问在python中将dbf转换为csv的方法？

EN

dbf = Dbf5('fake_file_name.dbf')
df = dbf.to_dataframe()

import pysal as ps

def dbf2DF(dbfile, upper=True):
    "Read dbf file and return pandas DataFrame"
    with ps.open(dbfile) as db:  # I suspect just using open will work too
        df = pd.DataFrame({col: db.by_col(col) for col in db.header})
        if upper == True: 
           df.columns = map(str.upper, db.header) 
        return df

import csv
from dbfpy import dbf

def dbf_to_csv(out_table):#Input a dbf, output a csv
    csv_fn = out_table[:-4]+ ".csv" #Set the table as .csv format
    with open(csv_fn,'wb') as csvfile: #Create a csv file and write contents from dbf
        in_db = dbf.Dbf(out_table)
        out_csv = csv.writer(csvfile)
        names = []
        for field in in_db.header.fields: #Write headers
            names.append(field.name)
        out_csv.writerow(names)
        for rec in in_db: #Write records
            out_csv.writerow(rec.fieldData)
        in_db.close()
    return csv_fn

import csv
from dbfread import DBF

def dbf_to_csv(dbf_table_pth):#Input a dbf, output a csv, same name, same path, except extension
    csv_fn = dbf_table_pth[:-4]+ ".csv" #Set the csv file name
    table = DBF(dbf_table_pth)# table variable is a DBF object
    with open(csv_fn, 'w', newline = '') as f:# create a csv file, fill it with dbf content
        writer = csv.writer(f)
        writer.writerow(table.field_names)# write the column name
        for record in table:# write the rows
            writer.writerow(list(record.values()))
    return csv_fn# return the csv name

import sys
import dbf
for arg in sys.argv[1:]:
    dbf.export(arg)

python dbf2csv.py dbfname dbf2name dbf3name ...