blocks|key|1077860|text|import+re
import+np
text+=+open('text_numbers.txt')
final+=+[]
for+line+in+text:
++++line+=+line.strip()
++++y+=+re.findall('([0-9]%2B)',line)

++++if+len(y)+>+0:
+++++++++lineVal+=+sum(map(int,+y))
+++++++++final.append(lineVal)
+++++++++print+"line+sum+=+{0}".format(lineVal)
+print+"Final+sum+=+{0}".format(np.sum(final))|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1077861|这就是你要找的吗？|unstyled|1077862|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>import re
import np
text = open('text_numbers.txt')
final = []
for line in text:
 line = line.strip()
 y = re.findall('([0-9]+)',line)

 if len(y) &gt; 0:
 lineVal = sum(map(int, y))
 final.append(lineVal)
 print "line sum = {0}".format(lineVal)
 print "Final sum = {0}".format(np.sum(final))
</code></pre>

Is that what you're looking for?

blocks|key|2949966|text|import+re
text+=+open('text_numbers.txt')
data=text.read()
print+sum(map(int,re.findall(r"\b\d%2B\b",data)))|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2949967|使用.read获取string格式的内容|unstyled|offset|length|style|CODE|2949968|entityMap^0|0|2|5|9|6|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]|$G|Q|H|R|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|S|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>import re
text = open('text_numbers.txt')
data=text.read()
print sum(map(int,re.findall(r"\b\d+\b",data)))
</code></pre>

Use <code>.read</code> to get content in <code>string</code> format

blocks|key|2949980|text|import+re
sample+=+open+('text_numbers.txt')
total+=0
dignum+=+0+

for+line+in+sample:
++++line+=+line.rstrip()
++++dig=+re.findall('[0-9]%2B',+line)

++++if+len(dig)+>0:
++++++++dignum+%2B=+len(dig)
++++++++linetotal=+sum(map(int,+dig))
++++++++total+%2B=+linetotal

print+'The+number+of+digits+are:++'+
print+dignum
print+'The+sum+is:+'
print+total+++++
print+'The+sum+ends+with:+'
print++total+%25+1000|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2949981|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import re
sample = open ('text_numbers.txt')
total =0
dignum = 0 

for line in sample:
 line = line.rstrip()
 dig= re.findall('[0-9]+', line)

 if len(dig) &gt;0:
 dignum += len(dig)
 linetotal= sum(map(int, dig))
 total += linetotal

print 'The number of digits are: ' 
print dignum
print 'The sum is: '
print total 
print 'The sum ends with: '
print total % 1000
</code></pre>

blocks|key|2950008|text|我不太懂蟒蛇，但我可以给出一个简单的解决方案。尝尝这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2950009|import+re
hand+=+open('text_numbers.txt')
x=list()
for+line+in+hand:
++++y=re.findall('[0-9]%2B',line)
++++x=x%2By
sum=0
for+i+in+x:
++++sum=sum+%2B+int(i)
print+sum|code-block|syntax|javascript|2950010|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I dont know much python but I can give a simple solution.
Try this

<pre><code>import re
hand = open('text_numbers.txt')
x=list()
for line in hand:
 y=re.findall('[0-9]+',line)
 x=x+y
sum=0
for i in x:
 sum=sum + int(i)
print sum
</code></pre>

blocks|key|1170132|text|import+re
print+sum([int(i)+for+i+in+re.findall('[0-9]%2B',open(raw_input('What+is+the+file+you+want+to+analyze?\n'),'r').read())])|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1170133|你可以把它压缩成一行，但这只是为了好玩！|unstyled|1170134|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>import re
print sum([int(i) for i in re.findall('[0-9]+',open(raw_input('What is the file you want to analyze?\n'),'r').read())])
</code></pre>

You can compact it into one line, but this is only for fun!

blocks|key|2950088|text|我第一次尝试用正则表达式来回答这个问题，我发现这是一个很好的练习技巧，那就是阅读别人的代码。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2950089|import+re+#+import+regular+expressions
chuck_text+=+open("regex_sum_286723.txt")
numbers+=+[]
Total+=+0
for+line+in+chuck_text:
++++nmbrs+=+re.findall('[0-9]%2B',+line)
++++numbers+=+numbers+%2B+nmbrs+
for+n+in+numbers:
++++Total+=+Total+%2B+float(n)
print+"Total+=+",+Total+|code-block|syntax|javascript|2950090|并感谢啤酒的“理解清单”一句，虽然他的“r”似乎不需要，但不知道它能做什么。但是它读起来很漂亮，我更困惑地读了两个像我的答案一样的循环。|2950091|import+re
print+sum([int(i)+for+i+in+re.findall('[0-9]%2B',open("regex_sum_286723.txt").read())])|2950092|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

My first attempt to answer with the use of regular expressions, I find it a great skill to practise, that reading other's code. 

