blocks|key|2417050|text|你必须使用两个循环，因为你有两个随机长度的数组。但是你不需要嵌套它们。根据ID数组创建一个映射，然后检查索引。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2417051|var+availableIDs+=+array2.map(function+(+item+)+{+return+item.ID;+});
array1.forEach(function+(+item+)+{
++++if+(availableIDs.indexOf(item.StudentID)+!==+-1)+item.Checked+=+true;
});|code-block|syntax|javascript|2417052|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>You''ll have to use two loops, since you have two arrays of random length. But you don't have to nest them. Create a map from the array of IDs and then check the index.</p>

<pre><code>var availableIDs = array2.map(function ( item ) { return item.ID; });
array1.forEach(function ( item ) {
    if (availableIDs.indexOf(item.StudentID) !== -1) item.Checked = true;
});
</code></pre>


blocks|key|1952339|text|使用简单的映射函数，您可以对所有对象进行简单的搜索。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1952340|var+array1+=+[{Age:+24,+Name:+"Test",+StudentID:+101,+Checked:+false},+{Age:25,+Name:+"Test",+StudentID:+102,+Checked:+false}];
var+array2+=+[{ID:+101}];
function+search(studentList,searchQuery)+{
+++++var+results+=+[];
+++++studentList.forEach(function(student,sIndex)+{
++++++++++searchQuery.forEach(function(search,qIndex)+{
+++++++++++++++if(search.ID+==+student.StudentID)+{
++++++++++++++++++++results.push(student);
+++++++++++++++}
++++++++++});+++++++
+++++})
+++++return+results;
}
search(array1,array2);|code-block|syntax|javascript|1952341|forEach函数所做的是对每个元素进行迭代，传递它正在迭代的索引的对象以及对象所在的索引。|offset|length|style|CODE|1952342|通过拥有一个双重嵌套映射，可以轻松地遍历对象，然后根据您定义的规则对它们进行比较。|1952343|然后，通过使用一个作用域变量，您可以将匹配值推入该数组，从而给出一个很好、干净的结果来返回。|1952344|现在请注意，这不是处理这件事最有效的方法。您可以做一个测试，其中数组是最长的，并且有一个迭代时间最少。因此，如果有更多的学生比搜索参数迭代学生一次。如果搜索参数比学生多，请迭代一次搜索参数。|1952345|此外，你也可以选择“预先过滤”数组，方法是在你想要排序的索引上对数组进行排序，跳过那些你不需要的数组，比如简单的min/max排除等等。但是，最好使用数据库查询来搜索大量的数据。但是，如果你只有一个大约1000的数据集，这就足够了。|1952346|entityMap^0|0|0|0|7|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@$I|Z|J|10|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|11|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|12|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|13|8|@]|9|@]|A|$]]|$1|S|3|T|5|6|7|14|8|@]|9|@]|A|$]]|$1|U|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|V|$]]

<p>using a simple mapping function you can compose an easy search through all objects</p>

<pre><code>var array1 = [{Age: 24, Name: "Test", StudentID: 101, Checked: false}, {Age:25, Name: "Test", StudentID: 102, Checked: false}];
var array2 = [{ID: 101}];
function search(studentList,searchQuery) {
     var results = [];
     studentList.forEach(function(student,sIndex) {
          searchQuery.forEach(function(search,qIndex) {
               if(search.ID == student.StudentID) {
                    results.push(student);
               }
          });       
     })
     return results;
}
search(array1,array2);
</code></pre>

<p>what the <code>forEach</code> function does is iterate over each element, passing along the object of the index it's iterating, and the index that object is at.</p>

<p>By having a double nested map it's easy to iterate over the objects and then compare them according to the rules you define.</p>

<p>Then by using a scoped variable you can push matching values into that array, giving you a nice, neat clean result to return.</p>

<p>Now please mind, this is not the most efficient way to handle this. You could do a test which arary is longest and have that one iterate the least time.
So if there are more students than search parameters iterate the students once. If there are more search parameters than students, iterate the search paramateters once.</p>

