如何在clojure中获得‘How’函数的输出？
如何在clojure中获得‘How’函数的输出？
提问于 2016-02-16 04:21:59
我试图保存doc函数的输出，例如：
user> (def doc-str-split (doc str/split))
-------------------------
clojure.string/split
([s re] [s re limit])
Splits string on a regular expression. Optional argument limit is
the maximum number of splits. Not lazy. Returns vector of the splits.
#'user/doc-str-split
user> doc-str-split
nil
user> 然而，我得到了nil的doc-str-split。我试图获得type的doc输出：
user> (type (doc str/split))
-------------------------
clojure.string/split
([s re] [s re limit])
Splits string on a regular expression. Optional argument limit is
the maximum number of splits. Not lazy. Returns vector of the splits.
nil还能拿到nil。如何保存doc函数的输出？
回答 2
Stack Overflow用户
回答已采纳
发布于 2016-02-16 04:54:09
您可以使用with-out-str捕获输出，如下所示：
user> (def doc-str-split (with-out-str (doc str/split)))
#'user/doc-str-split
user> (println doc-str-split)
-------------------------
clojure.string/split
([s re] [s re limit])
Splits string on a regular expression. Optional argument limit is
the maximum number of splits. Not lazy. Returns vector of the splits.
nil
user> (type (with-out-str (doc str/split)))
java.lang.StringStack Overflow用户
发布于 2016-02-16 05:46:40
您可以得到如下所示的文档字符串：
user.core=> (def doc (prn (:doc (meta #'clojure.string/split))))
"Splits string on a regular expression. Optional argument limit is
the maximum number of splits. Not lazy. Returns vector of the splits."页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/35423694
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