blocks|key|170955|text|URL不能包含西里尔字符。有一些标准可以将西里尔字符转换成有效的URLs+-如果你搜索"Punicode“(P是有意的)，你可能会发现一些东西。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|170956|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

URLs cannot contain Cyrillic characters. There are standards how to translate Cyrillic characters into valid URLs - you might find something if you search for "Punicode" (the P is intentional).

blocks|key|170976|text|非ASCII字符(和许多特殊字符)需要在URL中转义。Chrome和其他浏览器会自动完成此操作。为了更好的显示，他们取消了地址栏中的URL。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|170977|因此，如果您有一个静态URL，只需将其粘贴到adressbar，按enter，再次选择URL，复制并粘贴到您的应用程序：|170978|因此，与其：|170979|let+jsonUrl+=+"http://api.com/алматы/events"|code-block|syntax|javascript|170980|你会得到：|170981|let+jsonUrl+=+"http://api.com/%25D0%25B0%25D0%25BB%25D0%25BC%25D0%25B0%25D1%2582%25D1%258B/events"|170982|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|S|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|T|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|H|7|V|8|@]|9|@]|A|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Non-ASCII characters (and many special characters) need to be escaped in a URL. Chrome and other browser do it automatically. And they unescape the URLs in the address bar for a nicer display.

So if you have a static URL, just paste it into the adressbar, press enter, selected the URL again, copy and paste it to your app:

So instead of:

<pre><code>let jsonUrl = "http://api.com/алматы/events"
</code></pre>

You'll get:

<pre><code>let jsonUrl = "http://api.com/%D0%B0%D0%BB%D0%BC%D0%B0%D1%82%D1%8B/events"
</code></pre>

blocks|key|2196860|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2196861|let+encodedUrl+=+jsonUrl.stringByAddingPercentEncodingWithAllowedCharacters(URLQueryAllowedCharacterSet)|code-block|syntax|javascript|2196862|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this:

<pre><code>let encodedUrl = jsonUrl.stringByAddingPercentEncodingWithAllowedCharacters(URLQueryAllowedCharacterSet)
</code></pre>

blocks|key|113064|text|就像这样：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|113065|let+apiHost+=+"http://api.com/"
let+apiPath+=+"алматы/events"
let+escapedPath+=+apiPath.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLHostAllowedCharacterSet())
let+url+=+NSURL(string:+"\(apiHost)\(escapedPath!)")|code-block|syntax|javascript|113066|显然，您应该做一些比强制展开escapedPath更聪明的事情。|offset|length|style|CODE|113067|将维基百科页面用于Swift作为示例：https://ru.wikipedia.org/wiki/Swift_(язык_программирования)|113068|变成：|113069|https://ru.wikipedia.org/wiki/Swift_(%25D1%258F%25D0%25B7%25D1%258B%25D0%25BA_%25D0%25BF%25D1%2580%25D0%25BE%25D0%25B3%25D1%2580%25D0%25B0%25D0%25BC%25D0%25BC%25D0%25B8%25D1%2580%25D0%25BE%25D0%25B2%25D0%25B0%25D0%25BD%25D0%25B8%25D1%258F)|113070|当粘贴到浏览器中时，可以将您带到正确的页面(而且大多数浏览器将方便地为您呈现UFT-8字符)。|113071|entityMap^0|0|0|E|B|0|J|1N|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@$I|Z|J|10|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|11|8|@$I|12|J|13|K|L]]|9|@]|A|$]]|$1|O|3|P|5|6|7|14|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|16|8|@]|9|@]|A|$]]|$1|U|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|V|$]]

