blocks|key|211554|text|在if块和else块中，下面的行都应该是相同的吗？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|211555|$(this).find('#sortIcon').removeClass('fa-sort-alpha-desc').addClass('fa-sort-alpha-asc');|code-block|syntax|javascript|211556|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>Is the following line suppose to be the same in both the if block and the else block? </p>

<pre><code>$(this).find('#sortIcon').removeClass('fa-sort-alpha-desc').addClass('fa-sort-alpha-asc');
</code></pre>


blocks|key|1991815|text|尝试下面的代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1991816|$('#sortName').on('click',+function+(e)+{
+++++e.preventDefault();
+++++if+($('#sortIcon').hasClass('fa-sort-alpha-desc'))+{
+++++++++$(this).find('#sortIcon').removeClass('fa-sort-alpha-desc').addClass('fa-sort-alpha-asc');
+++++++++$('#searchVal').val('asc');
+++++}+else+{
+++++++++$(this).find('#sortIcon').removeClass('fa-sort-alpha-asc').addClass('fa-sort-alpha-desc');
+++++++++$('#searchVal').val('desc');
+++++}
+++++$('form').submit();
+});|code-block|syntax|javascript|1991817|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>Try this code instead:</p>

<pre><code>$('#sortName').on('click', function (e) {
     e.preventDefault();
     if ($('#sortIcon').hasClass('fa-sort-alpha-desc')) {
         $(this).find('#sortIcon').removeClass('fa-sort-alpha-desc').addClass('fa-sort-alpha-asc');
         $('#searchVal').val('asc');
     } else {
         $(this).find('#sortIcon').removeClass('fa-sort-alpha-asc').addClass('fa-sort-alpha-desc');
         $('#searchVal').val('desc');
     }
     $('form').submit();
 });
</code></pre>


blocks|key|1991903|text|我更改了代码以查看隐藏字段是否为空。然后，我根据这个决定做出了一个决定。新的JQuery代码如下所示，到目前为止，它运行得很好。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1991904|+$('#sortName').on('click',+function+(e)+{
+++++++++++++e.preventDefault();
+++++++++++++var+testVal+=+$('#searchVal').val();
+++++++++++++if+(testVal+===+'desc')+{
+++++++++++++++++$('#sortIcon').removeClass('fa-sort-alpha-desc').addClass('fa-sort-alpha-asc');
+++++++++++++++++$('#searchVal').val('asc');
+++++++++++++}+else+{
+++++++++++++++++$('#sortIcon').removeClass('fa-sort-alpha-asc').addClass('fa-sort-alpha-desc');
+++++++++++++++++$('#searchVal').val('desc');
+++++++++++++}
+++++++++++++$('form').submit();
+++++++++});|code-block|syntax|javascript|1991905|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>I changed the code to see if the hidden field is null or not. Then, I made a decision based on that decision. The new JQuery code is below, and it's worked fine so far. </p>

<pre><code> $('#sortName').on('click', function (e) {
             e.preventDefault();
             var testVal = $('#searchVal').val();
             if (testVal === 'desc') {
                 $('#sortIcon').removeClass('fa-sort-alpha-desc').addClass('fa-sort-alpha-asc');
                 $('#searchVal').val('asc');
             } else {
                 $('#sortIcon').removeClass('fa-sort-alpha-asc').addClass('fa-sort-alpha-desc');
                 $('#searchVal').val('desc');
             }
             $('form').submit();
         });
</code></pre>


blocks|key|119034|text|像这样试试|type|unstyled|depth|inlineStyleRanges|entityRanges|data|119035|​|119036|$('a#sortName').on('click',+function+(e)+{
++++e.preventDefault();
++++//+Setting+the+current+clicked+icon+into+a+variable.
++++var+findSortIcon+=+$(this).find('#sortIcon');
++++if+(findSortIcon.hasClass('fa-sort-alpha-desc'))+{
++++++++$('#searchVal').val('asc');
++++++++//$('form').submit();+-+We+are+sending+the+submit+anytime+whenever+the+button+is+		clicked
++++++++findSortIcon.removeClass('fa-sort-alpha-desc').addClass('fa-sort-alpha-asc');
++++}+else+{
++++++++$('#searchVal').val('desc');
++++++++//var+myVal+=+$('#searchVal').val();+-+no+need+for+this+(You+dont+use+it+anyway)
++++++++//+$('form').submit();+-+same+in+here
++++++++findSortIcon.removeClass('fa-sort-alpha-asc').addClass('fa-sort-alpha-desc');
++++}
++++//+Whether+its+true+or+false+submit+it!
++++$('form').submit();
++++
++++
+++	//+Extra+stuff+to+check+changing+directly
++++var+attr+=+findSortIcon.attr("class");
++++$('#show-class').html(attr+%2B+"+for+"+%2B+$(this).text())
++++
});|code-block|syntax|javascript|119037|<script+src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div+class="divFullWidth+hidden-sx+col-sm-2+col-md-2+col-lg-2">
++<a+href="#"+data-action="POST">+First+Name</a>+
++<a+id="sortName"+href="#"+data-sort="SORT">
++++<i+id="sortIcon"+class="sort+fa+fa-1x+fa-sort-alpha-desc">
++++++ICON
++++</i>
++</a>
</div>
<div+class="divFullWidth+hidden-sx+col-sm-2+col-md-2+col-lg-2">
++<a+href="#"+data-action="POST">+First+Name2</a>+
++<a+id="sortName"+href="#"+data-sort="SORT">+
++++<i+id="sortIcon"+class="sort+fa+fa-1x+fa-sort-alpha-desc">
++++++ICON2
++++</i>
++</a>
</div>

