我主要想做的是:
select * from request where id = 1 and created_at like (today's date);但要用雄辩。
我试过:
$query = m_requests::where(['id' => Auth::User()->id, "created_at", "like", "%".date("Y-m-d")."%"]);但这会返回错误:
SQLSTATE[42S22]: Column not found: 1054 Unknown
column '0' in 'where clause' (SQL: select * from
from `request` where (`id` = 1 and `0` = created_at
and `1` = like and `2` = %2016-04-22%))有人知道我怎样才能做到我想做的事吗?
总之:我希望id等于所请求的id,但我希望日期“类似”今天的日期(这是因为我只对创建它的日期感兴趣,而不是它创建的时间)。
干杯
发布于 2016-04-22 12:50:39
试一试,它应该能起作用:
m_requests::where('id', '=', Auth::user()->id)
->where('created_at', 'LIKE', '%'.date("Y-m-d").'%');https://stackoverflow.com/questions/36793986
复制相似问题