Something like this:
<pre class="lang-swift prettyprint-override"><code>let apiHost = &quot;http://api.com/&quot;
let apiPath = &quot;алматы/events&quot;
let escapedPath = apiPath.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLHostAllowedCharacterSet())
let url = NSURL(string: &quot;\(apiHost)\(escapedPath!)&quot;)
</code></pre>
Obviously you should do something smarter than just force unwrap <code>escapedPath</code>.
Using the Wikipedia page for Swift as an example:
<code>https://ru.wikipedia.org/wiki/Swift_(язык_программирования)</code>
Becomes:
<pre><code>https://ru.wikipedia.org/wiki/Swift_(%D1%8F%D0%B7%D1%8B%D0%BA_%D0%BF%D1%80%D0%BE%D0%B3%D1%80%D0%B0%D0%BC%D0%BC%D0%B8%D1%80%D0%BE%D0%B2%D0%B0%D0%BD%D0%B8%D1%8F)
</code></pre>
Which when pasted into the browser takes you to the right page (and most browsers will conveniently render the UFT-8 characters for you).

blocks|key|112986|text|尝试在stringByAddingPercentEncodingWithAllowedCharacters：上定义的NSString。您可能会看到有人建议使用stringByAddingPercentEscapesUsingEncoding:，但在iOS+9中不推荐使用该方法。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|112987|基金会中也有一些预定义的NSCharacterSet，如URLHostAllowedCharacterSet和URLPathAllowedCharacterSet。因此，如果您真的必须在代码中解析未转义的URL+(使用可接受的答案中提到的预处理URL通常是一个更好的主意)，您可以编写如下帮助方法：|112988|import+Foundation

func+url(scheme+scheme:+String,+host:+String,+path:+String)+->+NSURL?+{
++++let+components+=+NSURLComponents()
++++components.scheme+=+scheme
++++components.host+=+host.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLHostAllowedCharacterSet())
++++components.path+=+path.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLPathAllowedCharacterSet())
++++return+components.URL
}

//+evaluates+to+http://api.com/%2525D0%2525B0%2525D0%2525BB%2525D0%2525BC%2525D0%2525B0%2525D1%252582%2525D1%25258B/events
url(scheme:+"http",+host:+"api.com",+path:+"/алматы/events")|code-block|syntax|javascript|112989|请注意，上面的文档提到|112990|此方法用于百分比-编码URL组件或子组件字符串，而不是整个URL字符串。|blockquote|112991|这是因为根据RFC+3986的说法，不是所有的网址都是百分比编码的(例如scheme+-http/https/等)。|112992|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.apple.com/library/ios/documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/#//apple_ref/occ/instm/NSString/stringByAddingPercentEncodingWithAllowedCharacters:|1|https://www.rfc-editor.org/rfc/rfc3986^0|27|16|3|1F|0|0|C|E|S|Q|1J|Q|0|0|0|0|10|6|6|8|1|0^^$0|@$1|2|3|4|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@$9|16|A|17|1|18]]|E|$]]|$1|F|3|G|5|6|7|19|8|@$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]|$9|1E|A|1F|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|1G|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1H|8|@]|D|@]|E|$]]|$1|O|3|P|5|Q|7|1I|8|@]|D|@]|E|$]]|$1|R|3|S|5|6|7|1J|8|@$9|1K|A|1L|B|C]]|D|@$9|1M|A|1N|1|1O]]|E|$]]|$1|T|3|-4|5|6|7|1P|8|@]|D|@]|E|$]]]|U|$V|$5|W|X|Y|E|$Z|10]]|11|$5|W|X|Y|E|$Z|12]]]]

Try <a href="https://developer.apple.com/library/ios/documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/#//apple_ref/occ/instm/NSString/stringByAddingPercentEncodingWithAllowedCharacters:" rel="nofollow noreferrer">stringByAddingPercentEncodingWithAllowedCharacters:</a> defined on NSString. You may see people suggesting <code>stringByAddingPercentEscapesUsingEncoding:</code>, but that method is deprecated in iOS 9.
There are also a few predefined <code>NSCharacterSet</code>s in Foundation, such as <code>URLHostAllowedCharacterSet</code> and <code>URLPathAllowedCharacterSet</code>. Therefore, if you really have to parse the unescaped URL in code (using preprocessed URLs, mentioned in the accepted answer, is usually a much better idea), you can write a helper method like this:
<pre><code>import Foundation

func url(scheme scheme: String, host: String, path: String) -&gt; NSURL? {
 let components = NSURLComponents()
 components.scheme = scheme
 components.host = host.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLHostAllowedCharacterSet())
 components.path = path.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLPathAllowedCharacterSet())
 return components.URL
}

