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社区首页 >问答首页 >兼工作任务

兼工作任务
EN

Stack Overflow用户
提问于 2016-05-19 21:23:41
回答 2查看 78关注 0票数 0

我试着准备一个简单的程序,它允许用户创建很少的并发工作任务。没有什么特别事情。每个任务从值1开始,并在达到最大值时再添加1(每个任务得到不同的最大值)。然后任务通知,指定的值已经到达并停止。所有任务都必须包含在我所做的ArrayList中。我需要提供方法,这允许(在任何时候)

  1. 检查任务的状态
  2. 检查任务的结果
  3. 单独地或全部地完成任务
  4. 显示列表,其中包含所有任务(名称、值、状态)

我宁愿避开桂,因为这不是我的教授所要求的。我已经参与其中了,但是我不知道如何打印列表的所有元素(TASK_LIST)并停止单个任务。

MAIN.java

代码语言:javascript
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import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;

public class Main {

  public static void main(String[] args) {

    ExecutorService exec = Executors.newCachedThreadPool();

    Task t1 = new Task("Task 1", 2);
    Task t2 = new Task("Task 2", 20);
    Task t3 = new Task("Task 3", 5);

    exec.execute(t1);
    exec.execute(t2);
    exec.execute(t3);

    //showTASK_LIST();

  }
}

TASK.java

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    import java.util.ArrayList;
    import java.util.List;

    class Task implements Runnable {
        String TASK_NAME;
        int TASK_RESULT;
        int TASK_GOAL;
        String TASK_STATUS;
        static List<Task> TASK_LIST = new ArrayList<Task>();

        public Task(String name, int goal) {
            this.TASK_NAME = name;
            this.TASK_GOAL = goal;
            this.TASK_STATUS = "INACTIVE";
            TASK_LIST.add(this);
        }

        public void run() {
            TASK_STATUS="ACTIVE";
            System.out.println(TASK_NAME + " starts.");
            while (TASK_RESULT != TASK_GOAL){
                //if (Thread.currentThread().isInterrupted()) return;
                TASK_RESULT++;
                System.out.println(TASK_NAME + " " + TASK_RESULT);
                try {
                    Thread.sleep(500);
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
                Thread.yield();

            }
            System.out.println("===========================================\n" + 
                                TASK_NAME + " has been completed. Final result = " + TASK_GOAL +
                                "\n===========================================" );
            setTASK_STATUS("COMPLETED");
            System.out.println(TASK_LIST.size());


        }

        //Method to check current result
        public int getTASK_RESULT() {
            return TASK_RESULT;
        }

        //Method to check current status
        public String getTASK_STATUS() {
            return TASK_STATUS;
        }

        //Method to change result
        public void setTASK_STATUS(String status) {
            TASK_STATUS = status;
        }

        //This part doesnt work
        public showTASK_LIST(){
            for(int i = 0; i <= TASK_LIST.size(); i++){
                System.out.println(TASK_LIST.get(i).TASK_NAME);
            }

        }

    }

它就是这样看待这个时刻的。

EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2016-05-19 21:59:03

您需要使您的showTASK_LIST()保持静态。然后你可以用Task.showTASK_LIST();调用它

就像下面

代码语言:javascript
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   public static void showTASK_LIST(){
        for(int i = 0; i <= TASK_LIST.size(); i++){
            System.out.println(TASK_LIST.get(i).TASK_NAME);
        }

Task.showTASK_LIST();//goes in your main method to show the tasks

运行您的代码时得到的结果在上面的代码中产生了一个indexOutOfBounds异常。这是一个简单的解决办法。

将for循环更改为

代码语言:javascript
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for(int i = 0; i < TASK_LIST.size(); i++)// changed <= to <

只有3个任务,<=上升到第四个任务,造成问题

我得到了这个输出

代码语言:javascript
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Task 1 starts.
Task 3 starts.
Task 3 1
Task 1
Task 2
Task 3
Task 2 starts.
Task 1 1
Task 2 1
Task 3 2
Task 1 2
Task 2 2
Task 3 3
===========================================
Task 1 has been completed. Final result = 2
===========================================
Task 2 3
3
Task 3 4
Task 2 4
Task 2 5
Task 3 5
Task 2 6
===========================================
Task 3 has been completed. Final result = 5
===========================================
3
Task 2 7
Task 2 8
Task 2 9
Task 2 10
Task 2 11
Task 2 12
Task 2 13
Task 2 14
Task 2 15
Task 2 16
Task 2 17
Task 2 18
Task 2 19
Task 2 20
===========================================
Task 2 has been completed. Final result = 20
===========================================
3
票数 1
EN

