如何将标题正确地包含在索引文件中。我想有积极的编辑我的标题,因为它在我的所有网页。
让我说我有一个标题:
<nav class="navbar navbar-default navbar-fixed-top topnav" role="navigation">
<div class="container topnav">
<!-- Brand and toggle get grouped for better mobile display -->
<div class="navbar-header">
<button type="button" class="navbar-toggle" data-toggle="collapse" data-target="#bs-example-navbar-collapse-1">
<span class="sr-only">Toggle navigation</span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</button>
<a class="navbar-brand topnav" href="#">Start Bootstrap</a>
</div>
</div>
</nav我复制到我的header.php的代码,所以我只有一次的地方来编辑它。上面的代码应该在body标记中,还是我需要在我的头文档中包含html、head和body标记?
<html>
<head>
</head>
<body>
<-!-- Code here -->
</body>
</html>发布于 2016-01-31 09:22:40
<html>
<head>
<!-- Latest compiled and minified CSS -->
<link rel="stylesheet" href="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css">
<!-- jQuery library -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
<!-- Latest compiled JavaScript -->
<script src="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"> </script>
</head>
<body>
<nav class="navbar navbar-default navbar-fixed-top topnav" role="navigation">
<div class="container topnav">
<!-- Brand and toggle get grouped for better mobile display -->
<div class="navbar-header">
<button type="button" class="navbar-toggle" data-toggle="collapse" data-target="#bs-example-navbar-collapse-1">
<span class="sr-only">Toggle navigation</span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</button>
<a class="navbar-brand topnav" href="#">Start Bootstrap</a>
</div>
</div>
</nav>
</body>
</html>我相信你用的是引导
发布于 2016-01-31 09:26:57
考虑到所有包含PHP代码的文件都应该具有.php扩展名。
然后,您可以像这样包含任何HTML粒子:将头文件命名为header.php、页脚文件footer.php:等等。
<html>
<head>
</head>
<body>
<?php include 'header.php'; ?>
<-!-- Code here -->
<?php include 'footer.php'; ?>
</body>
</html>https://stackoverflow.com/questions/35112026
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