<div+id="show-class"></div>|119038|119039|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|P|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|K|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|M|$]]

<p>Try it like this</p>

<p><div class="snippet" data-lang="js" data-hide="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>$('a#sortName').on('click', function (e) {
    e.preventDefault();
    // Setting the current clicked icon into a variable.
    var findSortIcon = $(this).find('#sortIcon');
    if (findSortIcon.hasClass('fa-sort-alpha-desc')) {
        $('#searchVal').val('asc');
        //$('form').submit(); - We are sending the submit anytime whenever the button is 		clicked
        findSortIcon.removeClass('fa-sort-alpha-desc').addClass('fa-sort-alpha-asc');
    } else {
        $('#searchVal').val('desc');
        //var myVal = $('#searchVal').val(); - no need for this (You dont use it anyway)
        // $('form').submit(); - same in here
        findSortIcon.removeClass('fa-sort-alpha-asc').addClass('fa-sort-alpha-desc');
    }
    // Whether its true or false submit it!
    $('form').submit();
    
    
   	// Extra stuff to check changing directly
    var attr = findSortIcon.attr("class");
    $('#show-class').html(attr + " for " + $(this).text())
    
});
                   </code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"&gt;&lt;/script&gt;
&lt;div class="divFullWidth hidden-sx col-sm-2 col-md-2 col-lg-2"&gt;
  &lt;a href="#" data-action="POST"&gt; First Name&lt;/a&gt; 
  &lt;a id="sortName" href="#" data-sort="SORT"&gt;
    &lt;i id="sortIcon" class="sort fa fa-1x fa-sort-alpha-desc"&gt;
      ICON
    &lt;/i&gt;
  &lt;/a&gt;
&lt;/div&gt;
&lt;div class="divFullWidth hidden-sx col-sm-2 col-md-2 col-lg-2"&gt;
  &lt;a href="#" data-action="POST"&gt; First Name2&lt;/a&gt; 
  &lt;a id="sortName" href="#" data-sort="SORT"&gt; 
    &lt;i id="sortIcon" class="sort fa fa-1x fa-sort-alpha-desc"&gt;
      ICON2
    &lt;/i&gt;
  &lt;/a&gt;
&lt;/div&gt;

&lt;div id="show-class"&gt;&lt;/div&gt;</code></pre>
</div>
</div>
</p>


<p>I am sorting a list of users by first name when a user click on the sort  icon. However, I've noticed that there are times when I click the sort icon, the icon is switched, however, the data not sorted. For example, I click on it 10 times, and there may be 3 times when the data simply not sorted but the icon changed. Any help here would be appreciated.</p>

<p><strong>A partial section of the html code.</strong></p>

<pre><code>  &lt;div class="divFullWidth hidden-sx col-sm-2 col-md-2 col-lg-2"&gt;
&lt;a href="#" data-action="POST"&gt; First Name&lt;/a&gt; 
&lt;a id="sortName" href="#" data-sort="SORT"&gt;
&lt;i id="sortIcon" class="sort fa fa-1x fa-sort-alpha-desc"&gt;&lt;/i&gt;&lt;/a&gt;&lt;/div&gt;
</code></pre>

<p><strong>The function to handle replacing the button and submit the form.</strong></p>

<pre><code>  $('#sortName').on('click', function (e) {
         e.preventDefault();
         if ($('#sortIcon').hasClass('fa-sort-alpha-desc')) {
             $('#searchVal').val('asc');
             $('form').submit();
             $(this).find('#sortIcon').removeClass('fa-sort-alpha-desc').addClass('fa-sort-alpha-asc');
         } else {
             $('#searchVal').val('desc');
             var myVal = $('#searchVal').val();
             $('form').submit();
             $(this).find('#sortIcon').removeClass('fa-sort-alpha-asc').addClass('fa-sort-alpha-desc');
         }
     });
</code></pre>


JQuery Click Function Randomly Stops Working

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

当用户单击排序图标时，我将按名称对用户列表进行排序。然而，我已经注意到，有时我点击排序图标，图标被切换，然而，数据没有排序。例如，我点击它10次，可能有3次，当数据没有排序，但图标改变。这里的任何帮助都将不胜感激。：html代码的一部分.  <div class="divFullWidth hidden-sx col-...

问JQuery单击函数随机停止工作
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问JQuery单击函数随机停止工作EN