<pre><code>import re # import regular expressions
chuck_text = open("regex_sum_286723.txt")
numbers = []
Total = 0
for line in chuck_text:
 nmbrs = re.findall('[0-9]+', line)
 numbers = numbers + nmbrs 
for n in numbers:
 Total = Total + float(n)
print "Total = ", Total 
</code></pre>

and thanx to Beer for the 'comprehension list' one liner, though his 'r' seems not needed, not sure what it does. But it reads beautifully, I get more confused reading two lots of loops like my answer

<pre><code>import re
print sum([int(i) for i in re.findall('[0-9]+',open("regex_sum_286723.txt").read())])
</code></pre>

blocks|key|1077989|text|这是我对这个问题的解决办法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1077990|import+re

file+=+open('text_numbers.txt')
sum+=+0+

for+line+in+file:
++++line+=+line.rstrip()
++++line+=+re.findall('([0-9]%2B)',+line)
++++for+i+in+line:
++++++++i+=+int(i)
++++++++sum+%2B=+i++++

print(sum)|code-block|syntax|javascript|1077991|第一个for循环中的行元素也是lists，我使用第二个for循环将其元素从字符串转换为整数，这样我就可以对它们进行求和。|offset|length|style|BOLD|1077992|entityMap^0|0|0|3|3|F|5|R|3|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]|$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|X|8|@]|9|@]|A|$]]]|N|$]]

Here is my solution to this problem. 

<pre><code>import re

file = open('text_numbers.txt')
sum = 0 

for line in file:
 line = line.rstrip()
 line = re.findall('([0-9]+)', line)
 for i in line:
 i = int(i)
 sum += i 

print(sum)
</code></pre>

The line elements in first for loop are the lists also and I used second for loop to convert its elements to integer from string so I can sum them.

blocks|key|2950124|text|import+re

fl=open('regex_sum_7469.txt')
ls=[]

for+x+in+fl:+#create+a+list+in+the+list
+++x=x.rstrip()
+++print+x
+++t=+re.findall('[0-9]%2B',x)+#all+numbers
+++for+d+in+t:+#for+loop+as+there+a+empthy+values+in+the+list+a
++++++++ls.append(int(d))
print+(sum(ls))|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2950125|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import re

fl=open('regex_sum_7469.txt')
ls=[]

for x in fl: #create a list in the list
 x=x.rstrip()
 print x
 t= re.findall('[0-9]+',x) #all numbers
 for d in t: #for loop as there a empthy values in the list a
 ls.append(int(d))
print (sum(ls))
</code></pre>

blocks|key|1078011|text|这是我的代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1078012|f+=+open('regex_sum_text.txt',+'r').read().strip()
y+=+re.findall('[0-9]%2B',+f)
l+=+[int(s)+for+s+in+y]
s+=+sum(l)
print(s)|code-block|syntax|javascript|1078013|另一种较短的方式是：|1078014|with+open('regex_sum_text.txt',+'r')+as+f:
++++total+=+sum(map(int,+re.findall(r'[0-9]%2B',+f.read())))

print(total)|1078015|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Here is my code:
<pre><code>f = open('regex_sum_text.txt', 'r').read().strip()
y = re.findall('[0-9]+', f)
l = [int(s) for s in y]
s = sum(l)
print(s)
</code></pre>
another shorter way is:
<pre><code>with open('regex_sum_text.txt', 'r') as f:
 total = sum(map(int, re.findall(r'[0-9]+', f.read())))

print(total)
</code></pre>

blocks|key|1170281|text|import+re
print(sum(int(value)+for+value+in+re.findall('[0-9]%2B',+open('regex_sum_1128122.txt').read())))|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1170282|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import re
print(sum(int(value) for value in re.findall('[0-9]+', open('regex_sum_1128122.txt').read())))
</code></pre>

I am just learning python and need some help for my class assignment. 

I have a file with text and numbers in it. Some lines have from one to three numbers and others have no numbers at all.

I need to:

<ol>
<li>Extract numbers only from the file using regex</li>
<li>Find the sum of all the numbers</li>
</ol>

I used regex to extract out all the numbers. I am trying to get the total sum of all the numbers but I am just getting the sum of each line that had numbers. I have been battling with different ways to do this assignment and this is the closest I have gotten to getting it right. 

I know I am missing some key parts but I am not sure what I am doing wrong. 

Here is my code:

<pre><code>import re
text = open('text_numbers.txt')

for line in text:
 line = line.strip()
 y = re.findall('([0-9]+)',line)

 if len(y) &gt; 0:
 print sum(map(int, y))
</code></pre>

The result I get is something like this 
(each is a sum of a line):

<blockquote>
 14151
 
 8107
 
 16997
 
 18305
 
 3866
</blockquote>

And it needs to be one sum like this (sum of all numbers):

<blockquote>
 134058
</blockquote>

Sum of strings extracted from text file using regex

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

我只是在学习python，需要一些帮助来完成我的课堂作业。我有一个文件，里面有文字和数字。有些行有一个到三个数字，而另一些则根本没有数字。我需要：仅使用regex从文件中提取数字。找出所有数字的和我用regex提取出所有的数字。我试图得到所有数字的总和，但我只是得到每一行有数字的总和。我一直在努力用不同的方法来完成这个...

问使用regex从文本文件中提取字符串的和
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问使用regex从文本文件中提取字符串的和EN