blocks|key|2094357|text|如果find()方法成功返回一个正索引，则为-1。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2094358|您应该逐行循环内容，如下所示：|2094359|for+line+in+myFile:
++++if+line.find(playerName):
++++++++print(line)|code-block|syntax|javascript|2094360|entityMap^0|2|6|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|S|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

<code>find()</code> method returns a positive index if it succeeds, -1 otherwise

You should loop on your content line by line, as follows:

<pre><code>for line in myFile:
 if line.find(playerName):
 print(line)
</code></pre>

blocks|key|2092721|text|使用str方法将需要更多的杂技。尝试以下几点，|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2092722|import+re
p+=+re.compile(r"\b{}\b".format(playername))+#+keep+it+ready

#+inside+option+B
for+line+in+myfile:++++#+no+need+to+`.read()`+it
++++match+=+p.search(line)
++++if+match:
++++++++print(line)
++++++++break+++#+if+there+is+only+one+record+for+playername|code-block|syntax|javascript|2092723|看看它对你有用吗。|2092724|entityMap^0|2|3|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

Working with <code>str</code> methods will take more acrobatics. Try the following,

<pre><code>import re
p = re.compile(r"\b{}\b".format(playername)) # keep it ready

# inside option B
for line in myfile: # no need to `.read()` it
 match = p.search(line)
 if match:
 print(line)
 break # if there is only one record for playername
</code></pre>

See if it works for you.

blocks|key|1724032|text|这里类似的事情：Reading+specific+lines+only+(Python)|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1724033|fp+=+open("file")
for+i,+line+in+enumerate(fp):
++++if+line+==+playername:
++++++++print+line

fp.close()|code-block|syntax|javascript|1724034|我还注意到你没有为每一个决定关闭你的文件，应该做到这一点。|1724035|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/2081836/reading-specific-lines-only-python^0|8|10|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|C|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

similar thing here: 
<a href="https://stackoverflow.com/questions/2081836/reading-specific-lines-only-python">Reading specific lines only (Python)</a>

<pre><code>fp = open("file")
for i, line in enumerate(fp):
 if line == playername:
 print line

fp.close()
</code></pre>

I also notice you don't close your file for each decision, should make that happen.

blocks|key|1724081|text|我这边几分钱：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1724082|file+=+open("file")
lines+=+file.readlines()
for+line+in+lines:
++++if+playername+in+line:
++++++++print+line

file.close()|code-block|syntax|javascript|1724083|希望它能成功！|1724084|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

A few cents from my side :

<pre><code>file = open("file")
lines = file.readlines()
for line in lines:
 if playername in line:
 print line

file.close()
</code></pre>

Hope it works!

blocks|key|963197|text|一种更安全的读取文件和查找数据的方法，以便在将整个文件存储在内存中时不会出现OutOfMemory问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|963198|playerName+=+input("Enter+a+player+name+to+view+their+scores:+")
with+open("Scores.txt",+'r')+as+f:
++++for+row+in+f:
++++++++if+playerName+in+row:
++++++++++++print+row|code-block|syntax|javascript|963199|这样，您将使用with，它将在程序结束时或垃圾收集启动时自行关闭文件。这样，python将逐行读取文件，并且只在内存中存储1行。因此，您可以使用巨大的文件，而不必担心内存问题。|offset|length|style|CODE|963200|希望它有帮助:)|963201|entityMap^0|0|0|7|4|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

A safer way to read the file and find data, so that you will not have OutOfMemory issues when storing the whole file in memory.

<pre><code>playerName = input("Enter a player name to view their scores: ")
with open("Scores.txt", 'r') as f:
 for row in f:
 if playerName in row:
 print row
</code></pre>

This way you will be using <code>with</code> that will close the file by itself either when the program ends or Garbage Collection kicks in. This way python will read the file line by line and store only 1 line in memory. So you can use huge files and do not worry about memory issues.

Hope it helps :)

blocks|key|963293|text|很少的python成语和小的优化|type|unstyled|depth|inlineStyleRanges|entityRanges|data|963294|这里有很多答案，我的示例引入了一些python成语，并对其进行了一些优化：|963295|fname+=+"Scores.txt"
player_name+=+"Quido"

with+open(fname)+as+f:
++++for+line+in+f:
++++++++if+player_name+in+line:
++++++++++++print+line
++++++++++++break
print+"Going+on+doing+following+tasks."|code-block|syntax|javascript|963296|with块将在退出内部块时关闭打开的文件。不需要f.close()，安全的情况下，读取文件的问题。|offset|length|style|CODE|963297|for+line+in+f:显示，在文本模式下对打开的文件进行迭代，我们每次迭代得到一行。|963298|当我们与玩家一起打印线后，break将有效地停止对行的迭代，假设只有一条这样的线，或者我们对第一条线很满意。如果不是这样，则删除break允许打印包含播放机名称的所有行。|963299|由于从文本文件迭代器返回的行包含新行，因此您可能更愿意删除它们。在这种情况下使用print+line.strip()将从行的开始和结束中删除所有空白字符。|963300|最后打印正在证明，程序继续在它处理所有的行。|963301|可能发生的情况是，您没有获得名称的输出，而该输出似乎在文件中。在这种情况下，您可能需要澄清信函的情况。例如，如果文本文件中包含所有名称，则必须正确地输入名称。|963302|其他选项是将player_name小写，并将其与小写大小写行进行比较：|963303|fname+=+"Scores.txt"
player_name+=+"Quido"
normalized_player_name+=+player_name.lower()

