给定一个图像url,我如何将该图像上传到,以便使用Node.js进行图像处理?
发布于 2016-04-16 08:43:47
这是两个步骤的过程:
如果要将文件保存为jpeg映像,则需要编辑remoteWriteStream流并添加自定义元数据:
var image = bucket.file('zebra.jpg');
localReadStream.pipe(image.createWriteStream({
metadata: {
contentType: 'image/jpeg',
metadata: {
custom: 'metadata'
}
}
}))
我在挖掘这个文档的时候发现了这个
发布于 2017-06-16 07:23:05
为了添加到Yevgen Safronov的答案中,我们可以将请求传输到写流中,而无需显式地将图像下载到本地文件系统中。
const request = require('request');
const storage = require('@google-cloud/storage')();
function saveToStorage(attachmentUrl, bucketName, objectName) {
const req = request(attachmentUrl);
req.pause();
req.on('response', res => {
// Don't set up the pipe to the write stream unless the status is ok.
// See https://stackoverflow.com/a/26163128/2669960 for details.
if (res.statusCode !== 200) {
return;
}
const writeStream = storage.bucket(bucketName).file(objectName)
.createWriteStream({
// Tweak the config options as desired.
gzip: true,
public: true,
metadata: {
contentType: res.headers['content-type']
}
});
req.pipe(writeStream)
.on('finish', () => console.log('saved'))
.on('error', err => {
writeStream.end();
console.error(err);
});
// Resume only when the pipe is set up.
req.resume();
});
req.on('error', err => console.error(err));
}
发布于 2016-11-30 20:57:15
在处理从远程网址上传的图像的情况下。参考Google文档提供的最新库。而不是存储图像的缓冲区。我们可以直接把它送到储藏室。
function sendUploadUrlToGCS(req, res, next) {
if (!req.body.url) {
return next();
}
var gcsname = Date.now() + '_name.jpg';
var file = bucket.file(gcsname);
return request({url: <remote-image-url>, encoding: null}, function(err, response, buffer) {
req.file = {};
var stream = file.createWriteStream({
metadata: {
contentType: response.headers['content-type']
}
});
stream.on('error', function(err) {
req.file.cloudStorageError = err;
console.log(err);
next(err);
});
stream.on('finish', function() {
req.file.cloudStorageObject = gcsname;
req.file.cloudStoragePublicUrl = getPublicUrl(gcsname);
next();
});
stream.end(buffer);
});
}
https://stackoverflow.com/questions/36661795
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