我有一个可以列出餐馆对象的工作数据表。我想删除/编辑所选的那些,但是当我选择一个时,会出现以下异常:
org.springframework.dao.InvalidDataAccessApiUsageException: The given id must not be null!这张桌子是:
<h:form id="restaurantForm">
<p:dataTable var="restaurant"
value="#{restaurantLazyBean.lazyDataModel}" paginator="true"
rows="10" rowsPerPageTemplate="5,10,50" id="carTable" lazy="true"
selectionMode="single" selection="#{RestaurantEditBean.selected}"
rowKey="#{restaurant.id}"
paginatorTemplate="{RowsPerPageDropdown} {FirstPageLink} {PreviousPageLink} {CurrentPageReport} {NextPageLink} {LastPageLink}">
<p:ajax event="rowSelect"
listener="#{RestaurantEditBean.onRowSelect()}"/>
<p:column headerText="ID">
<h:outputText value="#{restaurant.id}" />
</p:column>
</p:dataTable>
</h:form>现在,所有in都会出现在表中,但是在选择时会出现异常。我试着按照素颜的例子做每件事。但他们甚至没有rowKey属性。
这是豆子,如果是相关的话。
@Named("RestaurantEditBean")
@ViewScoped
@EJB(name = "ejb.RestaurantService", beanInterface = RestaurantService.class)
public class RestaurantEditBean {
@EJB
private RestaurantService restaurantService;
private RestaurantDTO selected;
public void onRowSelect(SelectEvent event) {
selected = ((RestaurantDTO) event.getObject());
}
public RestaurantService getRestaurantService() {
return restaurantService;
}
public void setRestaurantService(RestaurantService restaurantService) {
this.restaurantService = restaurantService;
}
public RestaurantDTO getSelected() {
return selected;
}
public void setSelected(RestaurantDTO selected) {
this.selected = selected;
}}
基本面: 5.3 JSF: 2.2
发布于 2015-12-21 16:54:49
我发现我犯了一个严重的错误。在我的LazyDataModel中,我必须重写一个函数。
@Override
public RestaurantDTO getRowData(String rowKey) {
Long id = Long.parseLong(rowKey);
return restaurantService.findById(id);
}这个问题是由前一个Long.getLong(rowKey)引起的,并且返回null。
https://stackoverflow.com/questions/34394846
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