with+open(fname)+as+f:
++++for+line+in+f:
++++++++if+normalized_player_name+in+line.lower():
++++++++++++print+line.strip()
++++++++++++break++#+comment+out+to+print+all+lines+with+the+player
print+"Going+on+doing+following+tasks."|963304|请注意，我们将循环外部的player_name标准化，使其更快一些。循环内部的小写可以工作，但也会重复执行相同的任务。|963305|这一行是使用精确的字母箱打印的，就像在文件中一样。|963306|entityMap^0|0|0|0|0|4|O|9|0|0|E|0|D|5|1S|5|0|14|I|0|0|0|0|0|C|B|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|19|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|1A|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|1B|8|@$K|1C|L|1D|M|N]|$K|1E|L|1F|M|N]]|9|@]|A|$]]|$1|O|3|P|5|6|7|1G|8|@$K|1H|L|1I|M|N]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1J|8|@$K|1K|L|1L|M|N]|$K|1M|L|1N|M|N]]|9|@]|A|$]]|$1|S|3|T|5|6|7|1O|8|@$K|1P|L|1Q|M|N]]|9|@]|A|$]]|$1|U|3|V|5|6|7|1R|8|@]|9|@]|A|$]]|$1|W|3|X|5|6|7|1S|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|6|7|1T|8|@]|9|@]|A|$]]|$1|10|3|11|5|F|7|1U|8|@]|9|@]|A|$G|H]]|$1|12|3|13|5|6|7|1V|8|@$K|1W|L|1X|M|N]]|9|@]|A|$]]|$1|14|3|15|5|6|7|1Y|8|@]|9|@]|A|$]]|$1|16|3|-4|5|6|7|1Z|8|@]|9|@]|A|$]]]|17|$]]

<h2>Few python idioms and small optimization</h2>

Here are many answer, my sample brings in few python idioms and optimize it a bit:

<pre><code>fname = "Scores.txt"
player_name = "Quido"

with open(fname) as f:
 for line in f:
 if player_name in line:
 print line
 break
print "Going on doing following tasks."
</code></pre>

The <code>with</code> block will close the open file on exiting the inner block. No need to <code>f.close()</code>, safe
in case of problems to read the file.

<code>for line in f:</code> shows, that iterating over file open in text mode we get one line per iteration.

<code>break</code> after we print the line with the player will effectively stop iterating over lines assuming,
there is only one such line or that we are happy with the very first one. If this is not the case,
removing the <code>break</code> allows printing all lines containing the player name.

As lines returned from text file iterator contain new line, you may prefer to get rid of them. Use
<code>print line.strip()</code> in such case what will remove all blank characters from start and end of the line.

Final print is proving, the program continues after it processes all the lines.

It may happen, that you get no output for name, which appears to be present in the file. In such a
case, you might need to clarify letter case. For example, if your text file contains all the names
in exact casing, you have to enter the name properly.

Other option is to lower-case the player_name and compare it against lower cased line:

<pre><code>fname = "Scores.txt"
player_name = "Quido"
normalized_player_name = player_name.lower()

with open(fname) as f:
 for line in f:
 if normalized_player_name in line.lower():
 print line.strip()
 break # comment out to print all lines with the player
print "Going on doing following tasks."
</code></pre>

Note, that we normalize the <code>player_name</code> outside from the loop to be a bit faster. Lower-casing inside the
loop would work, but would do the same task repeatedly.

The line is printed using exact letter cases as in the file.

I am trying to print a specific line from the file "Scores", which is option B. This is my code:

<pre><code>print("Option A: Show all scores\nOption B: Show a record\nOption Q: Quit")
decision = input("Enter A, B, C or Q: ")
myFile = open("Scores.txt", "rt")
if decision == "A":
 record = myFile.read()
 print(record)
 myFile.close()
elif decision == "B" or decision == "b":
 playerName = input("Enter a player name to view their scores: ")
 record = myFile.read()
 answer = record.find(playerName)
 for line in answer:
 print(line)
elif decision == "Q" or decision == "q":
 exit
</code></pre>

I went for Option B, then I entered a player name that holds the score of the player, but it throws this error message:

<pre><code>line 12, in &lt;module&gt;
for line in answer():
TypeError: 'int' object is not callable
</code></pre>

How to print a specific line from a file

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我试图从文件“分数”中打印一个特定的行，这是选项B。这是我的代码：print("Option A: Show all scores\nOption B: Show a record\nOption Q: Quit")decision = input("Enter A, B, C or Q: ")myFile = ope...

问如何从文件中打印特定行
EN

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问如何从文件中打印特定行EN