blocks|key|1548606|text|这个怎么样？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1548607|MATCH+()-[r]-(p:Picture+{id:'101531146106623881437036830'})-[:UPLOADED_TO]-(fb:Facebook)-[rf]-()
DELETE+r,+p,+fb,+r|code-block|syntax|javascript|1548608|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

What about this

<pre><code>MATCH ()-[r]-(p:Picture {id:'101531146106623881437036830'})-[:UPLOADED_TO]-(fb:Facebook)-[rf]-()
DELETE r, p, fb, r
</code></pre>

blocks|key|1081683|text|您的查询不工作，因为您不能删除图片，关系仍然链接到它。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1081684|让我们检查查询并解释错误|1081685|match++(picture:Picture)+where+picture.id='101531146106623881437036830'+|code-block|syntax|javascript|1081686|好的，你匹配图片节点，这里一切都很好。|1081687|optional+match+()-[r]-+picture-[:UPLOADED_TO]-(facebook:Facebook)-[rf]-()|1081688|使用可选匹配是一种选择，但这里的问题是您没有为UPLOADED_TO设置变量，因此查询可以看到这种关系，但是没有进行引用。|offset|length|style|CODE|1081689|with+r,rf,picture,facebook,picture.id+as+id|1081690|在这里，您将引用推送到删除部分(实际上，它并不需要，这里只需要使用别名)|1081691|delete+r,rf,picture,facebook
return+id|1081692|最后，删除您想要删除的内容，但是在这里您会得到一个错误：“不能删除节点，因为它有关系”或类似的内容。这是因为UPLOADED_TO关系仍然存在。|1081693|怎么修？|1081694|只需添加一个对UPLOADED_TO关系的引用来删除它。|1081695|match++(picture:Picture)+where+picture.id='101531146106623881437036830'+
optional+match+()-[r]-+picture-[r2:UPLOADED_TO]-(facebook:Facebook)-[rf]-()+++++
with+r2,r,rf,picture,facebook,picture.id+as+id+++++
delete+r2,r,rf,picture,facebook
return+id|1081696|米高克的回答也应该有效，但我想澄清你的错误，避免再次这样做;)|1081697|entityMap^0|0|0|0|0|0|N|B|0|0|0|0|1I|B|0|0|7|B|0|0|0^^$0|@$1|2|3|4|5|6|7|1A|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|1B|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|1C|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|1D|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|1E|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|1F|8|@$O|1G|P|1H|Q|R]]|9|@]|A|$]]|$1|S|3|T|5|F|7|1I|8|@]|9|@]|A|$G|H]]|$1|U|3|V|5|6|7|1J|8|@]|9|@]|A|$]]|$1|W|3|X|5|F|7|1K|8|@]|9|@]|A|$G|H]]|$1|Y|3|Z|5|6|7|1L|8|@$O|1M|P|1N|Q|R]]|9|@]|A|$]]|$1|10|3|11|5|6|7|1O|8|@]|9|@]|A|$]]|$1|12|3|13|5|6|7|1P|8|@$O|1Q|P|1R|Q|R]]|9|@]|A|$]]|$1|14|3|15|5|F|7|1S|8|@]|9|@]|A|$G|H]]|$1|16|3|17|5|6|7|1T|8|@]|9|@]|A|$]]|$1|18|3|-4|5|6|7|1U|8|@]|9|@]|A|$]]]|19|$]]

Your query is not working because you can't delete picture, a relation is still linked to it.
<h3>Let's check the query and explain the error</h3>
<pre><code>match (picture:Picture) where picture.id='101531146106623881437036830' 
</code></pre>
Ok you match the picture node, everything is fine here
<pre><code>optional match ()-[r]- picture-[:UPLOADED_TO]-(facebook:Facebook)-[rf]-()
</code></pre>
Using optional match is a choice, but the problem here is that you didn't set a variable for <code>UPLOADED_TO</code>, so this relation is seen by the query, but no references are made.
<pre><code>with r,rf,picture,facebook,picture.id as id
</code></pre>
Here you push your references to the delete part (it's not needed in fact, only usefull pour aliases here)
<pre><code>delete r,rf,picture,facebook
return id
</code></pre>
And finally you delete what you wanted to delete, but here you get an error &quot;Can't delete node because it has relationships&quot; or something like that. It's because <code>UPLOADED_TO</code> relation still exists.
<h3>How to fix?</h3>
Simply add a reference to <code>UPLOADED_TO</code>relation to delete it.
<pre><code>match (picture:Picture) where picture.id='101531146106623881437036830' 
optional match ()-[r]- picture-[r2:UPLOADED_TO]-(facebook:Facebook)-[rf]-() 
with r2,r,rf,picture,facebook,picture.id as id 
delete r2,r,rf,picture,facebook
return id
</code></pre>
MicTech's answer should work too, but I wanted to clarify your mistake to avoid doing it again ;)

I'm trying to deletes 2 related nodes with all of their relationship.

This is the query that I've been trying to do that:

<pre><code>match (picture:Picture) where picture.id='101531146106623881437036830' 
optional match ()-[r]- picture-[:UPLOADED_TO]-(facebook:Facebook)-[rf]-() 
with r,rf,picture,facebook,picture.id as id 
delete r,rf,picture,facebook
return id
</code></pre>

Can't seem to get it right for some reason.

Neo4j - Delete 2 related nodes with all of their relationships

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我试图删除两个相关节点及其所有关系。这是我一直在尝试的一个查询：match  (picture:Picture) where picture.id='101531146106623881437036830' optional match ()-[r]- picture-[:UPLOADED_TO]-(facebook:...

问Neo4j -删除2个相关节点及其所有关系
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