C# Xml --System.Xml.XmlException类型的未处理异常发生在System.Xml.dll中
C# Xml --System.Xml.XmlException类型的未处理异常发生在System.Xml.dll中
提问于 2016-03-01 14:33:36
private void Form1_FormClosing(object sender, FormClosingEventArgs e) //Save On Form Closing
{
XmlDocument xDoc = new XmlDocument();
xDoc.Load(path + "\\Address Book - Me \\settings.xml");
XmlNode xNode = xDoc.SelectSingleNode("People");
xNode.RemoveAll();
foreach (Person pe in people)
{
XmlNode xTop = xDoc.CreateElement("People");
XmlNode xName = xDoc.CreateElement("Name");
XmlNode xLastName = xDoc.CreateElement("LastName");
XmlNode xStreet = xDoc.CreateElement("Address");
XmlNode xPhone = xDoc.CreateElement("Phone");
XmlNode xEmail = xDoc.CreateElement("Email");
XmlNode xDate = xDoc.CreateElement("Birth");
XmlNode xCity = xDoc.CreateElement("City");
XmlNode xState = xDoc.CreateElement("State");
XmlNode xCountry = xDoc.CreateElement("Country");
XmlNode xDetails = xDoc.CreateElement("Detail");
xName.InnerText = pe.Name;
xLastName.InnerText = pe.LastName;
xStreet.InnerText = pe.StreetAdress;
xPhone.InnerText = pe.Phone;
xEmail.InnerText = pe.Email;
xDate.InnerText = pe.Date.ToFileTime().ToString();
xCity.InnerText = pe.City;
xState.InnerText = pe.State;
xCountry.InnerText = pe.Country;
xDetails.InnerText = pe.Details;
xTop.AppendChild(xName);//adding a new node
xTop.AppendChild(xLastName);
xTop.AppendChild(xStreet);
xTop.AppendChild(xPhone);
xTop.AppendChild(xEmail);
xTop.AppendChild(xDate);
xTop.AppendChild(xCity);
xTop.AppendChild(xState);
xTop.AppendChild(xCountry);
xTop.AppendChild(xDetails);
xDoc.DocumentElement.AppendChild(xTop);
}
xDoc.Save(path + "\\Address Book - Me \\settings.xml");//在重新启动应用程序之后，我正在尝试制作一个保存信息并重新加载它们的洋芋。但是当我关闭我的程序时，没有什么是可行的，仅此而已：
Xml是一个未处理的'System.Xml.XmlException‘类型异常，出现在System.Xml.dll中，附加信息:根元素丢失。
请帮帮我。
注释:异常是在这里引发的：xDoc.Load(path + "\\Address Book - Me \\settings.xml");
回答 2
Stack Overflow用户
发布于 2016-05-24 14:28:56
用.xml文件删除您的文件夹。然后用这个创建了一个新的.xml文件。
XmlTextWriter xW = new XmlTextWriter(YourPath, YourEncoding);
xW.WriteStartElement(Your Tag);
xW.WriteEndElement();
xW.Close(); Stack Overflow用户
发布于 2016-05-24 14:50:28
最简单的方法是使用XmlSerialization，如下例所示。
using System;
using System.Collections.Generic;
using System.IO;
using System.Xml.Serialization;
namespace ConsoleApplication1
{
public class Program
{
static void Main(string[] args)
{
var settings = new Settings();
settings.People.Add(new Person { Name = "Name", LastName = "LastName", City="City", Country="Country", Date="11/11/11", Details="Details", Email="Email", Phone="Phone", State="State", Street="Steet" });
settings.Save("c:\\test.xml");
settings = Settings.TryLoad("c:\\test.xml");
}
[Serializable]
public class Settings
{
public Settings()
{
}
public List<Person> People
{
get { return people; }
set { people = value; }
}
List<Person> people = new List<Person>();
public void Save(string path)
{
XmlSerializer xs = new XmlSerializer(typeof(Settings));
using (var sw = new StreamWriter(File.Open(path, FileMode.OpenOrCreate)))
{
xs.Serialize(sw, this);
}
}
public static Settings TryLoad(string path)
{
Settings settings = null;
XmlSerializer xs = new XmlSerializer(typeof(Settings));
using (var sw = new StreamReader(File.OpenRead(path)))
{
try
{
settings = xs.Deserialize(sw) as Settings;
}
catch (Exception)
{
// skip
}
}
return settings;
}
}
[Serializable]
public class Person
{
public Person()
{
}
public string Name { get; set; }
public string LastName { get; set; }
public string Street { get; set; }
public string Phone { get; set; }
public string Email { get; set; }
public string Date { get; set; }
public string City { get; set; }
public string State { get; set; }
public string Country { get; set; }
public string Details { get; set; }
}
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/35725646
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