我有一个清单如下:
$A
[1] "one"
$B
[1] "Two"
$C
[1] "Three"
$D
[1] "Four" "Five"
$E
[1] "Six" "Seven"最后,我想得到这样一个数据框架:
Var1 Var2
A One
B Two
C Three
D Four
D Five
E Six
E Seven列表元素中的项数可以是任意的(可能也是character(0) )。嵌套级别只是一个。
发布于 2015-11-18 15:19:40
这个怎么样?
x <- list(A = "one",
B = "Two",
c = "Three",
D = c("Four", "Five"),
E = c("Six", "Seven"))
df <- data.frame(Var1 = rep(names(x), sapply(x, length)),
Var2 = unlist(x, use.names = F))https://stackoverflow.com/questions/33783494
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