// evaluates to http://api.com/%25D0%25B0%25D0%25BB%25D0%25BC%25D0%25B0%25D1%2582%25D1%258B/events
url(scheme: &quot;http&quot;, host: &quot;api.com&quot;, path: &quot;/алматы/events&quot;)
</code></pre>
Note that the above documentation mentions that
<blockquote>
This method is intended to percent-encode an URL component or subcomponent string, NOT an entire URL string.
</blockquote>
That's because according <a href="https://www.rfc-editor.org/rfc/rfc3986" rel="nofollow noreferrer">RFC 3986</a>, not all parts of an URL can be percent-encoded (e.g. <code>scheme</code> - http/https/etc.)

blocks|key|2196952|text|在xamarin：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2196953|var+uri+=+new+Uri+(url);
var+nsurl+=+new+NSUrl+(uri.GetComponents+(UriComponents.HttpRequestUrl,+UriFormat.UriEscaped));
UIApplication.SharedApplication.OpenUrl+(nsurl);|code-block|syntax|javascript|2196954|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

in xamarin:

<pre><code>var uri = new Uri (url);
var nsurl = new NSUrl (uri.GetComponents (UriComponents.HttpRequestUrl, UriFormat.UriEscaped));
UIApplication.SharedApplication.OpenUrl (nsurl);
</code></pre>

blocks|key|2196973|text|Swift+4|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|2196974|使用字符串扩展名创建一个名为String%2BExtension.swift的快速文件并粘贴此代码|2196975|import+UIKit
extension+String{
++++var+encodeUrl+:+String
++++{
++++++++return+self.addingPercentEncoding(withAllowedCharacters:+NSCharacterSet.urlQueryAllowed)!
++++}
++++var+decodeUrl+:+String
++++{
++++++++return+self.removingPercentEncoding!
++++}
}|code-block|syntax|javascript|2196976|并按如下方式使用：(根据问题进行抽样)：|2196977|"http://api.com/алматы/events".encodeUrl|2196978|entityMap^0|0|7|0|E|M|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@$9|W|A|X|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|Y|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|Z|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|10|8|@]|D|@]|E|$K|L]]|$1|Q|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|R|$]]

Swift 4 
Using String Extension
Create a swift file named String+Extension.swift and paste this code

<pre><code>import UIKit
extension String{
 var encodeUrl : String
 {
 return self.addingPercentEncoding(withAllowedCharacters: NSCharacterSet.urlQueryAllowed)!
 }
 var decodeUrl : String
 {
 return self.removingPercentEncoding!
 }
}
</code></pre>

and Use it like so: (sample according to question):

<pre><code>"http://api.com/алматы/events".encodeUrl
</code></pre>

App crashes with following url: 

<pre><code>let jsonUrl = "http://api.com/алматы/events"
let session = NSURLSession.sharedSession()
let shotsUrl = NSURL(string: jsonUrl)
let task = session.dataTaskWithURL(shotsUrl!)
</code></pre>

Log:

<pre><code>fatal error: unexpectedly found nil while unwrapping an Optional value
</code></pre>

It's because of cyrillic symbols in url. How can I solve this issue. Thanks for your help!

Cyrillic symbols in URL

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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应用程序崩溃的网址如下：let jsonUrl = "http://api.com/алматы/events"let session = NSURLSession.sharedSession()let shotsUrl = NSURL(string: jsonUrl)let task = session.dataTa...

问URL中的西里尔符号
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