Stack Overflow用户

发布于 2016-05-24 15:40:06

您的代码存在线程安全问题,因为您试图从多个线程读取/写入共享资源上的值(在本例中为Task对象):

您正在从一个线程中更改任务状态(写),并尝试从不同的线程(读)读取它(主线程是这样的):

代码语言:javascript
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Task.showTASK_LIST()

同样的问题还涉及:

代码语言:javascript
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      //Method to check current result
    public int getTASK_RESULT() {
        return TASK_RESULT;
    }

    //Method to check current status
    public String getTASK_STATUS() {
        return TASK_STATUS;
    }

您可以在:safety https://docs.oracle.com/javase/tutorial/essential/concurrency/上阅读有关Java并发性和线程安全的信息。

在重用代码时,我将提供自己的实现,但在您查看代码之前,请注意以下几个键注释:

  1. 使用可调用接口而不是Runnable,因为您希望在处理结束时返回结果(可调用与Runnable类似,但可以返回结果。
  2. 使用Executor ()方法返回未来对象(未来有许多有用的方法,如: isDone()、cancel()、get()等)
  3. 管理主线程中和任务类之外的任务列表

StatusChangeListener

代码语言:javascript
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public interface StatusChangeListener {

  void statusChanged(String oldStatus, String newStatus);
}

代码语言:javascript
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import java.util.ArrayList;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;

public class Main {

  public static void main(String[] args) {

    ExecutorService executor = Executors.newCachedThreadPool();

    //manage your tasks list here
    ArrayList<Task> tasks = new ArrayList<>();
    Task t1 = new Task("Task 1", 2);
    Task t2 = new Task("Task 2", 20);
    Task t3 = new Task("Task 3", 5);

    tasks.add(t1);
    tasks.add(t2);
    tasks.add(t3);

    //add status change listener to be notified for t1 status changes
    t1.addStatusChangeListener(new MyListener());

    System.out.println("tasks = " + tasks);

    //use submit instead of execute
    Future<Integer> future1 = executor.submit(t1);

    System.out.println("task 1 is done = " + future1.isDone());

    Future<Integer> future2 = executor.submit(t2);
    Future<Integer> future3 = executor.submit(t3);
    //cancel task 3
    future3.cancel(true);

    try {
      System.out.println("future 1 result= " + future1.get());
      System.out.println("future 2 result= " + future2.get());
    } catch (InterruptedException e) {
      e.printStackTrace();
    } catch (ExecutionException e) {
      e.printStackTrace();
    }
  }

  //you can do the same with the progress. e.g. add progress listener
  private static class MyListener implements StatusChangeListener{

    @Override
    public void statusChanged(String oldStatus, String newStatus) {
      System.out.println(String.format("Thread : %s status changed from %s to %s", Thread.currentThread(), oldStatus, newStatus));
    }
  }

}

任务

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import java.util.concurrent.Callable;

class Task implements Callable<Integer> {

  //can be replaced by enum
  private String TASK_STATUS;
  private String TASK_NAME;
  private int TASK_RESULT;
  private int TASK_GOAL;
  private StatusChangeListener statusChangeListener;


  public Task(String name, int goal) {
    this.TASK_NAME = name;
    this.TASK_GOAL = goal;
    this.TASK_STATUS = "INACTIVE";
  }

  //private Method to change result
  private void setTASK_STATUS(String newStatus) {
    String oldStatus = TASK_STATUS;
    TASK_STATUS = newStatus;
    //notify status changes
    if (statusChangeListener != null)
      statusChangeListener.statusChanged(oldStatus, newStatus);
  }

  @Override
  public Integer call() throws Exception {
    setTASK_STATUS("ACTIVE");
    System.out.println(TASK_NAME + " starts.");
    while (TASK_RESULT != TASK_GOAL) {
      //if (Thread.currentThread().isInterrupted()) return;
      TASK_RESULT++;
      System.out.println(TASK_NAME + " " + TASK_RESULT);
      try {
        Thread.sleep(500);
      } catch (InterruptedException e) {
        e.printStackTrace();
      }
      Thread.yield();

    }
    System.out.println("===========================================\n" +
            TASK_NAME + " has been completed. Final result = " + TASK_GOAL +
            "\n===========================================");
    setTASK_STATUS("COMPLETED");
    return TASK_RESULT;
  }

  public void addStatusChangeListener(StatusChangeListener statusChangeListener) {
    this.statusChangeListener = statusChangeListener;
  }
}
票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/37334252

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