问关于不工作的getter的JPA @列注释

EN

@Transient
private Map<String, String> choices = null;

@Column(name = "choices", nullable = false)
public String getChoices() {
    return gson.toJson(choices);
}

 DEBUG SQL:109 - 
    insert 
    into
        question
        (description, id) 
    values
        (?, ?)

CREATE TABLE `question` (<br/>
  `id` varchar(50) COLLATE utf8_bin NOT NULL,<br/>
  `description` varchar(1000) COLLATE utf8_bin NOT NULL,<br/>
  `choices` text COLLATE utf8_bin NOT NULL,<br/>
  `answers` varchar(100) COLLATE utf8_bin NOT NULL<br/>
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_bin;<br/>
<br/>
ALTER TABLE `question`<br/>
  ADD PRIMARY KEY (`id`);<br/>

@Entity
@Table(name = "question")
public class Question {

@Id
private String id = null;

@Column(name = "description", nullable = false)
private String description = null;


@Transient
@Column(name = "choices", nullable = false)
private Map<String, String> choices = null;

public String getChoices() {
    return gson.toJson(choices);
}


@Transient
private Set<String> answers = null;

@Transient
private Gson gson = new GsonBuilder().create();

public Question() {
    this.id = UUID.randomUUID().toString();
}
...
}//End of class