
</code></pre>

Is there a nicer way than the following to return today's date in the <code>YYYY-MM-DD</code> format?
<pre><code>str(datetime.datetime.today()).split()[0]
</code></pre>

Getting today's date in YYYY-MM-DD in Python?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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是否有比以下更好的方法以YYYY-MM-DD格式返回今天的日期？str(datetime.datetime.today()).split()[0]

问用Python的YYYY DD获取今天的日期？
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回答 12

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问用Python的YYYY DD获取今天的日期？
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