<p>also you could chooose to 'prefilter" the arrays by sorting them on the index you wish to sort on, skip the ones you don't need by simple min/max exclusion and such.
But you'd be better off using a database query for searching with large quantities of data.
But if you only have a dataset of about a 1000 or so this will suffice.</p>


blocks|key|1952374|text|试试这个片段：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1952375|_.each(array1,+function+(el)+{
++++el.Checked+=+!!(JSON.stringify(array2).indexOf(el.StudentID)+%2B+1)+%7C%7C+el.Checked;
});|code-block|syntax|javascript|1952376|或者，您可以不使用lo-dash.js(使用纯JavaScript)。|1952377|​|1952378|var+array1+=+[{Age:+24,+Name:+"Test",+StudentID:+101,+Checked:+false},+{Age:25,+Name:+"Test",+StudentID:+102,+Checked:+false}];
var+array2+=+[{ID:+101}];
var+students+=+array1.filter(function(data){
++var+isTrue+=+!!(JSON.stringify(array2).indexOf(data.StudentID)%2B1);
++data.Checked+=+isTrue+%7C%7C+data.Checked;
++return+isTrue;
})
console.log(students)|1952379|1952380|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Q|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|R|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|S|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|M|3|J|5|6|7|U|8|@]|9|@]|A|$]]|$1|N|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|O|$]]

<p>Try this snippet:</p>

<pre><code>_.each(array1, function (el) {
    el.Checked = !!(JSON.stringify(array2).indexOf(el.StudentID) + 1) || el.Checked;
});
</code></pre>

<p>Or, you can do without lo-dash.js(with pure JavaScript)</p>

<p><div class="snippet" data-lang="js" data-hide="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var array1 = [{Age: 24, Name: "Test", StudentID: 101, Checked: false}, {Age:25, Name: "Test", StudentID: 102, Checked: false}];
var array2 = [{ID: 101}];
var students = array1.filter(function(data){
  var isTrue = !!(JSON.stringify(array2).indexOf(data.StudentID)+1);
  data.Checked = isTrue || data.Checked;
  return isTrue;
})
console.log(students)</code></pre>
</div>
</div>
</p>


blocks|key|2417254|text|使用lodash，使用一个序列，在其中您使用array1创建一个项目映射，使用_.indexBy()。使用array2使用_.pluck()创建一个ids数组，并将它们与_.at()一起使用以获取所选项。使用_.forEach()迭代返回的对象，将Checked属性设置为true，并使用.commit()应用更改：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2417255|​|2417256|function+checkById(items,+selected)+{
++_(items)+//+start+chained+sequence
++++.indexBy('StudentID')+//+create+a+map+of+student+objects+by+ids
++++.at(_.pluck(selected,+'ID'))+//+create+an+array+of+IDs+from+the+objects+in+the+selected+array
++++.forEach(function(item)+{+//+change+the+items+Checked+to+true
++++++item.Checked+=+true;
++++})
++++.commit();+//+executes+the+chained+sequence
}

var+array1+=+[{
++Age:+24,
++Name:+"Test1",
++StudentID:+101,
++Checked:+false
},+{
++Age:+25,
++Name:+"Test2",
++StudentID:+102,
++Checked:+false
},+{
++Age:+22,
++Name:+"Test3",
++StudentID:+103,
++Checked:+false
},+{
++Age:+28,
++Name:+"Test4",
++StudentID:+104,
++Checked:+false
}];

var+array2+=+[{
++ID:+101
},+{
++ID:+104
}];

checkById(array1,+array2);

console.table(array1);

document.getElementById('demo').innerText+=+JSON.stringify(array1,+null,+'+');|code-block|syntax|javascript|2417257|<script+src="https://cdn.jsdelivr.net/lodash/3.10.1/lodash.min.js"></script>

