从列表字典中找到最小的键子集
对于一个练习，我必须确定一个最小的蛋白质组子集，其中包含所有给定的蛋白质。我可以使用的对象如下所示：
以蛋白质组ID作为密钥的列表字典和包含在其中的蛋白质ID的列表。我也有一系列的蛋白质ID。多个蛋白质组可以有相同的蛋白质ID。
问题：找到包含数组中所有蛋白质的最小蛋白质组子集。
Visualisation:
列表字典
{'UP000040088': ['A0A0T9TGA2', 'A0A0T9PBK6'],'UP000005347': ['I2WKK5', 'I2W7Q9', 'I2WH23', 'I2W8G3', 'I2W8S8', 'I2WCH8', 'I2WCJ2', 'I2WA21', 'I2WC26', 'I2WCG9', 'I2W9F2', 'I2WKG5', 'I2W4G7', 'I2WCD6', 'I2WG92', 'I2W6I6', 'I2W648', 'I2WE51', 'I2WKU2', 'I2WIG4', 'I2WED9', 'I2WEM0', 'I2WB05', 'I2W998', 'I2W7Q9', 'I2WA37', 'I2WD89', 'I2WEB4', 'I2W4G7', 'I2W4B1', 'I2WIM9', 'I2WI84', 'I2WIS6', 'I2WES7', 'I2WGL9', 'I2WIA8', 'I2W7H0', 'I2WDB3', 'I2WE60', 'I2WC93', 'I2WC36', 'I2WC86', 'I2WC82', 'I2W6J9', 'I2W428', 'I2WCH8', 'I2WCJ2', 'I2W9T1', 'I2W9B9', 'I2WC26', 'I2WCG9', 'I2WA28', 'I2WA21', 'I2W648', 'I2WE51', 'I2WKU2', 'I2WIG4', 'I2WEM0', 'I2WED9', 'I2W9F2'], 'UP000001592': ['A9IMD2', 'A9IU64', 'A9IWM9', 'A9IWP5', 'A9IZ28', 'A9IZ30', 'A9IZ48', 'A9IZ71', 'A9IZ73', 'A9IZ75']}
数组
['A9IWM9', 'A9IWP5','A0A0T9PBK6']
这个例子中的输出应该是
'UP000040088':['A0A0T9PBK6'],'UP000001592':['A9IWM9', 'A9IWP5']
诚挚的问候
回答 1
Stack Overflow用户
发布于 2016-05-02 14:16:38
不需要在for循环中使用附加和避免方法.
dct={'UP000040088': ['A0A0T9TGA2', 'A0A0T9PBK6'],'UP000005347': ['I2WKK5', 'I2W7Q9', 'I2WH23', 'I2W8G3', 'I2W8S8', 'I2WCH8', 'I2WCJ2', 'I2WA21', 'I2WC26', 'I2WCG9', 'I2W9F2', 'I2WKG5', 'I2W4G7', 'I2WCD6', 'I2WG92', 'I2W6I6', 'I2W648', 'I2WE51', 'I2WKU2', 'I2WIG4', 'I2WED9', 'I2WEM0', 'I2WB05', 'I2W998', 'I2W7Q9', 'I2WA37', 'I2WD89', 'I2WEB4', 'I2W4G7', 'I2W4B1', 'I2WIM9', 'I2WI84', 'I2WIS6', 'I2WES7', 'I2WGL9', 'I2WIA8', 'I2W7H0', 'I2WDB3', 'I2WE60', 'I2WC93', 'I2WC36', 'I2WC86', 'I2WC82', 'I2W6J9', 'I2W428', 'I2WCH8', 'I2WCJ2', 'I2W9T1', 'I2W9B9', 'I2WC26', 'I2WCG9', 'I2WA28', 'I2WA21', 'I2W648', 'I2WE51', 'I2WKU2', 'I2WIG4', 'I2WEM0', 'I2WED9', 'I2W9F2'], 'UP000001592': ['A9IMD2', 'A9IU64', 'A9IWM9', 'A9IWP5', 'A9IZ28', 'A9IZ30', 'A9IZ48', 'A9IZ71', 'A9IZ73', 'A9IZ75']}
a = ['A9IWM9', 'A9IWP5','A0A0T9PBK6']
match={k:[None for _ in a] for k in dct.keys()}
for k,lst in dct.items():
n=0
for ai in a:
if ai in lst:
match[k][n]=ai
n+=1
print match # {'UP000040088': [None, None, 'A0A0T9PBK6'], 'UP000005347': [None, None, None], 'UP000001592': ['A9IWM9', 'A9IWP5', None]}
match={k:[vi for vi in v if not vi is None] for k,v in match.items()}
print match # {'UP000040088': ['A0A0T9PBK6'], 'UP000005347': [], 'UP000001592': ['A9IWM9', 'A9IWP5']}
match={k:v for k,v in match.items() if len(v)}
print match # {'UP000040088': ['A0A0T9PBK6'], 'UP000001592': ['A9IWM9', 'A9IWP5']}https://stackoverflow.com/questions/36983967
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