生成包含范围的所有字典组合
生成包含范围的所有字典组合
提问于 2016-05-25 09:32:37
在julia中，我有一本字典，它可以包含其他字典、字符串/数字列表、字典列表、字符串/数字和范围。
我需要一个列表，包含每个范围(如StepRange、FloatRange、UnitRange)的所有可能的字典组合--它包含在其中。
示例：
Dict{}("A" => Dict{}("B" => 1:1:3, "C" => 2), "B" => [Dict{}( "S" => 1:1.1:2.1)])=>
[
Dict{}("A" => Dict{}("B" => 1, "C" => 2), "B" => [Dict{}( "S" => 1.1)]),
Dict{}("A" => Dict{}("B" => 2, "C" => 2), "B" => [Dict{}( "S" => 1.1)]),
Dict{}("A" => Dict{}("B" => 3, "C" => 2), "B" => [Dict{}( "S" => 1.1)]),
Dict{}("A" => Dict{}("B" => 1, "C" => 2), "B" => [Dict{}( "S" => 2.1)]),
Dict{}("A" => Dict{}("B" => 2, "C" => 2), "B" => [Dict{}( "S" => 2.1)]),
Dict{}("A" => Dict{}("B" => 3, "C" => 2), "B" => [Dict{}( "S" => 2.1)])
]现在，我正在重载这样的递归函数，但是不知道如何继续。
function iterate(generic, nets::Array)
return (generic, false)
end
function iterate(range::Union{StepRange,FloatRange,UnitRange}, nets::Array)
return (collect(range), true)
end
function iterate(array::Array, nets::Array)
for (n, v) in enumerate(array)
res = iterate(v, nets)
if res[2]
## We found a range! Return it
return res
end
end
return (array, false)
end
function iterate(dict::Dict, nets::Array)
for (k, v) in dict
res = iterate(v, nets)
if res[2]
return (dict, true)
end
end
return (dict, false)
end(我已经在python中这样做了，但是使用regex查找自定义范围(比如"1,2,0.1")并在生成文本代码解析之后处理文本。
回答 1
Stack Overflow用户
回答已采纳
发布于 2016-05-25 22:44:27
下面的代码片段再现了示例中的输出，它可以作为其他变量的基础，这些变量以不同的方式处理递归(正如我在尝试时注意到的那样，有许多选项)。它使用与Iterators.jl一起安装的Pkg.add("Iterators")。
using Iterators
function findranges{K}(sd::Dict{K})
ranges = Vector{Vector}()
for v in values(sd)
if isa(v,Range)
push!(ranges,collect(v))
elseif isa(v,Dict)
push!(ranges,recdictcollect(v))
elseif isa(v,Vector)
push!(ranges,map(x->vcat(x...),collect(product(map(recdictcollect,v)...))))
end
end
ranges
end
function recdictcollect{K}(sd::Dict{K})
ranges = findranges(sd)
if length(ranges)==0
cases = [()]
else
cases = product(ranges...) |> collect
end
outv = Vector{Dict{K,Any}}()
for c in cases
newd = Dict{K,Any}()
i = 1
for (k,v) in sd
if any([isa(v,t) for t in [Range,Dict,Vector]])
newd[k] = c[i]
i += 1
else
newd[k] = v
end
end
push!(outv,newd)
end
return outv
end举个例子：
julia> example = Dict{}("A" => Dict{}("B" => 1:1:3, "C" => 2), "B" => [Dict{}( "S" => 1:1.1:2.1)])
Dict{ASCIIString,Any} with 2 entries:
"B" => [Dict("S"=>1.0:1.1:2.1)]
"A" => Dict{ASCIIString,Any}("B"=>1:1:3,"C"=>2)
julia> recdictcollect(example)
6-element Array{Dict{ASCIIString,Any},1}:
Dict{ASCIIString,Any}("B"=>[Dict{ASCIIString,Any}("S"=>1.0)],"A"=>Dict{ASCIIString,Any}("B"=>1,"C"=>2))
Dict{ASCIIString,Any}("B"=>[Dict{ASCIIString,Any}("S"=>2.1)],"A"=>Dict{ASCIIString,Any}("B"=>1,"C"=>2))
Dict{ASCIIString,Any}("B"=>[Dict{ASCIIString,Any}("S"=>1.0)],"A"=>Dict{ASCIIString,Any}("B"=>2,"C"=>2))
Dict{ASCIIString,Any}("B"=>[Dict{ASCIIString,Any}("S"=>2.1)],"A"=>Dict{ASCIIString,Any}("B"=>2,"C"=>2))
Dict{ASCIIString,Any}("B"=>[Dict{ASCIIString,Any}("S"=>1.0)],"A"=>Dict{ASCIIString,Any}("B"=>3,"C"=>2))
Dict{ASCIIString,Any}("B"=>[Dict{ASCIIString,Any}("S"=>2.1)],"A"=>Dict{ASCIIString,Any}("B"=>3,"C"=>2))页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/37433071
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