<pre+id="demo"></pre>|2417258|2417259|entityMap|0|LINK|mutability|MUTABLE|url|https://lodash.com/docs#indexBy|1|https://lodash.com/docs#pluck|2|https://lodash.com/docs#at|3|https://lodash.com/docs#forEach|4|http://_.prototype.commit()/^0|M|6|13|B|1H|6|1P|9|2D|6|2W|B|3G|7|3S|4|40|9|13|B|0|1P|9|1|2D|6|2|2W|B|3|40|9|4|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|15|8|@$9|16|A|17|B|C]|$9|18|A|19|B|C]|$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]|$9|1E|A|1F|B|C]|$9|1G|A|1H|B|C]|$9|1I|A|1J|B|C]|$9|1K|A|1L|B|C]|$9|1M|A|1N|B|C]]|D|@$9|1O|A|1P|1|1Q]|$9|1R|A|1S|1|1T]|$9|1U|A|1V|1|1W]|$9|1X|A|1Y|1|1Z]|$9|20|A|21|1|22]]|E|$]]|$1|F|3|G|5|6|7|23|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|24|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|J|7|25|8|@]|D|@]|E|$K|L]]|$1|O|3|G|5|6|7|26|8|@]|D|@]|E|$]]|$1|P|3|-4|5|6|7|27|8|@]|D|@]|E|$]]]|Q|$R|$5|S|T|U|E|$V|W]]|X|$5|S|T|U|E|$V|Y]]|Z|$5|S|T|U|E|$V|10]]|11|$5|S|T|U|E|$V|12]]|13|$5|S|T|U|E|$V|14]]]]

<p>Using lodash, use a sequence in which you create a map of items in <code>array1</code>, using <a href="https://lodash.com/docs#indexBy" rel="nofollow"><code>_.indexBy()</code></a>. Create an array of ids from <code>array2</code> using <a href="https://lodash.com/docs#pluck" rel="nofollow"><code>_.pluck()</code></a>, and use them with <a href="https://lodash.com/docs#at" rel="nofollow"><code>_.at()</code></a> to get the selected items. Iterate the returned objects using <a href="https://lodash.com/docs#forEach" rel="nofollow"><code>_.forEach()</code></a> to set the <code>Checked</code> property to <code>true</code>, and <a href="http://_.prototype.commit()" rel="nofollow"><code>.commit()</code></a> to apply the changes:</p>

<p><div class="snippet" data-lang="js" data-hide="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>function checkById(items, selected) {
  _(items) // start chained sequence
    .indexBy('StudentID') // create a map of student objects by ids
    .at(_.pluck(selected, 'ID')) // create an array of IDs from the objects in the selected array
    .forEach(function(item) { // change the items Checked to true
      item.Checked = true;
    })
    .commit(); // executes the chained sequence
}

var array1 = [{
  Age: 24,
  Name: "Test1",
  StudentID: 101,
  Checked: false
}, {
  Age: 25,
  Name: "Test2",
  StudentID: 102,
  Checked: false
}, {
  Age: 22,
  Name: "Test3",
  StudentID: 103,
  Checked: false
}, {
  Age: 28,
  Name: "Test4",
  StudentID: 104,
  Checked: false
}];

var array2 = [{
  ID: 101
}, {
  ID: 104
}];

checkById(array1, array2);

console.table(array1);

document.getElementById('demo').innerText = JSON.stringify(array1, null, ' ');</code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;script src="https://cdn.jsdelivr.net/lodash/3.10.1/lodash.min.js"&gt;&lt;/script&gt;

&lt;pre id="demo"&gt;&lt;/pre&gt;</code></pre>
</div>
</div>
</p>


<pre><code>var array1 = [{Age: 24, Name: "Test", StudentID: 101, Checked: false}, {Age:25, Name: "Test", StudentID: 102, Checked: false}];
var array2 = [{ID: 101}];
</code></pre>

<p>If any element in <code>array1</code> has a property of <code>StudentID</code> that is equal to an <code>ID</code> property present in <code>array2</code> I'd like to set the <code>Checked</code> property in <code>array1</code> to true. </p>

<p>Any tips? I'd like to do this without writing nested _.each statements.</p>

<p>This is my first take; however, I believe <code>_.some</code> performs an interation anyway.</p>

<pre><code>_.each($scope.array1, function(element1) {
          if(_.some($scope.array2, { ID: element1.ID })) {
            element1.Checked = true;
          }
        });
</code></pre>


I have two arrays, how do I find matchings elements and perform some action? (lodash)

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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var array1 = [{Age: 24, Name: "Test", StudentID: 101, Checked: false}, {Age:25, Name: "Test", StudentID: 102, Checked: false}];var array2 = [{ID: 101}];如果array1...

问我有两个数组，如何找到匹配元素并执行一些操作？(送交)
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问我有两个数组，如何找到匹配元素并执行一些操作？(送交)EN